1+21=?
giúp
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\(\dfrac{1}{21}+\dfrac{2}{21}+\dfrac{3}{21}+\dfrac{4}{21}+\dfrac{5}{21}+\cdot\cdot\cdot+\dfrac{17}{21}+\dfrac{18}{21}+\dfrac{19}{21}+\dfrac{20}{21}\)
\(=\dfrac{1+2+3+4+5+\cdot\cdot\cdot+17+18+19+20}{21}\)
\(=\dfrac{210}{21}=10\)
1, \(\frac{5}{21}+0,5-\frac{19}{23}+\frac{16}{21}-\frac{4}{23}\)
\(=\frac{5+16}{21}-\frac{19+4}{23}+0,5\)
\(=1-1+0,5\)
\(=0,5\)
2,\(\frac{27}{23}+\frac{5}{21}-\frac{4}{23}+\frac{6}{21}+\frac{1}{2}\)
\(=\frac{27-4}{23}+\frac{5+6}{21}+\frac{1}{2}\)
\(=1+\frac{11}{21}+\frac{1}{2}\)
\(=\frac{42+22+21}{42}\)
\(=\frac{85}{42}\)
\( S = 1-1/5 +1/5-1/9+1/9-1/13+1/13-1/17+1/17-1/21+1/21-1/25+1/25-1/29. \)
\(S= 1- 1/29 \)
\(S=\frac{28}{29}\)
Nếu mình ko nhầm!
\(=\dfrac{3}{2}-\dfrac{2}{21}-\dfrac{7}{12}+\left[\dfrac{15}{21}-\dfrac{1}{3}+\dfrac{5}{4}-\dfrac{2}{7}-\dfrac{1}{3}\right]\)
=11/12-2/21+5/7-2/3+5/4-2/7
=11/12-2/3+5/4-2/21+3/7
=11/12-8/12+15/12-2/21+9/21
=18/12+7/21
=3/2+1/3
=9/6+2/6=11/6
\(B=\dfrac{3}{2}-\dfrac{2}{21}-\left\{\dfrac{7}{12}-\left[\dfrac{15}{21}-\left(\dfrac{1}{3}-\dfrac{5}{4}\right)-\left(\dfrac{2}{7}+\dfrac{1}{3}\right)\right]\right\}\)
\(B=\dfrac{3}{2}-\dfrac{2}{21}-\left\{\dfrac{7}{12}-\left[\dfrac{15}{21}-\left(-\dfrac{11}{12}\right)-\dfrac{13}{21}\right]\right\}\)
\(B=\dfrac{3}{2}-\dfrac{2}{21}-\left\{\dfrac{7}{12}-\dfrac{85}{84}\right\}\)
\(B=\dfrac{3}{2}-\dfrac{2}{21}-\left(-\dfrac{3}{7}\right)\)
\(B=\dfrac{11}{6}\)
a. (21 - 1) x (21 - 2) x (21 - 3) x ... x (21 - 21)
= 20 x 19 x 18 x ... x 0
= 0
b. 3 x 27 x 8 + 4 x 35 x 6 + 2 x 38 x 12
= (3 x 8) x 27 + (4 x 6) x 35 + (2 x 12) x 38
= 24 x 27 + 24 x 35 + 24 x 38
= 24 x (27 + 35 + 38)
= 24 x100
= 2400
c. A = (1001 + 1002 + 1003 +... + 2009) x (360 x 87 - 360 x 32 - 360 x 55)
= (1001 + 1002 + 1003 + ... + 2009) x [360 x (87 - 32 - 55)]
= (1001 + 1002 + 1003 + ... + 2009) x (360 x 0)
= (1001 + 1002 + 1003 + ... + 2009) x 0
= 0
1+21=22
1+21=22
nha em