\(\frac{16x17-5}{16x16+11}\)
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\(\frac{16.17-5}{16.16+11}\)
\(=\frac{16.16+16-5}{16.16+11}\)
\(=\frac{16.16+11}{16.16+11}\)
\(=1\)
\(\frac{16\cdot17-5}{16\cdot16+11}\)
\(=\frac{16\cdot17-5}{16\cdot17-16-11}\)
\(=\frac{16\cdot17-5}{16\cdot17-5}\)
\(=1\)
mk ko copy của Trần Thùy Dung nhé
\(\frac{16\times17-5}{16\times16+11}=\frac{16\times\left(16+1\right)-5}{16\times16+11}=\frac{16\times16+16-5}{16\times16+11}=\frac{16\times16+11}{16\times16+11}=1\)
Trả lời
\(\frac{16\times17-5}{16\times16+11}=\frac{16\times\left(16+1\right)-5}{16\times16+11}\)
\(=\frac{16\times16+16-5}{16\times16+11}\)
\(=\frac{16\times16+11}{16\times16+11}\)
\(=1\)
\(\frac{16.17-5}{16.16+11}\)
\(=\frac{16.\left(16+1\right)-5}{16^2+11}\)
\(=\frac{16^2+16-5}{16^2+11}\)
\(=\frac{16^2+11}{16^2+11}\)
\(=1\)
(Nhớ k cho mình với nhé!)
\(\frac{16x17-5}{16x16+11}\)
=\(\frac{16x\left(16+1\right)-5}{16x16+11}\)
=\(\frac{16x16+16x1-5}{16x16+11}\)
= \(\frac{16x16+11}{16x16+11}\)
= 1 ( vì TS = MS )
\(\frac{16.17-5}{16.16+11}\)
\(=\frac{16.\left(16+1\right)-5}{16^2+11}\)
\(=\frac{16^2+16-5}{16^2+11}\)
\(=\frac{16^2+11}{16^2+11}=1\)
(Nhớ k cho mình với nhé!)
\(\frac{16x17-5}{16x16+11}=\frac{16x16+16-5}{16x16+11}=1\)
\(\frac{4}{3x7}+\frac{5}{7x12}+\frac{1}{12x13}+....+\frac{3}{20x23}\)
=\(\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+...+\frac{1}{20}-\frac{1}{23}\)
=\(\frac{1}{3}-\frac{1}{23}=\frac{20}{69}\)
a) \(\frac{16\cdot17-5}{16\cdot16+11}\)
= \(\frac{16\cdot16+16-5}{16\cdot16+11}\)
= \(\frac{16\cdot16+11}{16\cdot16+11}=1\)
a: A=16*16+16-5=16*16+11
=>A=B
b: A=2000*2000=2000^2
B=1998*2002=(2000-2)(2000+2)=2000^2-4
=>A<B
d: B=(2020-1)(2020+1)=2020^2-1
=>B<A
\(\frac{16.17-5}{16.16+11}\)
\(=\frac{17-5}{16+11}\)
\(=\frac{12}{27}\)
Bài làm
\(\frac{16x17-5}{16x16+11}\)
\(=\frac{272-5}{256+11}\)
\(=\frac{267}{267}\)
\(=1\)
# Học tốt #