(X - 1 phần 3 ) nhân ( X + 2 phần 5 ) > 0
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\(\left(x-\frac{1}{3}\right)\left(x+\frac{2}{5}\right)>0\)
\(\orbr{\begin{cases}x=\frac{1}{3}\\x=-\frac{2}{5}\end{cases}}\)
\(-\frac{2}{5}< x< \frac{1}{3}\)
1/3x + 2/3(x-2) = 45
1/3x + 2/3x - 4/3 = 45
x= 45+4/3
x= 139/3
1/3 x + 2/3 (x-2) = 45
1/3x + 2/3x - 4/3 = 45
x = 45 + 4/3
x = 139/3
>_< học tốt
tích giùm mk nha cảm ơn nhìu
\(\frac{2}{3}-\frac{1}{3}.\frac{x-3}{2}-\frac{1}{2}.2.x+1=5\)
\(\Leftrightarrow\frac{2}{3}-\frac{x-3}{3.2}-\frac{2.x}{2}+1=5\)
\(\Leftrightarrow\frac{2}{3}-\frac{x-3}{6}-x+1=5\)
\(\Leftrightarrow\frac{2}{3}-\frac{x-3}{6}-x=4\)
\(\Leftrightarrow\frac{4}{6}-\frac{x-3}{6}-\frac{6x}{6}=4\)
\(\Leftrightarrow\frac{4-\left(x-3\right)-6x}{6}=4\)
\(\Leftrightarrow\frac{4-x+3+6x}{6}=4\)
\(\Leftrightarrow\frac{4+3-x+6x}{6}=\frac{4}{1}\)
\(\Leftrightarrow\frac{7+5x}{6}=\frac{4}{1}\)
\(\Leftrightarrow7+5x=4.6\)
\(\Leftrightarrow7+5x=24\)
\(\Leftrightarrow5x=24-7\)
\(\Leftrightarrow5x=17\)
\(\Leftrightarrow x=\frac{17}{5}\)
Vậy \(x=\frac{17}{5}\)
Chúc bạn học tốt
(\(x\) + \(\dfrac{1}{2}\))2 = \(\dfrac{1}{16}\)
\(\left[{}\begin{matrix}x+\dfrac{1}{2}=-\dfrac{1}{4}\\x+\dfrac{1}{2}=\dfrac{1}{4}\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-\dfrac{1}{4}-\dfrac{1}{2}\\x=\dfrac{1}{4}-\dfrac{1}{2}\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-\dfrac{3}{4}\\x=-\dfrac{1}{4}\end{matrix}\right.\)
Vậy \(x\) \(\in\) {- \(\dfrac{3}{4};-\dfrac{1}{4}\)}
\(x\) : (- \(\dfrac{1}{3}\))3 = - \(\dfrac{1}{3}\)
\(x\) = (-\(\dfrac{1}{3}\)).(-\(\dfrac{1}{3}\))3
\(x\) = \(\dfrac{1}{81}\)
Vậy \(x=\dfrac{1}{81}\)
\(\left(\frac{3}{4}x-\frac{9}{16}\right)-\left(\frac{1}{3}+\frac{-3}{5}x\right)=0.\)
\(\frac{3}{4}x-\frac{9}{16}-\frac{1}{3}-\frac{-3}{5}x=0\)
\(\frac{27}{20}x-\frac{43}{48}=0\)
\(\frac{27}{20}x=\frac{43}{48}\)
\(x=\frac{215}{324}\)
mong ủng hộ mk
(3 phần 4 nhân X - 9 phần 16 ) - (1 phần 3 + -3 phần 5 chia X ) = 0
=>\(\frac{3}{4}.x-\frac{9}{16}=\frac{1}{3}+\frac{-3}{5}:x\)
=\(\frac{3}{4}.x-\frac{9}{16}=\frac{-4}{15}:x\)
=>\(\frac{3}{4}.x-\frac{-4}{15}:x=\frac{9}{16}\)
Đến đây thì mk chịu =)
Dù sao thi cg ti.ck giúp mk tí
\(\left(x+1\right)\left(x-2\right)< 0\)
Th1 : \(\hept{\begin{cases}x+1< 0\\x-2>0\end{cases}=>\hept{\begin{cases}x< -1\\x>2\end{cases}}}\)
TH2 : \(\hept{\begin{cases}x+1>0\\x-2< 0\end{cases}=>\hept{\begin{cases}x>-1\\x< 2\end{cases}}}\)
\(\left(x+2\right)\left(x+\frac{2}{3}\right)>0\)
Th1 : \(\hept{\begin{cases}x+2>0\\x+\frac{2}{3}>0\end{cases}=>\hept{\begin{cases}x>-2\\x>\frac{-2}{3}\end{cases}}}\)
TH2 : \(\hept{\begin{cases}x+2< 0\\x+\frac{2}{3}< 0\end{cases}=>\hept{\begin{cases}x< -2\\x< \frac{-2}{3}\end{cases}}}\)
T nha các bạn
\(\frac{x-1}{3}\cdot\frac{x+2}{5}>0\)
\(\Leftrightarrow\left(x-1\right)\left(x+2\right)>0\)
\(TH1:\orbr{\begin{cases}x-1>0\\x+2>0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x>1\\x>-2\end{cases}}\Leftrightarrow x>1\left(1\right)\)
\(TH2:\orbr{\begin{cases}x-1< 0\\x+2< 0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x< 1\\x< -2\end{cases}}\Leftrightarrow x< -2\left(2\right)\)
Tu ( 1 ) va ( 2 ) suy ra \(-2< x< 1\)
Cho mik sua 1 chut nha.
\(TH1:\Leftrightarrow x>-2\)
\(TH2:\Leftrightarrow x< 1\)