M
2
K
Khách
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NB
2
17 tháng 7 2016
\(\frac{16.17-5}{16.16+11}\)
\(=\frac{16.16+16-5}{16.16+11}\)
\(=\frac{16.16+11}{16.16+11}\)
\(=1\)
17 tháng 7 2016
\(\frac{16\cdot17-5}{16\cdot16+11}\)
\(=\frac{16\cdot17-5}{16\cdot17-16-11}\)
\(=\frac{16\cdot17-5}{16\cdot17-5}\)
\(=1\)
mk ko copy của Trần Thùy Dung nhé
ON
2
DK
30 tháng 6 2016
\(\frac{16.17-5}{16.16+11}\)
\(=\frac{16.\left(16+1\right)-5}{16^2+11}\)
\(=\frac{16^2+16-5}{16^2+11}\)
\(=\frac{16^2+11}{16^2+11}\)
\(=1\)
(Nhớ k cho mình với nhé!)
LT
30 tháng 6 2016
\(\frac{16x17-5}{16x16+11}\)
=\(\frac{16x\left(16+1\right)-5}{16x16+11}\)
=\(\frac{16x16+16x1-5}{16x16+11}\)
= \(\frac{16x16+11}{16x16+11}\)
= 1 ( vì TS = MS )
ZH
2
DK
30 tháng 6 2016
\(\frac{16.17-5}{16.16+11}\)
\(=\frac{16.\left(16+1\right)-5}{16^2+11}\)
\(=\frac{16^2+16-5}{16^2+11}\)
\(=\frac{16^2+11}{16^2+11}=1\)
(Nhớ k cho mình với nhé!)
5 tháng 7 2017
\(B=\frac{5}{7}.\frac{2}{11}+\frac{5}{7}.\frac{12}{11}-\frac{5}{7}.\frac{7}{11}\)
\(B=\frac{5}{7}.\left(\frac{2}{11}+\frac{12}{11}\right)-\frac{5}{7}.\frac{7}{11}\)
\(B=\frac{5}{7}.\frac{14}{11}-\frac{5}{7}.\frac{7}{11}\)
\(B=\frac{5}{7}.\left(\frac{14}{11}-\frac{7}{11}\right)\)
\(B=\frac{5}{7}.\frac{7}{11}\)
\(B=\frac{35}{77}=\frac{5}{11}\)
8 tháng 7 2023
a: A=16*16+16-5=16*16+11
=>A=B
b: A=2000*2000=2000^2
B=1998*2002=(2000-2)(2000+2)=2000^2-4
=>A<B
d: B=(2020-1)(2020+1)=2020^2-1
=>B<A
4 tháng 7 2016
\(\frac{5}{8}+\frac{5}{27}-\frac{5}{49}\)
\(=5\left(\frac{1}{8}+\frac{1}{27}-\frac{1}{49}\right)\)
\(=\frac{1499}{10584}.5\)
\(=\frac{7495}{10584}\)
\(\frac{11}{8}+\frac{11}{27}-\frac{11}{49}\)
\(=11.\left(\frac{1}{8}+\frac{1}{27}-\frac{1}{49}\right)\)
\(=\frac{1499}{10584}.11\)
\(=1.557917611\)
27 tháng 7 2019
a)(5\(\frac{2}{7}\). \(\frac{8}{11}\)+ \(\frac{2}{11}\).5\(\frac{2}{7}\)): 3\(\frac{4}{11}\)- 1\(\frac{3}{7}\)
= 5\(\frac{2}{7}\). (\(\frac{8}{11}\)+\(\frac{2}{11}\)):\(\frac{37}{11}\)-\(\frac{10}{7}\)
= \(\frac{37}{7}\).\(\frac{8}{11}\).\(\frac{11}{37}\)-\(\frac{10}{7}\)
= \(\frac{37.8.11}{7.11.37}\)- \(\frac{10}{7}\)
= \(\frac{8}{7}\)-\(\frac{10}{7}\)
= \(\frac{-2}{7}\)
NT
26 tháng 3 2018
\(\frac{5}{11}.\frac{3}{7}+\frac{5}{7}.\frac{4}{11}-\frac{3}{11}\)
\(=\frac{3}{11}.\frac{5}{3}.\frac{3}{7}+\frac{5}{7}.\frac{4}{3}.\frac{3}{11}-\frac{3}{11}\)
\(=\frac{3}{11}.\left(\frac{5}{7}+\frac{20}{21}-1\right)\)
\(=\frac{3}{11}.\left(\frac{15+20}{21}-1\right)\)
\(=\frac{3}{11}.\left(\frac{35}{21}-1\right)\)
\(=\frac{3}{11}.\frac{14}{21}\)
\(=\frac{14}{77}\)
26 tháng 3 2018
5/11 x 3/7 + 5/7 x 4/11 - 3/11
= 5/11 x 3/7 + 5/11 x 4/7 - 3/11
= 5/11 x ( 3/7 + 4/7 ) - 3/11
= 5/11 x 1 - 3/11
= 5/11 - 3/11
= 2/11
Tk nha !!
NL
22 tháng 4 2017
Bài 1:
\(g.\frac{5}{11}+\frac{6}{11}=\frac{5+6}{11}=\frac{11}{11}=1\)\(\)
\(e.\frac{-17}{25}.\frac{20}{33}+\frac{-17}{25}.\frac{13}{33}+\frac{-3}{25}=\frac{-17}{25}.\left(\frac{20}{33}+\frac{13}{33}\right)+\frac{-3}{25}\)
\(=\frac{-17}{25}.1+\frac{-3}{25}=\frac{-17}{25}+\frac{-3}{25}=\frac{-17-3}{25}=\frac{-20}{25}=\frac{-4}{5}\)
\(d.\frac{5}{7}.\frac{19}{23}+\frac{5}{7}.\frac{5}{23}-\frac{5}{7}.\frac{1}{23}=\frac{5}{7}\left(\frac{19}{23}+\frac{5}{23}-\frac{1}{23}\right)\)
\(=\frac{5}{7}\left(\frac{19+5-1}{23}\right)=\frac{5}{7}.1=\frac{5}{7}\)
\(c.\left(-11\right).\frac{9}{22}=\frac{\left(-11\right).9}{22}=\frac{-99}{22}=\frac{-9}{2}\)
\(b.\frac{5}{6}-\frac{1}{8}=\frac{5.4}{6.4}-\frac{1.3}{8.3}=\frac{20}{24}-\frac{3}{24}=\frac{17}{24}\)
\(a.\frac{2}{3}+\frac{1}{5}-\frac{1}{6}=\frac{2.10}{3.10}+\frac{1.6}{5.6}-\frac{1.5}{6.5}=\frac{20}{30}+\frac{6}{30}-\frac{5}{30}\)
\(=\frac{20+6-5}{30}=\frac{21}{30}=\frac{7}{10}\)
Bài 2:
\(a.\frac{3}{4}+x=\frac{11}{12}\)
\(\Leftrightarrow x=\frac{11}{12}-\frac{3}{4}\)
\(\Leftrightarrow x=\frac{11}{12}-\frac{9}{12}\)
\(\Leftrightarrow x=\frac{2}{12}=\frac{1}{6}\)
\(b.x-\frac{11}{12}=0,5\)
\(\Leftrightarrow x=\frac{1}{2}-\frac{11}{12}\)
\(\Leftrightarrow x=\frac{6}{12}+\frac{11}{12}\)
\(\Leftrightarrow x=\frac{17}{12}\)
\(\frac{16.17-5}{16.16+11}\)
\(=\frac{17-5}{16+11}\)
\(=\frac{12}{27}\)
Bài làm
\(\frac{16x17-5}{16x16+11}\)
\(=\frac{272-5}{256+11}\)
\(=\frac{267}{267}\)
\(=1\)
# Học tốt #