thực hiện phép tính
a:125-(-75)+32-(48+32)
b:3.(-4)có mũ là 2 +2.(-5)-20
c:[-1685]+(-2365)+[+569]-1685
giúp mình vs
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a)\(\left(-3\right).8.\left(-2\right).5=\left(-3\right).\left(-2\right).8.5\)
\(=6.40=240\)
b)\(127-18.\left(5+6\right)=127-18.11\)
\(=127-198=-71\)
c)\(125-\left(-75\right)+32-\left(48+32\right)=125+75+32-48-32\)
\(\left(125+75\right)+\left(32-32\right)-48=200-48=152\)
d)\(3.\left(-4\right).2+2.\left(-5\right)-20=-12.2+2.\left(-5\right)-20\)
\(=\left(-12-5\right).2-20=-17.2-20=-140-20=-160\)
Chúc bạn học tốt
Bài 1: Thực hiện các phép tính sau:
\(a)\)Chưa rỏ đề
\(b)\)\(5025\div5-25\div5\)
\(=\)\(1005-5\)
\(=\)\(1000\)
\(c)\)\(218-180\div2\div9\)
\(=\)\(218-10\)
\(=\)\(208\)
\(d)\)\(\left(328-8\right)\div32\)
\(=\)\(320\div32\)
\(=\)\(10\)
Bài 1:
a) ( Tôi không nhìn rõ đầu bài )
b) 5025 : 5 - 25 : 5
= ( 5025 - 25 ) : 5
= 5000 : 5
= 1000
c) 218 - 180 : 2 : 9
= 218 - 180 : ( 2 . 9 )
= 218 - 180 : 18
= 218 - 10
= 208
d) ( 328 - 8 ) : 32
= 320 : 32
= 10
125 - ( - 75) + 32 - ( 48 + 32)
= 125 - ( - 75) + 32 - 80
= 200 + 32 - 80
= 232 - 80
= 152
3 . ( -4)2 + 2 . ( -5) - 20
= 3 . 16 + ( -10 ) - 20
= 48 + ( -10 ) - 20
= 38 - 20
= 18
a)=125+75+32-48-32
=(125+75)+(32-32)-48
=200+0-48
=152
b)=3.16-10-20
=48-(10+20)
=48-30
=18
a) = [ - (5.2) ] . ( 8.3)
= (-10) . 24
= -240
b)= 125+75 + 32 - 48-32
= (125+75) + [(32-32)-48]
= 200 + [0 -48]
= 200 + (-48)
= 152
c) 3.(-4)2 + 2.(-5)-20
= 3.16 + (-10) - 20
= 48 + (-30)
= 18
d) = 47.[(300 + 47)+ (200+47)]
= 47. [(300+200).47]
= 47. 500 .47
= 47.500
=23500
p/s: Phần d tớ không chắc lắm đâu nhé nhưng nếu chắc tớ sai thì cậu làm theo cái này nhé:
d) = 47.(347+247)
= 47. 594
=27918
p/s: thấy cái này hơi hợp lý nè...
a)\(2\sqrt{\dfrac{16}{3}}-3\sqrt{\dfrac{1}{27}}-6\sqrt{\dfrac{4}{75}}\)
\(=2.\sqrt{\dfrac{4^2}{3}}-3.\sqrt{\dfrac{1}{3.3^2}}-6\sqrt{\dfrac{2^2}{3.5^2}}\)
\(=2.\dfrac{4}{\sqrt{3}}-3.\dfrac{1}{3\sqrt{3}}-6.\dfrac{2}{5\sqrt{3}}=\dfrac{8}{\sqrt{3}}-\dfrac{1}{\sqrt{3}}-\dfrac{12}{5\sqrt{3}}\)\(=\dfrac{23}{5\sqrt{3}}=\dfrac{23\sqrt{3}}{15}\)
b)\(\left(6\sqrt{\dfrac{8}{9}}-5\sqrt{\dfrac{32}{25}}+14\sqrt{\dfrac{18}{49}}\right).\sqrt{\dfrac{1}{2}}\)
\(=6\sqrt{\dfrac{8}{9}.\dfrac{1}{2}}-5\sqrt{\dfrac{32}{25}.\dfrac{1}{2}}+14\sqrt{\dfrac{18}{49}.\dfrac{1}{2}}\)
\(=6\sqrt{\dfrac{4}{9}}-5\sqrt{\dfrac{16}{25}}+14\sqrt{\dfrac{9}{49}}\)\(=6.\dfrac{2}{3}-5.\dfrac{4}{5}+14.\dfrac{3}{7}=6\)
c)\(\sqrt{\left(\sqrt{2}-2\right)^2}-\sqrt{6+4\sqrt{2}}=\left|\sqrt{2}-2\right|-\sqrt{4+2.2\sqrt{2}+2}=2-\sqrt{2}-\sqrt{\left(2+\sqrt{2}\right)^2}\)
\(=2-\sqrt{2}-\left(2+\sqrt{2}\right)=-2\sqrt{2}\)
b, \(\dfrac{2}{\sqrt{5}+2}+\dfrac{2}{2-\sqrt{5}}\)
\(=\dfrac{2\left(\sqrt{5}-2\right)}{5-4}-\dfrac{2\left(\sqrt{5}+2\right)}{5-4}\)
\(=2\sqrt{5}-4-2\sqrt{5}-4=-8\)
a: =58(57+150-125)=58x82=4756
b: \(=9\cdot5-4\cdot7+83=45-28+83=100\)
c: =(2019-2019)+(-247-53)=-300
d: \(=13\cdot70-50\cdot\left[10:2+8\right]=910-50\cdot13=910-650=260\)
\(a,=58.\left(57+150-125\right)\\ =58.82=4756\\ b,=9.5-4.7+83.1\\ =45-28+83=100\)
a) \(125-\left(-75\right)+32-\left(48+32\right)\)
\(=125+75+32-48-32\)
\(=200+\left(32-32\right)-48\)
\(=200+0-48\)
\(=200-48\)
\(=152\)
b) \(3.\left(-4\right)^2+2.\left(-5\right)-20\)
\(=3.16-10-20\)
\(=48-30\)
\(=18\)
c) \(-1685+\left(-2365\right)+569-1685\)
\(=\left(-1685-1685\right)-2365+569\)
\(=-3370-2365+569\)
\(=-5735+569\)
\(=-5166\)