Hoàn thành các PTPỨ:
1, Cl2 + Fe --->
2, FeCl2 + Cl2 --->
3, NaBr+ I2 --->
4, Cl2 + Ag --->
5, Br2 + Al --->
help meeeeeeeeee
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2) 2KMnO4 + 16HCl = 2KCl + 2MnCl2 + 5Cl2 + 8H2O
Cl2 + H2 = 2HCl ( điều kiện ánh sáng )
2HCl + Fe = FeCl2 + H2
FeCl2 + 2AgNO3 = 2AgCl + Fe(NO3)2
2AgCl = 2Ag + Cl2
Hoàn thành các phương trình phản ứng xảy ra (nếu có, ghi rõ điều kiện)
1) 3Cl2 + 2Fe →to->...2FeCl3........
2) 2Cl2 + 2H2O → .....4HCl + O2.......
3) Cl2 + 2NaOH → ....NaClO + NaCl + H20.....
4) Fe + .....2HCl..... → FeCl2 + ......H2.......
5) 3HCl + Fe(OH)3→......FeCl3 + 3H20.............
6) KCl + AgNO3→........AgCl + KNO3................
7) 2HCl + CaCO3 →.........CaCl2 + H2CO3..............
a)
\(16HCl+2KMnO_4\underrightarrow{^{to}}5Cl_2+8H_2O+2MnCl_2\)
\(3Cl_2+6KOH\underrightarrow{^{to}}3H_2O+5KCl+KClO_3\)
\(6HCl+KClO_3\rightarrow3Cl_2+3H_2O+KCl\)
\(3Cl_2+2Fe\rightarrow2FeCl_3\)
\(FeCl_3+3KOH\rightarrow Fe\left(OH\right)_3+3KCl\)
\(KCl+NaOH\rightarrow NaCl+KOH\)
2)
\(2H_2O+CaCl_2\underrightarrow{^{đpmn}}Ca\left(OH\right)_2+Cl_2+2H_2\)
\(Cl_2+H_2\underrightarrow{^{askt}}2HCl\)
\(2HCl+Fe\rightarrow FeCl_2+H_2\)
\(2FeCl_2+Cl_2\rightarrow2FeCl_3\)
\(3Ba\left(OH\right)_2+2FeCl_3\rightarrow3BaCl_2+2Fe\left(OH\right)_3\)
3)
\(4HCl+MnO_2\underrightarrow{^{to}}Cl_2+2H_2O+MnCl_2\)
\(Cl_2+2NaOH\rightarrow H_2O+NaCl+NaClO\)
\(H_2O+NaCl+CO_2\rightarrow NaHCO_3+HClO\)
4)
\(KClO_3+3MnO_2+6NaOH\rightarrow3H_2O+KCl+3Na_2MnO_4\)
\(KCl+AgNO_3\rightarrow AgCl+KNO_3\)
\(2AgCl\underrightarrow{^{nđp,as}}2Ag+Cl_2\)
\(3Cl_2+6KOH\underrightarrow{^{to}}H_2O+5KCl+KClO_3\)
5)
\(CaOCl_2+MnSO_4+2NaOH\rightarrow H_2O+MnO_2+Na_2SO_4+CaCl_2\)
\(2CaOCl_2+H_2O+CO_2\rightarrow CaCO_3+CaCl_2+2HClO\)
\(CaCO_3\underrightarrow{^{to}}CaO+CO_2\)
\(H_2O+NaClO+CO_2\rightarrow NaHCO_3+HClO\)
6)
\(MnO_2+4HBr\rightarrow Br_2+2H_2O+MnBr_2\)
\(Br_2+2HI\rightarrow I_2+2HBr\)
\(2Ag+I_2\rightarrow2AgI\)
1)
NaOH + hCl => NaCl + H2O
NaCl -dpnc-> Na + 1/2Cl2
Cl2 + Ca -to-> CaCl2
CaCl2 + Na2CO3 => CaCO3 + 2NaCl
NaCl + AgNO3 => AgCl + NaNO3
2)
Na + 1/2I2 -to-> NaI
2NaI + Cl2 => 2NaCl + I2
2NaCl + 2H2O -dpcmn-> 2NaOH + H2 + Cl2
H2 + Cl2 -as-> 2HCl
CaO + 2HCl => CaCl2 + H2O
CaCl2 + 2AgNO3 => Ca(NO3)2 + 2AgC;
3)
Fe + 2HCl => FeCl2 + H2
H2 + Cl2 -to-> 2HCl
CuO + 2HCl => CuCl2 + H2O
CuCl2 + Na2CO3 => CuCO3 + 2NaCl
NaCl -dpnc-> Na + 1/2Cl2
Cl2 + 2NaI => 2NaCl + I2
4)
2KMnO4 + 16HCl => 2KCl + 2MnCl2 + 5Cl2 + 8H2O
Na + 1/2Cl2 -to-> NaCl
NaCl -đpnc-> Na + 1/2Cl2
Cl2 + 2NaBr => 2NaCl + Br2
Br2 + 2NaI => 2NaBr + I2
5)
CaCO3 + 2HCl => CaCl2 + CO2 + H2O
Đáp án B
Fe+ 2HCl → FeCl2 + H2 (1)
2Fe + 3Cl2dư → 2FeCl3 (2)
2FeCl2 + Cl2 → 2FeCl3 (3)
Fe3O4 + 8HCl → FeCl2 + 2FeCl3 + 4H2O (4)
9Fe(NO3)2 + 12HCl→ 4FeCl3 + 5Fe(NO3)3 + 3NO + 6H2O (5)
FeCl2 + KI → không xảy ra phản ứng.
Đáp án B
Fe+ 2HCl → FeCl2 + H2 (1)
2Fe + 3Cl2dư → 2FeCl3 (2)
2FeCl2 + Cl2 → 2FeCl3 (3)
Fe3O4 + 8HCl → FeCl2 + 2FeCl3 + 4H2O (4)
9Fe(NO3)2 + 12HCl→ 4FeCl3 + 5Fe(NO3)3 + 3NO + 6H2O (5)
FeCl2 + KI → không xảy ra phản ứng.
1,
\(4HCl+MnO_2\rightarrow MnCl_2+2H_2O+Cl_2\\ 2Fe+3Cl_2\underrightarrow{t^o}2FeCl_3\\ FeCl_3+3NaOH\rightarrow Fe\left(OH\right)_3\downarrow+3NaCl\\ 2NaCl+H_2SO_4\rightarrow Na_2SO_4+2HCl\uparrow\\ CuO+2HCl\rightarrow CuCl_2+H_2O\\ CuCl_2+2AgNO_3\rightarrow2AgCl\downarrow+Cu\left(NO_3\right)_2\)
2,
\(2KMnO_4+16HCl\rightarrow2KCl+8H_2O+5Cl_2+2MnCl_2\\ Cl_2+H_2\underrightarrow{as}2HCl\\ 6HCl+Fe_2O_3\rightarrow2FeCl_3+3H_2O\\ FeCl_3+3AgNO_3\rightarrow3AgCl\downarrow+Fe\left(NO_3\right)_3\\ 2AgCl\underrightarrow{as}2Ag+Cl_2\\ Cl_2+2NaBr\rightarrow2NaCl+Br_2\\ Br_2+2NaI\rightarrow2NaBr+I_2\)
3,
2 pthh đầu giống ở 2
\(Fe+2HCl\rightarrow FeCl_2+H_2\\ FeCl_2+2AgNO_3\rightarrow2AgCl\downarrow+Fe\left(NO_3\right)_2\\ 2AgCl\underrightarrow{as}2Ag+Cl_2\)
4, 2 pthh đầu gióng ở 1
\(FeCl_3+3NaOH\rightarrow Fe\left(OH\right)_3\downarrow+3NaCl\\ 2Fe\left(OH\right)_3+3H_2SO_4\rightarrow Fe_2\left(SO_4\right)_3+6H_2O\)
\(Fe+S\underrightarrow{t^o}FeS\)
\(2Fe+3Cl_2\underrightarrow{t^o}2FeCl_3\)
\(2Cu+O_2\underrightarrow{t^o}2CuO\)
\(Mg+CuSO_4\rightarrow MgSO_4+Cu\downarrow\)
\(Ag+FeCl_2\rightarrow X\)
\(Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)
\(Mg+2HCl\rightarrow MgCl_2+H_2\uparrow\)
3Cl2 + 2Fe -> 2FeCl3
2FeCl2 + Cl2 -> 2FeCl3
NaBr + I2 -> NaBr + I2 (không phản ứng)
3Br2 + 2Al -> 2AlBr3
1:3Cl2+2Fe--->2FeCl3
2:2FeCl2+Cl2--->2FeCl3
3:NaBr+I2---> hình như ko có
4:2Ag+Cl2--->2AgCl kết tủa
5:3Br2+2Al--->2AlBr3