Tìm x biết:
\(25+3\left(x-8\right)=106\)
\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
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\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
\(720:\left[41-\left(2x-5\right)\right]=8.5\)
\(720:\left[41-\left(2x-5\right)\right]=40\)
\(41-\left(2x-5\right)=720:40\)
\(41- \left(2x-5\right)=18\)
\(2x-5=41-18\)
\(2x-5=23\)
\(2x=23+5\)
\(2x=28\)
\(x=28:2\)
\(\Rightarrow x=14\)
a, \(3^2\left(x+14\right)-5^2=5.4\)
\(\Rightarrow9\left(x+14\right)-25=20\)
\(\Rightarrow9x+126=20+25\)
\(\Rightarrow9x+126=45\)
\(\Rightarrow9x=45-126\)
\(\Rightarrow9x=-81\Rightarrow x=-9\)
Vậy x = 9
a,\(3^2\left(x+14\right)-5^2=5.4\)
\(\Rightarrow9\left(x-14\right)-25=20\)
\(\Rightarrow9\left(x-14\right)=20+25=45\)
\(\Rightarrow x-14=45:9=5\)
\(\Rightarrow x=5+14\)
\(\Rightarrow x=19\)
Vậy x = 19
b,\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
\(720:\left[41-2x+5\right]=40\)
\(\Rightarrow41+5-2x=720:40\)
\(\Rightarrow46-2x=18\)
\(\Rightarrow2x=46-18=28\)
\(\Rightarrow x=28:2\)
\(\Rightarrow x=14\)
Vậy x = 14
~Study well~
\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
\(\Leftrightarrow720:\left[41-\left(2x-5\right)\right]=40\)
\(\Leftrightarrow41-\left(2x-5\right)=720:40\)
\(\Leftrightarrow41-\left(2x-5\right)=18\)
\(\Leftrightarrow2x-5=41-18\)
\(\Leftrightarrow2x-5=23\)
\(\Leftrightarrow2x=28\)
\(\Leftrightarrow x=14\)
Ta có :\(720:\left[41-\left(2X-5\right)\right]=2^3\cdot5\)
\(\Leftrightarrow41-\left(2X-5\right)=18\)
\(\Leftrightarrow2X-5=23\)
\(\Leftrightarrow2X=28\)
\(\Leftrightarrow X=14\)(TMĐK)
Vậy X= 14 là giá trụ cần tìm.
720:(41-(2x-5)) =2\(^3\)x5
720:(41-(2x-5)) =40
41-(2x-5) =720:40=18
2x-5 =41-18=23
2x =23+5=28
=> x =28:2=14
x=14
k nha.đúng 100% đó
720 : [41-(2x-5)] = 2^3 . 5
720 : [41-(2x-5) ] =40
=> 41-(2x-5) =18
=> 2x-5 =23
=> 2x =28
=> x=14
720: ( 41-(2x-5) ) = 23 . 5
<=> 720 : ( 41 - ( 2x-5 ) ) = 8.5
<=> 720 : ( 41 - (2x -5 ) ) = 40
<=> ( 41 - ( 2x - 5) ) = 720 : 40 = 18
<=> 2x - 5 = 41 -18 = 23
<=> 2x = 23+5 =28
=> x = 28 : 2 =14
\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
\(720:\left[41-\left(2x-5\right)\right]=8.5\)
\(720:\left[41-\left(2x-5\right)\right]=40\)
\(\left[41-\left(2x-5\right)\right]=720:40\)
\(\left[41-\left(2x-5\right)\right]=18\)
\(\left(2x-5\right)=41-18\)
\(\left(2x-5\right)=23\)
\(2x=23+5\)
\(2x=28\)
\(x=28:2\)
\(x=14\)
720 : [41 - ( 2x - 5 ) ] = 2^3 . 5
=> 720 : [ 41 - ( 2x -5 ) ] = 8 . 5
=> 720 : [ 41 - ( 2x - 5 ) ] = 40
=> [ 41 - ( 2x - 5 ) ] = 720 : 40
=> [ 41 - ( 2x -5 ) ] = 18
=> ( 2x - 5 ) = 41 - 18
=> ( 2x - 5 ) =23
=> 2x = 23 + 5
=> 2x = 28
=> x = 28 : 2
=> x = 14
Chuc ban hc tot
a) \(\left(x-1\right)^3=8=2^3\)
\(x-1=2\)
\(x=2+1=3\)
b) \(7^{2x-6}=49=7^2\)
\(2x-6=2\)
\(2x=6+2=8\)
\(x=8:2=4\)
c) \(\left(2x-14\right)^7=128=2^7\)
\(2x-14=2\)
\(2x=14+2=16\)
\(x=16:2=8\)
d) \(x^4\cdot x^5=5^3\cdot5^6=5^4\cdot5^5\)
\(x=5\)
e) \(3\cdot\left(x+2\right):7\cdot4=120\)
\(x+2=120:3\cdot7:4\)
\(x+2=70\)
\(x=70-2=68\)
Lời giải:
a. $(x-1)^3=8=2^3$
$\Rightarrow x-1=2$
$\Rightarrow x=3$
b. $7^{2x-6}=49=7^2$
$\Rightarrow 2x-6=2$
$\Rightarrow 2x=8$
$\Rightarrow x=4$
c. $(2x-14)^7=128=2^7$
$\Rightarrow 2x-14=2$
$\Rightarrow 2x=16$
$\Rightarrow x=18$
d.
$x^4.x^5=5^3.5^6$
$x^9=5^9$
$\Rightarrow x=5$
e.
$3(x+2):7=120:4=30$
$3(x+2)=30.7=210$
$x+2=210:3=70$
$x=70-2=68$
Cách làm
Bài 1: 25 + 3(x - 8) = 106
3(x - 8) = 106 - 25
3(x - 8) = 81
(x - 8) = 81 : 3
(x - 8) = 27
x = 27 + 8
x = 25
Bài 2: 720 : [41 - (2x - 5)] = 23 . 5
720 : [41 - (2x - 5)] = 8 . 5
720 : [41 - (2x - 5)] = 40
[41 - (2x - 5)] = 720 : 40
[41 - (2x - 5)] = 18
(2x - 5) = 41 - 18
(2x - 5) = 23
2x = 23 + 5
2x = 28
x = 28 : 2
x = 14