N= \(\frac{-5}{9}\). \(\frac{3}{7}\)+ \(\frac{4}{7}\). \(\frac{-5}{9}\)+ 2019\(\frac{5}{9}\)
K
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9 tháng 2 2017
1. \(\frac{5}{9}.\frac{7}{13}+\frac{5}{9}.\frac{9}{13}-\frac{5}{9}.\frac{3}{13}\)
= \(\frac{5}{9}\) .(\(\frac{7}{13}+\frac{9}{13}-\frac{3}{13}\) )
= \(\frac{5}{9}\) . 1 = \(\frac{5}{9}\)
B
2 tháng 4 2019
\(N=\frac{1}{6}.\frac{5}{9}+\frac{5}{9}.\frac{2}{7}+\frac{1}{9}.\frac{5}{7}-\frac{5}{9}.\frac{3}{7}\)
\(N=\frac{1}{6}.\left(\frac{5}{9}+\frac{1}{9}\right).\left(\frac{2}{7}+\frac{5}{7}-\frac{3}{7}\right)\)
\(N=\frac{1}{6}.\frac{6}{9}.\frac{4}{7}\)
\(N=\frac{1}{9}.\frac{4}{7}\)
\(N=\frac{4}{63}\)
12 tháng 6 2020
\(N=\frac{1}{6}.\frac{5}{9}+\frac{5}{9}.\frac{2}{7}+\frac{1}{9}.\frac{5}{7}-\frac{5}{9}.\frac{3}{7}\)
\(N=\frac{1}{6}.\frac{5}{9}+\frac{5}{9}.\frac{2}{7}+\frac{5}{9}.\frac{1}{7}-\frac{5}{9}.\frac{3}{7}\)
\(N=\frac{5}{9}.\left(\frac{1}{6}+\frac{2}{7}+\frac{1}{7}-\frac{3}{7}\right)\)
\(N=\frac{5}{9}.\frac{1}{6}\)
\(N=\frac{5}{54}\)
VM
9 tháng 12 2019
i) \(\frac{25^9}{5^{16}}-5^3:5\)
\(=\frac{\left(5^2\right)^9}{5^{16}}-5^2\)
\(=\frac{5^{18}}{5^{16}}-25\)
\(=5^2-25\)
\(=25-25\)
\(=0.\)
k) \(\frac{5}{7}-\left|\frac{2}{-7}\right|\)
\(=\frac{5}{7}-\left|\frac{-2}{7}\right|\)
\(=\frac{5}{7}-\frac{2}{7}\)
\(=\frac{3}{7}.\)
l) \(\frac{3^6.3^4}{9^3}\)
\(=\frac{3^{6+4}}{\left(3^2\right)^3}\)
\(=\frac{3^{10}}{3^6}\)
\(=3^4.\)
\(=81.\)
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31 tháng 3 2019
=\(\frac{5}{9}\left(\frac{1}{6}+\frac{2}{7}+\frac{5}{7}-\frac{3}{7}\right)\)
=\(\frac{5}{9}.\frac{31}{42}\)
=155/378
\(N=\frac{-5}{9}\cdot\frac{3}{7} +\frac{4}{7}\cdot+\frac{-5}{9}+2019\frac{5}{9}\)
\(N=\frac{-5}{9}\left(\frac{3}{7}+\frac{4}{7}\right)+2019+\frac{5}{9}\)
\(=\frac{-5}{9}\cdot1+\frac{5}{9}+2019\)
\(=0+2019\)
\(=2019\)
\(N=-\frac{5}{9}\left(\frac{3}{7}+\frac{4}{7}\right)+2019\frac{5}{9}\)
\(N=-\frac{5}{9}+2019+\frac{5}{9}\)
\(N=2019\)