4×7/9×23
2×21/14×15
2×5×13/26×35
9×6-9×3/18
17×5-17/3-20
49+7×49/49
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1) 2763 +152 =2915
2) (-7) +(-14) = -21
3) (-35) + (-9) = -44
4) (-5) + (-248) = -253
5) (-23) + 105 = 82
6) 78 + (-123) = -45
7) 23 +(-13) = 10
8) (-23) +13 = -10
9) 26 + (-6) = 20
10) (-75) +50 = -25
11) 80 + (-220) = -140
12) (-23) + (-13) = -36
13) (-26) + (-6) = -32
14) (-75) + (-50) = -125
15) ❏-18❏ + (-12) = -17❏ -12
16)17 + ❏ - 33❏ = 17 -32❏
17) (-20) +❏ - 88❏ = -20 -87❏
18) ❏- 3❏+ ❏5❏ = ❏5❏ -2❏
19)❏-37❏+❏15❏ = ❏15❏ -36❏
20) ❏-37❏+(-❏15❏) = -❏15❏ - 36❏
21) (-❏-32❏) +❏5❏ = ❏5❏ -33❏
22) (-❏-22❏) + (-❏16❏) = -❏16❏ -23❏
23) (-23) +13 +(-17) +57 = 30
24) 14 +6 + (-9) + (-14) = -3
25) (-123 ) +❏-13❏+(-7) = -130-12❏
26) ❏0❏ + ❏45❏ +(-❏-455)❏+❏-796❏ = ❏45❏-❏\(^2\) -1250❏
1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30+31+32+33+34+35+36+37+38+39+40+41+42+43+44+45+46+47+48+49+50=1275
a) Ta có: \(\dfrac{-5}{7}\left(\dfrac{14}{5}-\dfrac{7}{10}\right):\left|-\dfrac{2}{3}\right|-\dfrac{3}{4}\left(\dfrac{8}{9}+\dfrac{16}{3}\right)+\dfrac{10}{3}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)\)
\(=\dfrac{-5}{7}\cdot\dfrac{3}{2}\cdot\dfrac{21}{10}-\dfrac{3}{4}\cdot\dfrac{56}{3}+\dfrac{10}{3}\cdot\dfrac{8}{15}\)
\(=\dfrac{-9}{4}-14+\dfrac{16}{9}\)
\(=\dfrac{-1621}{126}\)
b) Ta có: \(\dfrac{17}{-26}\cdot\left(\dfrac{1}{6}-\dfrac{5}{3}\right):\dfrac{17}{13}-\dfrac{20}{3}\left(\dfrac{2}{5}-\dfrac{1}{4}\right)+\dfrac{2}{3}\left(\dfrac{6}{5}-\dfrac{9}{2}\right)\)
\(=\dfrac{-17}{26}\cdot\dfrac{13}{17}\cdot\dfrac{-3}{2}-\dfrac{20}{3}\cdot\dfrac{3}{20}+\dfrac{2}{3}\cdot\dfrac{-33}{10}\)
\(=\dfrac{3}{4}-1-\dfrac{11}{5}\)
\(=-\dfrac{49}{20}\)
a: =35/17-18/17-9/5+4/5
=1-1=0
b: =-7/19(3/17+8/11-1)
=7/19*18/187=126/3553
c: =26/15-11/15-17/3-6/13
=1-6/13-17/3
=7/13-17/3=-200/39