272-[4xX+15]=45
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
4x+15 = 272-45
4x+15 = 227
4x = 227-15
4x = 212
x = 56,75
tui đầu tiên **** đi
`a, 504 : (16-3x)=72`
`<=> 16-3x=7`
`<=>3x=9`
`<=>x=3`
`b,272-(4x+15)=45`
`<=>4x+15=227`
`<=>4x=212`
`<=>x=53`
a: =>16-3x=504:72=7
=>3x=9
=>x=3
b: =>4x+15=272-45=227
=>4x=212
=>x=53
\(272+\left(146+x\right)=118\)
\(272+146+x=118\)
\(418+x=118\)
\(x=118-418\)
\(x=-300\)
\(4\times x-15=-75-x\)
\(\Leftrightarrow4x-15+75=-x\)
\(\Leftrightarrow4x+60=-x\)
\(\Leftrightarrow60=-x-4x\)
\(\Leftrightarrow60=-5x\)
\(\Leftrightarrow x=-12\)
Vậy \(x=-12\)
\(\dfrac{4\times x}{1\times5}\) + \(\dfrac{4\times x}{5\times9}\) + \(\dfrac{4\times x}{9\times13}\) + \(\dfrac{4\times x}{13\times17}\) = 16
\(x\times\left(\dfrac{4}{1\times5}+\dfrac{4}{5\times9}+\dfrac{4}{9\times13}+\dfrac{4}{13\times17}\right)\) = 16
\(x\) \(\times\) (\(\dfrac{1}{1}\) - \(\dfrac{1}{5}\) + \(\dfrac{1}{5}\) - \(\dfrac{1}{9}\) + \(\dfrac{1}{9}\) - \(\dfrac{1}{13}\) + \(\dfrac{1}{13}\) - \(\dfrac{1}{17}\)) = 16
\(x\) \(\times\) ( \(\dfrac{1}{1}\) - \(\dfrac{1}{17}\)) = 16
\(x\) \(\times\) \(\dfrac{16}{17}\) = 16
\(x\) = 16 : \(\dfrac{16}{17}\)
\(x\) = 17
a,504:[16-3.x]=72
16-3.x=504:72
16-3.x=7
3.x =16-7
3.x =9
\(\Rightarrow x=3\)
b,272-[4.x+15] = 45
4.x+15 = 272-45
4.x+15 = 227
4.x = 227-15
4.x = 212
x = 212:4
\(\Rightarrow x=53\)
c,425-x:8 =91
x:8 =425-91
x:8 =334
x =334x8
\(\Rightarrow x=2672\)
d, 293-8.27+x.25=80
293-216 +x.25=80
77+x.25 =80
x.25 =3
\(\Rightarrow x=\frac{3}{25}\)
x = 3
x = 53
x = 2672
x = 3 / 25
ai thấy đúng thì ủng hộ mk nha
a) => x : 80 = 2
=> x = 160
b) => 200/15 : x = 3
=> x = 40/9
c) => 158 - x = 140
=> x = 18
d) => 231 - (x-6) = 103
=> x - 6 = 128
=> x = 134
\(a,\Rightarrow x=-8-3=-11\\ b,\Rightarrow35+x-12=27\\ \Rightarrow x=4\\ c,\Rightarrow2^x=16=2^4\Rightarrow x=4\)
272-[4xX+15]=45
[ 4 * x + 15 ] = 272 - 45
[ 4 * x + 15 ] = 227
4* x = 227 - 15
4*x = 212
x = 212 : 4
x = 53
272-[4.x+15]=45
[4.x+15]=272-45=227
4.x =227-15=212
x =212:4=53
Hok tốt!