(4,5+2.x):3/4=-1 1/3
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a: Ta có: \(\left|\dfrac{2}{5}-x\right|+\dfrac{1}{2}=3.5\)
\(\Leftrightarrow\left|x-\dfrac{2}{5}\right|=3\)
\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{2}{5}=3\\x-\dfrac{2}{5}=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{17}{5}\\x=-\dfrac{13}{5}\end{matrix}\right.\)
b: Ta có: \(\dfrac{21}{5}+3:\left|\dfrac{x}{4}-\dfrac{2}{3}\right|=6\)
\(\Leftrightarrow3:\left|\dfrac{1}{4}x-\dfrac{2}{3}\right|=6-\dfrac{21}{5}=\dfrac{9}{5}\)
\(\Leftrightarrow\left|\dfrac{1}{4}x-\dfrac{2}{3}\right|=\dfrac{5}{3}\)
\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{4}x-\dfrac{2}{3}=\dfrac{5}{3}\\\dfrac{1}{4}x-\dfrac{2}{3}=-\dfrac{5}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{4}x=\dfrac{7}{3}\\\dfrac{1}{4}x=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{28}{3}\\x=-4\end{matrix}\right.\)
em muốn hỏi là tại sao 3,5 bên trên xuống dưới lại là 3 và -x +2/5 của em xuống dưới lại chuyển thành x-2/5 ạ mong anh giải đáp
b: 4(x+1)^2-9(x-1)^2=0
=>(2x+2)^2-(3x-3)^2=0
=>(2x+2-3x+3)(2x+2+3x-3)=0
=>(-x+5)(5x-1)=0
=>x=1/5 hoặc x=5
c: (x-1)^3+x^3+(x+1)^3=(x+2)^3
=>x^3-3x^2+3x-1+x^3+x^3+3x^2+3x+1=x^3+6x^2+12x+8
=>3x^3+6x-x^3-6x^2-12x-8=0
=>2x^3-6x^2-6x-8=0
=>x^3-3x^2-3x-4=0
=>x^3-4x^2+x^2-4x+x-4=0
=>(x-4)(x^2+x+1)=0
=>x-4=0
=>x=4
a.=> \(\frac{\left(\frac{1}{3}\right).x}{\frac{2}{3}}=\frac{\frac{7}{4}}{\frac{2}{5}}\)
=> \(\frac{1}{3}.x=\frac{7}{4}.\frac{2}{3}:\frac{2}{5}\)
=>\(\frac{1}{3}.x=\frac{35}{12}\)
=> x\(=\frac{35}{12}:\frac{1}{3}\)
Vậy x=\(\frac{35}{4}\).
b. => \(\frac{4,5}{0,3}=\frac{2,25}{0,1.x}\)
=>\(0,1.x=\frac{2,25.0,3}{4,5}\)
=>\(0,1.x=0,15\)
=>\(x=0,15:0,1\)
Vậy x=1,5
c. =>\(\frac{8}{\frac{1}{4}.x}=\frac{2}{0,02}\)
=>\(\frac{1}{4}.x=\frac{8.0,02}{2}\)
=>\(\frac{1}{4}.x=0,08\)
=>\(x=0,08:\frac{1}{4}\)
Vậy x=0,32.
d. =>\(\frac{3}{\frac{9}{4}}=\frac{\frac{3}{4}}{6.x}\)
=>\(3.6x=\frac{9}{4}.\frac{3}{4}\)
=>\(18x=\frac{27}{16}\)
=>\(x=\frac{27}{16}:18\)
Vậy x=\(\frac{3}{32}\)
a) Ta có: \(\frac{4}{5}+x=\frac{2}{3}\)
hay \(x=\frac{2}{3}-\frac{4}{5}=\frac{10}{15}-\frac{12}{15}=\frac{-2}{15}\)
Vậy: \(x=\frac{-2}{15}\)
b) Ta có: \(\frac{3}{4}-x=\frac{1}{3}\)
hay \(x=\frac{3}{4}-\frac{1}{3}=\frac{9}{12}-\frac{4}{12}=\frac{5}{12}\)
Vậy: \(x=\frac{5}{12}\)
c) Ta có: \(x-\frac{5}{9}=\frac{-2}{3}\)
hay \(x=\frac{-2}{3}+\frac{5}{9}=\frac{-6}{9}+\frac{5}{9}=-\frac{1}{9}\)
Vậy: \(x=\frac{-1}{9}\)
d) Ta có: \(\frac{\left(4,5-2x\right)}{\frac{3}{4}}=1\frac{1}{3}\)
\(\Leftrightarrow\frac{9}{2}-2x=\frac{4}{3}\cdot\frac{3}{4}=1\)
\(\Leftrightarrow2x=\frac{9}{2}-1=\frac{7}{2}\)
hay \(x=\frac{7}{4}\)
Vậy: \(x=\frac{7}{4}\)
a, 2x+ 1/4 = 3/2
2x = 3/2-1/4
2x = 5/4
x=5/4:2
x= 5/8
b, (x-5) - 1/3 = 2/5
x-5= 2/5+1/3
x-5=11/15
x=11/15+5
x=86/15
c, (4,5-2x):3/4=4/3
(4,5-2x)=4/3. 3/4
4,5-2x=1
2x= 5,5
x=5,5:2
x=2,75
a) 2x+1/4=3/2
=> 2x =3/2-1/4
=> 2x =5/4
=> x =5/4:2
=> x =5/8
b) (x-5)-1/3=2/5
=> x-5 =2/5+1/3
=> x-5 =11/15
=> x =11/15+5
=> x =86/15
c) (4,5-2x):3/4=4/3
=> 4,5-2x =4/3x3/4
=> 4,5-2x =1
=> 2x =4,5-1
=> 2x =3,5
=> x =3,5:2
=> x =1,75
a) \(3\frac{1}{3}\left(3\frac{1}{4}+2x\right)=6\frac{2}{3}\)
\(3\frac{1}{3}\times3\frac{1}{4}+2x=6\frac{2}{3}\)
\(10\frac{5}{6}+2x=6\frac{2}{3}\)
\(2\times x=6\frac{2}{3}+10\frac{5}{6}=17,5\)
\(x=17,5\div2=8,75\)
Vậy x = 8,75
b) \(x-25\%x=\frac{6}{11}\left(\frac{1}{2}+\frac{3}{4}-\frac{1}{3}\right)\)
\(x-\frac{25}{100}x=\frac{6}{11}\left(\frac{1}{2}+\frac{3}{4}-\frac{1}{3}\right)\)
\(x-\frac{1}{4}\times x=\frac{6}{11}\times1\frac{7}{12}=\frac{19}{22}\)
\(x\times x=\frac{19}{22}+\frac{1}{4}=\frac{49}{44}\)
\(\Rightarrow2x\left(x\times x\right)=\frac{49}{44}\)
\(x=\frac{49}{44}\div2=\frac{49}{88}\)
Vậy x = \(\frac{49}{88}\)
c) \(\left(4,5-2x\right)\times1\frac{4}{7}=\frac{11}{14}\)
\(4,5-2x\times1\frac{4}{7}=\frac{11}{14}\)
\(-2x\times1\frac{4}{7}=\frac{11}{14}-4,5=-3\frac{5}{7}\)
\(-2\times x=-3\frac{5}{7}\div1\frac{4}{7}=-2\frac{4}{11}\)
\(x=-2\frac{4}{11}\div\left(-2\right)=1\frac{2}{11}\)
Vậy x = \(1\frac{2}{11}\)
d) \(-3^2-|2x+3|=4\)
\(9-|2x+3|=4\)
\(-|2x+3|=4-9=-5\)
\(-|2x|=-5-|3|=-8\)
\(-|x|=-8\div2=-4\)
\(-x=4\Rightarrow x=-4\)
Vậy x = -4 (-x được xem là số đối của x)
b: \(x+\dfrac{5}{6}=\dfrac{3}{8}\)
=>\(x=\dfrac{3}{8}-\dfrac{5}{6}\)
=>\(x=\dfrac{9}{24}-\dfrac{20}{24}=-\dfrac{11}{24}\)
c: \(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{5}{6}\)
=>\(\dfrac{2}{3}x=\dfrac{5}{6}+\dfrac{1}{2}=\dfrac{8}{6}=\dfrac{4}{3}\)
=>2x=4
=>x=4/2=2
d: \(\dfrac{x}{7}=\dfrac{6}{-21}\)
=>\(\dfrac{x}{7}=\dfrac{-2}{7}\)
=>x=-2
e: \(\left(\dfrac{7}{3}x-0,6\right):\dfrac{3^2}{5}=1\)
=>\(\dfrac{7}{3}x-0,6=\dfrac{3^2}{5}=1,8\)
=>\(\dfrac{7}{3}x=2,4\)
=>\(x=2,4:\dfrac{7}{3}=2.4\cdot\dfrac{3}{7}=\dfrac{7.2}{7}=\dfrac{36}{35}\)
f: \(\dfrac{x}{45}=\dfrac{5}{6}+\dfrac{-29}{30}\)
=>\(\dfrac{x}{45}=\dfrac{25}{30}-\dfrac{29}{30}=-\dfrac{4}{30}=-\dfrac{2}{15}\)
=>\(x=-\dfrac{2}{15}\cdot45=-6\)
g: \(\left(4,5-2x\right)\cdot\left(-\dfrac{1^4}{7}\right)=\dfrac{11}{14}\)
=>\(4,5-2x=\dfrac{11}{14}:\dfrac{-1}{7}=\dfrac{-11}{2}\)
=>\(2x=4,5+\dfrac{11}{2}=\dfrac{20}{2}=10\)
=>x=10/2=5
h: \(-\dfrac{2}{7}+\dfrac{4}{7}x=\dfrac{5}{7}\)
=>\(\dfrac{4}{7}x=\dfrac{5}{7}+\dfrac{2}{7}=\dfrac{7}{7}\)
=>4x=7
=>\(x=\dfrac{7}{4}\)
\(\left(4,5+2x\right)\div\frac{3}{4}=-1\frac{1}{3}\)
\(\Leftrightarrow\left(4,5+2x\right)\div\frac{3}{4}=-\frac{4}{3}\)
\(\Leftrightarrow4,5+2x=-\frac{4}{3}\times\frac{3}{4}\)
\(\Leftrightarrow4,5+2x=-1\)
\(\Leftrightarrow2x=-1-4,5\)
\(\Leftrightarrow2x=-5,5\)
\(\Leftrightarrow x=-5,5\div2\)
\(\Leftrightarrow x=-2,75\)