TInh gia tri bieu thuc
\(B=\frac{-2}{3}+\frac{3}{4}-\frac{-1}{6}+\frac{-2}{5}\)
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\(A=\frac{\left(1+2+...+100\right)\left(\frac{1}{2}^2-...-\frac{1}{5}\right)\left(2,4.42-21.4,8\right)}{1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{100}}\)
=> \(A=\frac{\left(1+2+...+100\right)\left(\frac{1}{2}-...-\frac{1}{5}\right).0}{1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{100}}\)= 0
\(6\frac{1}{2}-2\frac{1}{3}\div\frac{7}{15}\)
=\(\frac{13}{2}-\frac{7}{3}\div\frac{7}{15}\)
=\(\frac{13}{2}-5\)
=\(\frac{3}{2}\)
D = \(\frac{9}{4}+\frac{1}{16}-\frac{1}{8}\)
D = \(\frac{35}{16}\)
\(D=\left(\frac{3}{2}\right)^2+\left(\frac{1}{4}\right)^2-\left(\frac{1}{2}\right)^3\)
\(D=\frac{9}{4}+\frac{1}{16}-\frac{1}{8}\)
\(D=\frac{37}{16}-\frac{1}{8}\)
\(D=\frac{35}{16}.\)
Chúc bạn học tốt!
\(A=3+\frac{1}{1+\frac{1}{1+\frac{1}{\frac{4}{3}}}}=3+\frac{1}{1+\frac{1}{1+\frac{3}{4}}}\)
\(=3+\frac{1}{1+\frac{1}{\frac{7}{4}}}=3+\frac{1}{1+\frac{4}{7}}=3+\frac{1}{\frac{11}{4}}=3+\frac{4}{11}=\frac{37}{11}\)
\(B=-5+\frac{1}{1-\frac{1}{2+\frac{1}{\frac{3}{4}}}}=-5+\frac{1}{1-\frac{1}{2+\frac{4}{3}}}\)
\(=-5+\frac{1}{1-\frac{1}{\frac{10}{3}}}=-5+\frac{1}{1-\frac{3}{10}}=-5+\frac{1}{\frac{7}{10}}=-5+\frac{10}{7}=\frac{-25}{7}\)
B = \(\frac{-2}{3}+\frac{3}{4}-\frac{-1}{6}+\frac{-2}{5}=\frac{-240+270+60-144}{360}=\frac{-54}{360}=-0,15\)