T=(1-1/4)×(1-1/9)×(1-1/16)×...×(1-1/576)×(1-1625)
Ai nhanh mik tck cho 3 tick nha mn
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Câu hỏi của Nguyễn Văn Duyệt - Toán lớp 5 - Học toán với OnlineMath
Em tham khảo nhé!
T = 3/4 x 8/9 x 15/16 x ... x 575/576 x 624/625
T = (1x3/1x4) x (2x4/3x3) x (3x5/4x4) x ... x (23x25/24x24) x (24x26/25x25)
T = [1 x 2/3 x 3/4 x 4/5 x ... x 23/24 x 24/25] x [3/5 x 4/3 x 5/4 x 6/5 x ... x 25/24 x 26/25]
T = 2/25 x 26/5
T = 52/125
(1-1/4).(1-1/9)......(1-1/100)
=1/1-1/4.1/4-1/9....1/9-1/100
=1/1-1/100
=99/100
\(\left(1-\frac{1}{4}\right).\left(1-\frac{1}{9}\right).....\left(1-\frac{1}{100}\right)\)
= 3/4.8/9.....99/100
= 3.8....99/4.9....100
=1.3.2.4.....9.11/2.2.3.3....10.10
= (1.2.3....9) . (3.4...11)/(2.3.4....10).(2.3.4...10 )
=11/10.2 = 11/20
k mk nha bn
\(B=\frac{3}{4}.\frac{8}{9}.\frac{15}{16}...\frac{9999}{10000}\)
\(B=\frac{3}{2^2}.\frac{8}{3^2}.\frac{15}{4^2}...\frac{9999}{100^2}\)
\(B=\frac{3.8.15...9999}{2^2.3^2.4^2...100^2}\)
\(B=\frac{1.3.2.4.3.5...99.101}{2.2.3.3.4.4...100.100}\)
\(B=\frac{\left(1.2.3...99\right).\left(3.4.5...101\right)}{\left(2.3.4...100\right).\left(2.3.4...100\right)}\)
\(B=\frac{1.101}{100.2}\)
\(B=\frac{101}{200}\)
\(C=\left(1+\frac{1}{2}\right).\left(1+\frac{1}{3}\right).\left(1+\frac{1}{4}\right)...\left(1+\frac{1}{99}\right).\left(1+\frac{1}{100}\right)\)
\(C=\frac{3}{2}.\frac{4}{3}.\frac{5}{4}...\frac{100}{99}.\frac{101}{100}\)
\(C=\frac{3.4.5...100.101}{2.3.4...99.100}\)
\(C=\frac{101}{2}\)
Dấu . là dâú x nha
Ta có:
x = \(\frac{17^{16}-3}{17^{16}+1}=\frac{17^{16}+1-4}{17^{16}+1}=\frac{17^{16}+1}{17^{16}+1}-\frac{4}{17^{16}+1}=1-\frac{4}{17^{16}+1}\)
y = \(\frac{17^{17}-3}{17^{17}+1}=\frac{17^{17}+1-4}{17^{17}+1}=\frac{17^{17}+1}{17^{17}+1}-\frac{4}{17^{17}+1}=1-\frac{4}{17^{17}+1}\)
Do \(\frac{4}{17^{16}+1}>\frac{4}{17^{17}+1}\) => \(-\frac{4}{17^{16}+1}< -\frac{4}{17^{17}+1}\) => \(1-\frac{4}{17^{16}+1}< 1-\frac{4}{17^{17}+1}\)
=> x < y
b) \(\frac{4}{9}x-\frac{1}{2}=\frac{-5}{9}\)
\(\Rightarrow\frac{4}{9}x=\frac{-5}{9}+\frac{1}{2}\)
\(\Rightarrow\frac{4}{9}x=\frac{-1}{18}\)
\(\Rightarrow x=\frac{-1}{18}:\frac{4}{9}\)
\(\Rightarrow x=\frac{-1}{8}\)
\(\frac{1}{x}-\frac{1}{4}=\frac{\frac{16}{1}}{x-1}\)
Có phải đề là vậy ko bạn
Sửa đề : \(T=\left[1-\frac{1}{4}\right]\times\left[1-\frac{1}{9}\right]\times\left[1-\frac{1}{16}\right]\times...\times\left[1-\frac{1}{576}\right]\times\left[1-\frac{1}{625}\right]\)
\(T=\frac{3}{4}\cdot\frac{8}{9}\cdot\frac{15}{16}\cdot...\cdot\frac{575}{576}\cdot\frac{624}{625}\)
\(T=\frac{1\cdot3}{2\cdot2}\cdot\frac{2\cdot4}{3\cdot3}\cdot\frac{3\cdot5}{4\cdot4}\cdot...\cdot\frac{23\cdot25}{24\cdot24}\cdot\frac{24\cdot26}{25\cdot25}\)
\(T=\frac{1\cdot2\cdot3\cdot....\cdot23\cdot24}{2\cdot3\cdot4\cdot....\cdot24\cdot25}\cdot\frac{3\cdot4\cdot5\cdot...\cdot25\cdot26}{2\cdot3\cdot4\cdot...\cdot24\cdot25}\)
Đến đây dễ rồi nhé bạn :v
\(T=\left(1-\frac{1}{4}\right)\times\left(1-\frac{1}{9}\right)\times\left(1-\frac{1}{16}\right)\times...\times\left(1-\frac{1}{157}\right)\times\left(1-\frac{1}{625}\right)\)
\(T=\frac{3}{4}\times\frac{8}{9}\times\frac{15}{16}\times...\times\frac{156}{157}\times\frac{624}{625}\)
\(T=\frac{3\times2\times4\times3\times5\times...\times23\times25\times24\times26}{2\times2\times3\times3\times4\times4\times...\times24\times24\times25\times25}\)
\(T=\frac{1\times26}{2\times25}=\frac{26}{50}=\frac{13}{25}\)