a, A=\(\frac{-2}{4}\)+\(\frac{2}{7}\)-\(\frac{5}{28}\) b,B= \(\frac{-7}{9}\)*\(\frac{4}{11}\)+\(\frac{-7}{9}\)*\(\frac{7}{11}\)+5\(\frac{7}{9}\)
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\(c)\) \(C=\frac{\frac{2}{7}+\frac{2}{5}+\frac{2}{17}-\frac{2}{293}}{\frac{3}{7}+\frac{3}{5}+\frac{3}{17}-\frac{3}{293}}\)
\(C=\frac{2\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}-\frac{1}{293}\right)}{3\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}-\frac{1}{193}\right)}\)
\(C=\frac{2}{3}\)
Bạn Cô nàng Thiên Bình làm đúng hết òi =.=
a=7.[1/8+1/27-1/49]
------------------------
11.[1/8+1/27-1/49]
=7/11
cau b,c tuong tu nha h mk
B=\(6\frac{4}{9}-4\frac{4}{9}+3\frac{7}{11}\)
B=\(2+3\frac{7}{11}\)
B=\(5\frac{7}{11}\)
B = \(5\frac{7}{11}=\frac{62}{11}\)
C = 1
D = \(\frac{5}{2}=2\frac{1}{2}\)
a) Ta có :
\(A=\frac{\frac{2}{5}-\frac{2}{9}+\frac{2}{11}}{\frac{7}{5}-\frac{7}{9}+\frac{7}{11}}\)
\(A=\frac{2\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}{7\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}\)
\(A=\frac{2}{7}\)
b) Ta có :
\(B=\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{7}{6}-\frac{7}{8}+\frac{7}{10}}\)
\(B=\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{7}{2}\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{5}\right)}\)
\(B=\frac{2}{7}\)
\(\Rightarrow\frac{A}{B}=\frac{\frac{2}{7}}{\frac{2}{7}}=1\)
\(A=\frac{-2}{4}+\frac{2}{7}-\frac{5}{28}\)
\(\Rightarrow A=\frac{-14}{28}+\frac{8}{28}-\frac{5}{28}\)
\(\Rightarrow A=\frac{-6}{28}-\frac{5}{28}\)
\(\Rightarrow A=\frac{-11}{28}\)
\(B=\frac{-7}{9}.\frac{4}{11}+\frac{-7}{9}.\frac{7}{5}+5.\frac{7}{9}\)
\(\Rightarrow B=\frac{-7}{9}.\frac{4}{11}+\frac{-7}{9}.\frac{7}{5}-5.\frac{-7}{9}\)
\(\Rightarrow B=\frac{-7}{9}.\left(\frac{4}{11}+\frac{7}{11}-5\right)\)
\(\Rightarrow B=\frac{-7}{9}.\left(1-5\right)\)
\(\Rightarrow B=\frac{-7}{9}.\left(-4\right)\)
\(\Rightarrow B=\frac{-28}{9}\)