(-3) mũ x +5 = 1/18
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\(325-5\left[4^3-\left(27-5^2\right)\cdot1^{18}\right]\\ =325-5\left[64-\left(27-25\right)\cdot1\right]\\ =325-5\left(64-2\right)=325-5\cdot62=325-310=15\)
Bài 1 :
\(M=\dfrac{30-2^{20}}{2^{18}}=\dfrac{2.15-2^{20}}{2^{18}}=\dfrac{15}{2^{17}}-2^2=\dfrac{15}{2^{17}}-4< 0\left(\dfrac{15}{2^{17}}< 1\right)\)
\(N=\dfrac{3^5}{1^{2021}+2^3}=\dfrac{3^5}{9}=\dfrac{3^5}{3^2}=3^3=27\)
\(\Rightarrow M< N\)
Bài 3 :
a) \(t^2+5t-8\) khi \(t=2\)
\(=5^2+2.5-8\)
\(=25+10-8\)
\(=27\)
b) \(\left(a+b\right)^2-\left(b-a\right)^3+2021\left(1\right)\)
\(\left\{{}\begin{matrix}a=5\\b=a+1=6\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}a+b=11\\b-a=1\end{matrix}\right.\)
\(\left(1\right)=11^2-1^3+2021=121-1+2021=2141\)
c) \(x^3-3x^2y+3xy^2-y^3=\left(x-y\right)^3\left(1\right)\)
\(\left\{{}\begin{matrix}x=3\\y=2\end{matrix}\right.\) \(\Rightarrow x-y=1\)
\(\left(1\right)=1^3=1\)
a) 75 : ( x - 18 ) = 52 = 25
=> x - 18 = 3
=> x = 21
b) 740 : ( x - 10 ) = 102 - 2 x 13
740 : ( x - 10 ) = 100 - 26 = 74
=> x - 10 = 10
=> x = 20
c) ( 2x - 5 )3 = 8 = 23
=> 2x - 5 = 2
=> 2x = 7
=> x= 7/2
d) ( 15 - 6x ) x 35 = 36
=> ( 15 - 6x ) = 36 : 35 = 3
=> 6x = 12
=> x = 2
Đề bài:\(5^x\times5^{x+1}\times5^{x+2}\le100...0\left(18\text{ số }10\right):2^{18}\)
Hay có thể viết thế này:\(5^x.5^{x+1}.5^{x+2}\le10^{18}:2^{18}=5^{18}\)
\(\Leftrightarrow5^{x+\left(x+1\right)+\left(x+2\right)}\le5^{18}\)
\(\Leftrightarrow x+\left(x+1\right)+\left(x+2\right)\le18\)
\(\Leftrightarrow3x+3\le18\)
\(\Leftrightarrow3x\le15\Leftrightarrow x\le5\)
dai the giai bao gio xong chac mua quyt nam sau moi giai xong
\(\frac{9^{14}\cdot25^5\cdot8^7}{18^{12}\cdot625^3\cdot24^3}=\frac{3^{28}\cdot5^{10}\cdot2^{21}}{2^{12}\cdot3^{24}\cdot5^{12}\cdot2^9\cdot3^3}=\frac{3\cdot3^{27}\cdot5^{10}\cdot2^{21}}{2^{21}\cdot3^{27}\cdot5^2\cdot5^{10}}=\frac{3}{5^2}=\frac{3}{25}\)
\(\frac{9^{14}.25^5.8^7}{18^{12}.625^3.24^3}\)
\(=\)\(\frac{3^{28}.5^{10}.2^{21}}{2^{12}.3^{24}.5^{12}.2^9.3^3}\)
\(=\)\(\frac{3.3^{27}.5^{10}.2^{21}}{2^{21}.3^{27}.5^2.5^{10}}\)
\(=\)\(\frac{3}{5^2}\)
\(=\)\(\frac{3}{25}\)
b, x = -5/3 hoặc x = 4/3.
c, x = 0 hoặc x = 3, -3.
d, x = 0 hoặc x = 2, -2.
e, x = 1 hoặc x = \(\dfrac{-1}{2}\).
a: \(\Leftrightarrow x^2-40x+400-x^2-4x-3=-7\)
=>-44x+397=-7
=>-44x=-404
hay x=101
b: \(\Leftrightarrow\left[{}\begin{matrix}3x+5=0\\4-3x=0\end{matrix}\right.\Leftrightarrow x\in\left\{-\dfrac{5}{3};\dfrac{4}{3}\right\}\)
c: \(\Leftrightarrow x\left(x^2-9\right)=0\)
=>x(x-3)(x+3)=0
hay \(x\in\left\{0;3;-3\right\}\)
d: \(\Leftrightarrow x\left(x-2\right)\left(x+2\right)=0\)
hay \(x\in\left\{0;2;-2\right\}\)
e: =>(2x+1)(1-x)=0
=>x=-1/2 hoặc x=1