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23 tháng 4 2019

\(\left(4,5+2x\right)\div\frac{3}{4}=-1\frac{1}{3}\)

\(\Leftrightarrow\left(4,5+2x\right)\div\frac{3}{4}=-\frac{4}{3}\)

\(\Leftrightarrow4,5+2x=-\frac{4}{3}\times\frac{3}{4}\)

\(\Leftrightarrow4,5+2x=-1\)

\(\Leftrightarrow2x=-1-4,5\)
\(\Leftrightarrow2x=-5,5\)

\(\Leftrightarrow x=-5,5\div2\)

\(\Leftrightarrow x=-2,75\)

a: Ta có: \(\left|\dfrac{2}{5}-x\right|+\dfrac{1}{2}=3.5\)

\(\Leftrightarrow\left|x-\dfrac{2}{5}\right|=3\)

\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{2}{5}=3\\x-\dfrac{2}{5}=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{17}{5}\\x=-\dfrac{13}{5}\end{matrix}\right.\)

b: Ta có: \(\dfrac{21}{5}+3:\left|\dfrac{x}{4}-\dfrac{2}{3}\right|=6\)

\(\Leftrightarrow3:\left|\dfrac{1}{4}x-\dfrac{2}{3}\right|=6-\dfrac{21}{5}=\dfrac{9}{5}\)

\(\Leftrightarrow\left|\dfrac{1}{4}x-\dfrac{2}{3}\right|=\dfrac{5}{3}\)

\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{4}x-\dfrac{2}{3}=\dfrac{5}{3}\\\dfrac{1}{4}x-\dfrac{2}{3}=-\dfrac{5}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{4}x=\dfrac{7}{3}\\\dfrac{1}{4}x=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{28}{3}\\x=-4\end{matrix}\right.\)

em muốn hỏi là tại sao 3,5 bên trên xuống dưới lại là 3 và -x +2/5 của em xuống dưới lại chuyển thành x-2/5 ạ mong anh giải đáp

b: 4(x+1)^2-9(x-1)^2=0

=>(2x+2)^2-(3x-3)^2=0

=>(2x+2-3x+3)(2x+2+3x-3)=0

=>(-x+5)(5x-1)=0

=>x=1/5 hoặc x=5

c: (x-1)^3+x^3+(x+1)^3=(x+2)^3

=>x^3-3x^2+3x-1+x^3+x^3+3x^2+3x+1=x^3+6x^2+12x+8

=>3x^3+6x-x^3-6x^2-12x-8=0

=>2x^3-6x^2-6x-8=0

=>x^3-3x^2-3x-4=0

=>x^3-4x^2+x^2-4x+x-4=0

=>(x-4)(x^2+x+1)=0

=>x-4=0

=>x=4

28 tháng 9 2015

a.=> \(\frac{\left(\frac{1}{3}\right).x}{\frac{2}{3}}=\frac{\frac{7}{4}}{\frac{2}{5}}\)

=> \(\frac{1}{3}.x=\frac{7}{4}.\frac{2}{3}:\frac{2}{5}\)

=>\(\frac{1}{3}.x=\frac{35}{12}\)

=> x\(=\frac{35}{12}:\frac{1}{3}\)

Vậy x=\(\frac{35}{4}\).

b. => \(\frac{4,5}{0,3}=\frac{2,25}{0,1.x}\)

=>\(0,1.x=\frac{2,25.0,3}{4,5}\)

=>\(0,1.x=0,15\)

=>\(x=0,15:0,1\)

Vậy x=1,5

c. =>\(\frac{8}{\frac{1}{4}.x}=\frac{2}{0,02}\)

=>\(\frac{1}{4}.x=\frac{8.0,02}{2}\)

=>\(\frac{1}{4}.x=0,08\)

=>\(x=0,08:\frac{1}{4}\)

Vậy x=0,32.

d. =>\(\frac{3}{\frac{9}{4}}=\frac{\frac{3}{4}}{6.x}\)

=>\(3.6x=\frac{9}{4}.\frac{3}{4}\)

=>\(18x=\frac{27}{16}\)

=>\(x=\frac{27}{16}:18\)

Vậy x=\(\frac{3}{32}\)

a) Ta có: \(\frac{4}{5}+x=\frac{2}{3}\)

hay \(x=\frac{2}{3}-\frac{4}{5}=\frac{10}{15}-\frac{12}{15}=\frac{-2}{15}\)

Vậy: \(x=\frac{-2}{15}\)

b) Ta có: \(\frac{3}{4}-x=\frac{1}{3}\)

hay \(x=\frac{3}{4}-\frac{1}{3}=\frac{9}{12}-\frac{4}{12}=\frac{5}{12}\)

Vậy: \(x=\frac{5}{12}\)

c) Ta có: \(x-\frac{5}{9}=\frac{-2}{3}\)

hay \(x=\frac{-2}{3}+\frac{5}{9}=\frac{-6}{9}+\frac{5}{9}=-\frac{1}{9}\)

Vậy: \(x=\frac{-1}{9}\)

d) Ta có: \(\frac{\left(4,5-2x\right)}{\frac{3}{4}}=1\frac{1}{3}\)

\(\Leftrightarrow\frac{9}{2}-2x=\frac{4}{3}\cdot\frac{3}{4}=1\)

\(\Leftrightarrow2x=\frac{9}{2}-1=\frac{7}{2}\)

hay \(x=\frac{7}{4}\)

Vậy: \(x=\frac{7}{4}\)

28 tháng 4 2021

i don't know

21 tháng 4 2016

a, 2x+ 1/4 = 3/2

2x = 3/2-1/4

2x = 5/4

x=5/4:2

x= 5/8 

b, (x-5) - 1/3 = 2/5

x-5= 2/5+1/3

x-5=11/15

x=11/15+5

x=86/15

c, (4,5-2x):3/4=4/3

(4,5-2x)=4/3. 3/4

4,5-2x=1

2x= 5,5

x=5,5:2

x=2,75

21 tháng 4 2016

a) 2x+1/4=3/2

=> 2x      =3/2-1/4

=> 2x       =5/4

=> x         =5/4:2

=> x         =5/8

b) (x-5)-1/3=2/5

=>  x-5      =2/5+1/3

=> x-5        =11/15

=> x           =11/15+5

=> x           =86/15

c) (4,5-2x):3/4=4/3

=> 4,5-2x       =4/3x3/4

=> 4,5-2x       =1

=>   2x          =4,5-1

=>   2x           =3,5

=>    x             =3,5:2

=>    x             =1,75

a) \(3\frac{1}{3}\left(3\frac{1}{4}+2x\right)=6\frac{2}{3}\)

   \(3\frac{1}{3}\times3\frac{1}{4}+2x=6\frac{2}{3}\)

   \(10\frac{5}{6}+2x=6\frac{2}{3}\)

   \(2\times x=6\frac{2}{3}+10\frac{5}{6}=17,5\)

   \(x=17,5\div2=8,75\)

Vậy x = 8,75

b) \(x-25\%x=\frac{6}{11}\left(\frac{1}{2}+\frac{3}{4}-\frac{1}{3}\right)\)

   \(x-\frac{25}{100}x=\frac{6}{11}\left(\frac{1}{2}+\frac{3}{4}-\frac{1}{3}\right)\)

   \(x-\frac{1}{4}\times x=\frac{6}{11}\times1\frac{7}{12}=\frac{19}{22}\)

   \(x\times x=\frac{19}{22}+\frac{1}{4}=\frac{49}{44}\)

\(\Rightarrow2x\left(x\times x\right)=\frac{49}{44}\)   

   \(x=\frac{49}{44}\div2=\frac{49}{88}\)

   Vậy x = \(\frac{49}{88}\)

c) \(\left(4,5-2x\right)\times1\frac{4}{7}=\frac{11}{14}\)

   \(4,5-2x\times1\frac{4}{7}=\frac{11}{14}\)

   \(-2x\times1\frac{4}{7}=\frac{11}{14}-4,5=-3\frac{5}{7}\)

   \(-2\times x=-3\frac{5}{7}\div1\frac{4}{7}=-2\frac{4}{11}\)

   \(x=-2\frac{4}{11}\div\left(-2\right)=1\frac{2}{11}\)

Vậy x = \(1\frac{2}{11}\)

d) \(-3^2-|2x+3|=4\)

    \(9-|2x+3|=4\)

   \(-|2x+3|=4-9=-5\)

   \(-|2x|=-5-|3|=-8\)

   \(-|x|=-8\div2=-4\)

    \(-x=4\Rightarrow x=-4\)

   Vậy x = -4 (-x được xem là số đối của x)

b: \(x+\dfrac{5}{6}=\dfrac{3}{8}\)

=>\(x=\dfrac{3}{8}-\dfrac{5}{6}\)

=>\(x=\dfrac{9}{24}-\dfrac{20}{24}=-\dfrac{11}{24}\)

c: \(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{5}{6}\)

=>\(\dfrac{2}{3}x=\dfrac{5}{6}+\dfrac{1}{2}=\dfrac{8}{6}=\dfrac{4}{3}\)

=>2x=4

=>x=4/2=2

d: \(\dfrac{x}{7}=\dfrac{6}{-21}\)

=>\(\dfrac{x}{7}=\dfrac{-2}{7}\)

=>x=-2

e: \(\left(\dfrac{7}{3}x-0,6\right):\dfrac{3^2}{5}=1\)

=>\(\dfrac{7}{3}x-0,6=\dfrac{3^2}{5}=1,8\)

=>\(\dfrac{7}{3}x=2,4\)

=>\(x=2,4:\dfrac{7}{3}=2.4\cdot\dfrac{3}{7}=\dfrac{7.2}{7}=\dfrac{36}{35}\)

f: \(\dfrac{x}{45}=\dfrac{5}{6}+\dfrac{-29}{30}\)

=>\(\dfrac{x}{45}=\dfrac{25}{30}-\dfrac{29}{30}=-\dfrac{4}{30}=-\dfrac{2}{15}\)

=>\(x=-\dfrac{2}{15}\cdot45=-6\)

g: \(\left(4,5-2x\right)\cdot\left(-\dfrac{1^4}{7}\right)=\dfrac{11}{14}\)

=>\(4,5-2x=\dfrac{11}{14}:\dfrac{-1}{7}=\dfrac{-11}{2}\)

=>\(2x=4,5+\dfrac{11}{2}=\dfrac{20}{2}=10\)

=>x=10/2=5

h: \(-\dfrac{2}{7}+\dfrac{4}{7}x=\dfrac{5}{7}\)

=>\(\dfrac{4}{7}x=\dfrac{5}{7}+\dfrac{2}{7}=\dfrac{7}{7}\)

=>4x=7

=>\(x=\dfrac{7}{4}\)