3/4-1/4x-1=40%.(-5/3)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a)
\(5x\left(4-8x\right)+40\left(x^2-1\right)=3\\ \Leftrightarrow20x-40x^2+40x^2-40=3\\ \Leftrightarrow20x-40=3\\ \Leftrightarrow20\left(x-2\right)=3\\ \Leftrightarrow x-2=\frac{3}{20}\\ \Leftrightarrow x=\frac{43}{20}\)
b)
\(\left(4x-5\right)\left(7-8x\right)+4x\left(3+8x\right)=4\\ \Leftrightarrow28x-32x^2-35+40x+12x+32x^2=4\\ \Leftrightarrow80x-35=4\\ \Leftrightarrow80x=39\\ \Leftrightarrow x=\frac{39}{80}\)
a) \(5x\left(4-8x\right)+40\left(x^2-1\right)=3\)
\(\Leftrightarrow\)\(20x-40x^2+40x^2-40=3\)
\(\Leftrightarrow20x-40=3\)
\(\Leftrightarrow20x=43\)
\(\Leftrightarrow x=\frac{43}{20}\)
b, \(\left(4x-5\right)\left(7-8x\right)+4x\left(3+8x\right)=4\)
\(\Leftrightarrow28x-32x^2-35+40x+12x+32x^2=4\)
\(\Leftrightarrow80x-35=4\)
\(\Leftrightarrow80x=39\)
\(\Leftrightarrow x=\frac{39}{80}\)
a: \(\Leftrightarrow2x^2+4-x^2+\dfrac{3}{2}=-3+4x^2-\dfrac{4}{3}x^2+1\)
\(\Leftrightarrow x^2+\dfrac{11}{2}=\dfrac{8}{3}x^2-2\)
\(\Leftrightarrow x^2\cdot\dfrac{-5}{3}=-\dfrac{15}{2}\)
\(\Leftrightarrow x^2=\dfrac{9}{2}\)
hay \(x\in\left\{\dfrac{3\sqrt{2}}{2};-\dfrac{3\sqrt{2}}{2}\right\}\)
b: \(\Leftrightarrow\left|x\right|-4-2+\left|x\right|-\dfrac{1}{3}\left|x\right|+5=0\)
\(\Leftrightarrow\left|x\right|\cdot\dfrac{5}{3}=1\)
hay \(x\in\left\{\dfrac{3}{5};-\dfrac{3}{5}\right\}\)
Bài 1:
c) ĐKXĐ: \(x\notin\left\{\dfrac{1}{4};-\dfrac{1}{4}\right\}\)
Ta có: \(\dfrac{3}{1-4x}=\dfrac{2}{4x+1}-\dfrac{8+6x}{16x^2-1}\)
\(\Leftrightarrow\dfrac{-3\left(4x+1\right)}{\left(4x-1\right)\left(4x+1\right)}=\dfrac{2\left(4x-1\right)}{\left(4x+1\right)\left(4x-1\right)}-\dfrac{6x+8}{\left(4x-1\right)\left(4x+1\right)}\)
Suy ra: \(-12x-3=8x-2-6x-8\)
\(\Leftrightarrow-12x-3-2x+10=0\)
\(\Leftrightarrow-14x+7=0\)
\(\Leftrightarrow-14x=-7\)
\(\Leftrightarrow x=\dfrac{1}{2}\)(nhận)
Vậy: \(S=\left\{\dfrac{1}{2}\right\}\)
Bài 1:
b: \(=2\left(4x^2+20x+25\right)+3\left(16x^2-1\right)\)
\(=8x^2+40x+50+48x^2-3\)
\(=56x^2+40x+47\)
Bài 2:
b: \(\Leftrightarrow3x-3+9x-18=2x-6+4x-4\)
=>12x-21=6x-10
=>6x=11
hay x=11/6
\(a,A=-1+3-5+7-9+...-2013+2015-2017=\left(-1+3\right)+\left(-5+7\right)+...+\left(-2013+2015\right)-2017\)\(=2+2+..+2-2017\)
\(=2.504-2017=-1009\)
\(b,B=2-4+6-8+...+2014-2016+2018\)\(=2+\left(-4+6\right)+\left(-8+10\right)+...+\left(-2016+2018\right)==2+2+...+2\)\(=2+503.2=1008\)
\(\frac{3}{4}-\frac{1}{4}x-1=40\%\times\frac{-5}{3}\)
\(\Leftrightarrow\frac{1}{4}\left(3-x\right)-1=\frac{40}{100}\times\frac{-5}{3}\)
\(\Leftrightarrow\frac{1}{4}\left(3-x\right)-1=\frac{2}{5}\times\frac{-5}{3}\)
\(\Leftrightarrow\frac{1}{4}\left(3-x\right)-\frac{15}{15}=\frac{-10}{15}\)
\(\Leftrightarrow\frac{1}{4}\left(3-x\right)=\frac{-10}{15}+\frac{15}{15}\)
\(\Leftrightarrow\frac{1}{4}\left(3-x\right)=\frac{5}{15}\)
\(\Leftrightarrow3-x=\frac{5}{15}\div\frac{1}{4}\)
\(\Leftrightarrow3-x=\frac{5}{15}\times4\)
\(\Leftrightarrow\frac{45}{15}-x=\frac{20}{15}\)
\(\Leftrightarrow x=\frac{45}{15}-\frac{20}{15}\)
\(\Leftrightarrow x=\frac{25}{15}=\frac{5}{3}\)