tìm x,biết x=16
6+x-16
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
HT
3
MH
8 tháng 4 2022
200 - 18 : (372 : x - 1) - 28 = 166
200 - 18 : (372 : x - 1) = 166 + 28
200 - 18 : (372 : x - 1) = 194
18 : (372 : x - 1) = 200 - 194
18 : (372 : x - 1) = 6
372 : x - 1 = 18 : 6
372 : x - 1 = 3
372 : x = 3 + 1
372 : x = 4
x = 372 : 4
x = 93
8 tháng 4 2022
\(200-18:\left(272:x-1\right)-28=166\)
\(-18:\left(272:x-1\right)=-6\)
\(272:x-1=3\)
\(272:x=4\)
\(x=93\)
T
3
6 tháng 11 2015
76 ; 166 ; 46 chia x
=>x thuộc ƯC(76,46,166)
Ta có:
76=22.19
166=2.83
46=2.23
=>ƯCLN(76,166,46) = 22.19.23.83=145084
Mà 3<x<15 nên x = 4
Vậy x=4
18 tháng 6 2017
\(\frac{x-241}{17}+\frac{x-220}{19}+\frac{x-195}{21}+\frac{x-166}{23}=10\)
\(\Leftrightarrow\left(\frac{x-241}{17}-1\right)+\left(\frac{x-220}{19}-2\right)+\left(\frac{x-195}{21}-3\right)+\left(\frac{x-166}{23}-4\right)=0\)
\(\Leftrightarrow\frac{x-258}{17}+\frac{x-258}{19}+\frac{x-258}{21}+\frac{x-258}{23}=0\)
\(\Leftrightarrow\left(x-258\right)\left(\frac{1}{17}+\frac{1}{19}+\frac{1}{21}+\frac{1}{23}\right)=0\)
\(\Leftrightarrow x-258=0\)(vì \(\frac{1}{17}+\frac{1}{19}+\frac{1}{21}+\frac{1}{23}\ne0\))
\(\Leftrightarrow x=258\)
vậy phương trình có tập nghiệm là: S={258}
13 tháng 9 2023
d: ĐKXĐ: x<>-4; x<>-5; x<>-6; x<>-7
\(PT\Leftrightarrow\dfrac{1}{x+4}-\dfrac{1}{x+5}+\dfrac{1}{x+5}-\dfrac{1}{x+6}+\dfrac{1}{x+6}-\dfrac{1}{x+7}=\dfrac{1}{18}\)
=>\(\dfrac{1}{x+4}-\dfrac{1}{x+7}=\dfrac{1}{18}\)
=>\(\dfrac{x+7-x-4}{\left(x+4\right)\left(x+7\right)}=\dfrac{1}{18}\)
=>x^2+11x+28=54
=>x^2+11x-26=0
=>(x+13)(x-2)=0
=>x=2 hoặc x=-13
e: \(\dfrac{x-241}{17}+\dfrac{x-220}{19}+\dfrac{x-195}{21}+\dfrac{x-166}{23}=10\)
\(\Leftrightarrow\left(\dfrac{x-241}{17}-1\right)+\left(\dfrac{x-220}{19}-2\right)+\left(\dfrac{x-195}{21}-3\right)+\left(\dfrac{x-166}{23}-4\right)=0\)
=>x-258=0
=>x=258
CN
1
S
13 tháng 6 2019
\(x^2+y^2+z^2-6x-22y+12z+166=0\)
\(\Leftrightarrow x^2+y^2+z^2-6x-22y+12z+121+9+36=0\)
\(\Leftrightarrow\left(x^2-6x+9\right)+\left(y^2-22y+121\right)+\left(z^2+12z+36\right)=0\)
\(\Leftrightarrow\left(x-3\right)^2+\left(y-11\right)^2+\left(z+6\right)^2=0\)
\(\hept{\begin{cases}\left(x-3\right)^2\ge0\\\left(y-11\right)^2\ge0\\\left(z+6\right)^2\ge0\end{cases}}\Rightarrow\hept{\begin{cases}\left(x-3\right)^2=0\\\left(y-11\right)^2=0\\\left(z+6\right)^2=0\end{cases}}\Leftrightarrow\hept{\begin{cases}x-3=0\\y-11=0\\z+6=0\end{cases}}\Leftrightarrow\hept{\begin{cases}x=3\\y=11\\z=-6\end{cases}}\)
30 tháng 1 2023
\(\dfrac{x-241}{17}+\dfrac{x-220}{19}+\dfrac{x-195}{21}+\dfrac{x-166}{23}=10\)
\(\Leftrightarrow\dfrac{x-241}{17}+\dfrac{x-220}{19}+\dfrac{x-195}{21}+\dfrac{x-166}{23}-10=0\)
\(\Leftrightarrow(\dfrac{x-241}{17}-1)+(\dfrac{x-220}{19}-2)+(\dfrac{x-195}{21}-3)+(\dfrac{x-166}{23}-4)=0\)
\(\Leftrightarrow\dfrac{x-258}{17}+\dfrac{x-258}{19}+\dfrac{x-258}{21}+\dfrac{x-258}{23}=0\)
\(\Leftrightarrow\left(x-258\right)\left(\dfrac{1}{17}+\dfrac{1}{19}+\dfrac{1}{21}+\dfrac{1}{23}\right)=0\)
\(Do\) \(\left(\dfrac{1}{17}+\dfrac{1}{19}+\dfrac{1}{21}+\dfrac{1}{23}\right)\ne0\) \(nên\) \(để\) \(gt=0\)
\(\Leftrightarrow x-258=0\)
\(\Leftrightarrow x=258\)
\(Vậy...\)
LA
9
SH
2 tháng 5 2016
200 - 18 : ( 372 : 3 : X - 1 ) - 28 = 166
200 - 18 : ( 372 : 3 : X - 1 ) = 166 + 28
200 - 18 : ( 372 : 3 : X - 1 ) = 194
200 - 18 : ( 124 . X - 1 ) = 194
18 : ( 124 . X - 1 ) = 200 - 194
18 : ( 124 . X - 1 ) = 6
124 . X - 1 = 18 : 6
124 . X - 1 = 3
124 . X = 3 + 1
124 . X = 4
X = 4 : 124
X = 1/31.
2 tháng 5 2016
200-18:(372:3:x-1)-28=166
200-18:(372:3:x-1)=166+28
200-18:(372:3:x-1)=194
18:(372:3:x-1)=200-194
18:(372:3:x-1)=6
372:3:x-1=18:6
372:3:x-1=3
124:x-1=3
124:x=3+1
124:x=4
x=124:4
x=31
TH
2
OT
7 tháng 7 2016
200-18:(372:3.X-1)-28=166
200-18:(372:3.X-1) =166+28
200-18:(372:3.X-1) =194
200-18:(124.X-1) =194
18:(124.X-1) =200-194
18:(124.X-1) =6
124.X-1 =18:6
124.X-1 =3
124.X =3+1
124.X =4
X =4:124
X =1/31 .
13 tháng 12 2021
1. \(\text{6 + 2.(x - 19) = 16}.\)
\(\Leftrightarrow2.\left(x-19\right)=10.\)
\(\Leftrightarrow x-19=5.\)
\(\Leftrightarrow x=24.\)
Vậy \(x=24.\)
2. \(\text{(-240) : x – 16 = 64}.\)
\(\Leftrightarrow\left(-240\right):x=80.\)
\(\Leftrightarrow x=-3.\)
Vậy \(x=-3.\)
3. \(2x^3=16.\)
\(\Leftrightarrow x^3=8.\)
\(\Leftrightarrow x=2.\)
Vậy \(x=2.\)
TK
1
6+x-16
=6+16-16
=22-16
=6
6+x-16
=6+16-16
=22-16
=6
tick mik nha