Tính nhanh:
\(\frac{223\times2007+1034}{224\times2007-973}\)
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Ta có: \(\frac{2004\cdot2007+6}{2005\cdot2005+2009}=\frac{\left(2005-1\right)\cdot2007+6}{2005\cdot2005+2009}=\frac{2005\cdot2007-1\cdot2007+6}{2005\cdot2005+2009}=\frac{2005\cdot2007-2007+6}{2005\cdot2005+2009}\)
\(=\frac{\text{2005 x (2005 + 2) - 2007 + 6}}{\text{2005 x 2005 + 2009}}=\frac{\text{2005 x 2005 + 2005 x 2 - 2007 + 6}}{\text{2005 x 2005 + 2009}}=\frac{\text{2005 x 2005 + 4010 - 2007 + 6}}{\text{2005 x 2005 + 2009}}=\text{ }\frac{\text{2005 x 2005 + 2009}}{\text{2005 x 2005 + 2009}}=1\)
2006 * ( 2005 + 2 ) - 2593 / 2005 * 2006 + 1419
2006 * 2005 + 2006 * 2 - 2593 / 2005 * 2006 + 1419
2006 * 2005 + 4012 - 2593 / 2005 * 2006 + 1419
2006 * 2005 + 1419 / 2005 * 2006 + 1419 = 1
k cho tui nha
\(\frac{2006\times2007-2593}{2005\times2006+1419}=\frac{2005\times2006+2\times2006-2593}{2005\times2006+1419}\)
\(=\frac{2005\times2006+4012-2593}{2005\times2006+1419}=\frac{2005\times2006+1419}{2005\times2016+1419}=1\)
\(=\frac{2005\times\left(2006+1\right)-1}{2004+2005\times2006}=\frac{2005\times2006+2005\times1-1}{2004+2005\times2006}=\frac{2005\times2006+2004}{2004+2005\times2006}=1\)
B = \(\dfrac{2021\times13+2007+2020\times2007}{2020+2020\times520+1500\times2020}\)
B = \(\dfrac{2021\times13+2007\times\left(1+2020\right)}{2020\times\left(1+520+1500\right)}\)
B = \(\dfrac{2021\times13+2007\times2021}{2020\times2021}\)
B = \(\dfrac{2021\times\left(13+2007\right)}{2021\times2020}\)
B = \(\dfrac{2021\times2020}{2021\times2020}\)
B = 1
\(\dfrac{223.2007+1034}{224.2007-973}\)
=\(\dfrac{223.2007+1034}{223.2007+2007-937}\)
=\(\dfrac{223.2007+1034}{223.2007+1034}\)
= 1
\(\frac{223.2007+1034}{224.2007-973}\)
= \(\frac{223.2007+1034}{223.2007+2007-973}\)
= \(\frac{1034}{1034}\)= 1
\(\frac{223\times2007+1034}{224\times2007-973}\)
\(=\frac{223\times2007+1034}{\left(223+1\right)\times2007-973}\)
\(=\frac{223\times2007+1034}{223\times2007+2007-973}\)
\(=\frac{223\times2007+1034}{223\times3007+1034}\)
\(=1\)