\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
M.n giup em vs mai em nop r em cam on
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
làm tiếp cái trước(ấn nhầm)
\(x=\frac{5}{42}-\frac{15}{28}\)
\(x=\frac{5.4}{6.4.7}-\frac{15.6}{4.7.6}\)
\(x=\frac{20}{168}-\frac{90}{168}\)
\(x=\frac{-70}{168}\)
\(x=\frac{-5}{12}\)
2.
1.
\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)
\(\frac{11}{13}-\frac{5}{42}+x=-\frac{15}{28}+\frac{11}{13}\)
\(\frac{11}{13}-\frac{11}{13}-\frac{5}{42}+\frac{15}{28}=-x\)
\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\left|x+\frac{4}{15}\right|-3,75=-2,15\)
\(\left|x+\frac{4}{15}\right|=1,6\)
\(\Rightarrow\orbr{\begin{cases}x+\frac{4}{15}=1,6\\x+\frac{4}{15}=-1,6\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{4}{3}\\x=\frac{-28}{15}\end{cases}}}\)
\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\left|x+\frac{4}{15}\right|-3,75=-2,15\)
\(\left|x+\frac{4}{15}\right|=-2,15+3,75\)
\(\left|x+\frac{4}{15}\right|=1,6\)
Ta có 2 trường hợp
trường hợp 1
\(x+\frac{4}{15}=1,6\)
\(x=1,6-\frac{4}{15}\)
\(x=\frac{4}{3}\)
Trường hợp 2
\(x+\frac{4}{15}=-1,6\)
\(x=-1,6-\frac{4}{15}\)
\(x=\frac{-28}{15}\)
Vậy \(x=\left\{-\frac{28}{15};\frac{4}{3}\right\}\)
\(\left|x+\dfrac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\Leftrightarrow\left|x+\dfrac{4}{15}\right|=-2,15+3,75\)
\(\Leftrightarrow\left|x+\dfrac{4}{15}\right|=\dfrac{8}{5}\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{4}{15}=\dfrac{8}{5}\\x+\dfrac{4}{15}=-\dfrac{8}{5}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x=-\dfrac{28}{15}\end{matrix}\right.\)
\(\Rightarrow\left|x+\dfrac{4}{15}\right|-3,75=-2,15\\ \Rightarrow\left|x+\dfrac{4}{15}\right|=1,6=\dfrac{8}{5}\\ \Rightarrow\left[{}\begin{matrix}x+\dfrac{4}{15}=\dfrac{8}{5}\\x+\dfrac{4}{15}=-\dfrac{8}{5}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x=-\dfrac{28}{15}\end{matrix}\right.\)
\(B=\left|x+3\right|+\left|2-x\right|\ge\left|x+3+2-x\right|=\left|5\right|=5\)
Dấu "=" xảy ra khi \(x=0\)
Vậy \(B_{min}=5\Leftrightarrow x=0\)
│x+14/15│-3,75=-2,15
│x+14/15│=-2,15+3,75=1,6
Suy ra :
TH1 :x+14/15=1,6
x=2/3
TH2 :x+14/15=-1,6
x=-38/15
\(\left|x+\dfrac{14}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\Leftrightarrow\left|x+\dfrac{14}{15}\right|-3,75=-2,15\)
\(\Leftrightarrow\left|x+\dfrac{14}{15}\right|=-2,15+3,75\)
\(\Leftrightarrow\left|x+\dfrac{14}{15}\right|=1,6\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{14}{15}=-1,6\\x+\dfrac{14}{15}=1,6\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-38}{15}\\x=\dfrac{2}{3}\end{matrix}\right.\)
Vậy....
Chúc các bạn học tốt !!!
\(\left|x+\frac{4}{15}\right|-\left|-3.75\right|=-\left|-2,15\right|\)
\(\Rightarrow\left|x+\frac{4}{15}\right|-\frac{15}{4}=-\frac{43}{20}\)
\(\Rightarrow\left|x+\frac{4}{15}\right|=-\frac{43}{20}+\frac{15}{4}\)
\(\Rightarrow\left|x+\frac{4}{15}\right|=\frac{8}{5}\)
\(\Rightarrow\orbr{\begin{cases}x+\frac{4}{15}=\frac{8}{5}\\x+\frac{4}{15}=-\frac{8}{5}\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{4}{3}\\x=-\frac{28}{15}\end{cases}}\)
\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\left|x+\frac{4}{15}\right|-3,75=-2,15\)
\(\left|x+\frac{4}{15}\right|=1,6\)
=> \(x+\frac{4}{15}=1,6\) hoặc \(x+\frac{4}{15}=-1,6\)
=> \(x=\frac{4}{3}\) hoặc \(x=\frac{-28}{15}\)
Vậy..