GIẢI CÁC PHƯƠNG TRÌNH SAU:
Giúp mình với, mình đang cần gấp
a)\(\frac{2x}{x+2}+\frac{x+2}{2x}=2\)
b) \(\frac{1}{x^2-2x+2}+\frac{2}{x^2-2x+3}=\frac{6}{x^2-2x+4}\)
c) \(\frac{1}{x^2-3x+3}+\frac{2}{x^2-3x+4}=\frac{6}{x^2-3x+5}\)
d) \(\frac{x^2-x}{x^2-x+1}-\frac{x^2-x+2}{x^2-x-2}=1\)
a) \(\frac{2x}{x+2}+\frac{x+2}{2x}=2\)
\(\Leftrightarrow4x^2+\left(x+2\right)^2=4x\left(x+2\right)\)
\(\Leftrightarrow5x^2+4x+4=4x^2+8x\)
\(\Leftrightarrow5x^2+4x+4-4x^2-8x=0\)
\(\Leftrightarrow x^2-4x+4=0\)
\(\Leftrightarrow x^2-2.x.2+2^2=0\)
\(\Leftrightarrow\left(x-2\right)^2=0\)
\(\Leftrightarrow x-2=0\)
\(\Rightarrow x=2\)