Tính nhanh:
9*3*1001+0,9*30000+30*899,9*9
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Bài này hơi rối ha ^ ^
9.3.1001+9,9.30000+ 30.899,9.9
\(=9.3.1001+9.1,1.30.1000+30.899,9.9\)
\(=9.3.1001+9.30.\left(1,1.1000\right)+9.30.899,9\)
\(=9.3.1001+9.3.10.1100+9.3.10.899,9\)
\(=9.3.1001+9.3.11000+9.3.8999\)
\(=9.3\left(1001+11000+8999\right)\)
\(=27.21000=567000\)
\(\dfrac{24\cdot47-23}{24+47\cdot23}\cdot\dfrac{3+\dfrac{3}{7}-\dfrac{3}{11}+\dfrac{3}{1001}-\dfrac{3}{13}}{\dfrac{9}{1001}-\dfrac{9}{13}+\dfrac{9}{7}-\dfrac{9}{11}+9}\\ =\dfrac{24\cdot\left(24+23\right)-23}{24+\left(24+23\right)\cdot23}\cdot\dfrac{3\left(1+\dfrac{1}{7}-\dfrac{1}{11}+\dfrac{1}{1001}-\dfrac{1}{13}\right)}{9\left(1+\dfrac{1}{7}-\dfrac{1}{11}+\dfrac{1}{1001}-\dfrac{1}{13}\right)}\\ =\dfrac{24\cdot24+24\cdot23-23\cdot1}{24+24\cdot23+23\cdot23}\cdot\dfrac{1}{3}\\ =\dfrac{23\left(24-1\right)+24\cdot24}{24\left(1+23\right)+23\cdot23}\cdot\dfrac{1}{3}=\dfrac{23\cdot23+24\cdot24}{24\cdot24+23\cdot23}\cdot\dfrac{1}{3}\\ =1\cdot\dfrac{1}{3}=\dfrac{1}{3}\)
( 67,875 * 0,5 + 3,1416 * 0,5 ) * ( 9 * 0,9 + 0,9 - 0,9 * 10)
= ( 67,875 * 0,5 + 3,1416 * 0,5 ) * 0,9 * ( 9 + 1 - 10 )
= ( 67,875 * 0,5 + 3,1416 * 0,5 ) * 0,9 * 0
=0
\(\frac{24\cdot47-23}{24+47\cdot23}.\frac{3+\frac{3}{7}-\frac{3}{11}+\frac{3}{1001}-\frac{3}{13}}{\frac{9}{1001}-\frac{9}{13}+\frac{9}{7}-\frac{9}{11}+9}\)
\(=\frac{24\cdot\left(24+23\right)-23}{24+\left(24+23\right)\cdot23}\cdot\frac{3\left(1+\frac{1}{7}-\frac{1}{11}+\frac{1}{1001}-\frac{1}{13}\right)}{9\left(\frac{1}{1001}-\frac{1}{13}+\frac{1}{7}-\frac{1}{11}+1\right)}\)
\(=\frac{24^2+24\cdot23-23}{24+24\cdot23+23^2}\cdot\frac{3}{9}\) \(=\frac{24^2+23\cdot\left(24-1\right)}{\left(23+1\right)\cdot24\cdot23^2}\cdot\frac{1}{3}=1\cdot\frac{1}{3}=\frac{1}{3}\)
= [(67,895 + 3,1416) *0,5)] * [(9+1-10) *0,9]
= [71,0366 * 0,5] * [0 * 0,9]
= 35,5183 * 0
= 0
( 67,895 * 0,5 + 3,1416 * 0,5 ) * ( 9 * 0,9 + 0,9 - 0,9 * 10 ) =
=0,5 *(67,895+ 3,1416)*0,9*(9+1-10)
=0,5 *(67,895+ 3,1416)*0,9*0
=0