y x 6/11+y x 5/11=2025
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\(Y\times6+11\times\dfrac{5}{11}=2025\\ Y\times6+5=2025\\ Y\times6=2025-5\\ Y\times6=2020\\ Y=\dfrac{2020}{6}\\ Y=\dfrac{1010}{3}\)
\(y\times6+11\times\dfrac{5}{11}=2025\\ y\times6+5=2025\\y\times6=2025-5\\ y\times6=2020\\ y=2020:6\\ y=\dfrac{1010}{3}\)
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\(y\times\dfrac{6}{11}+y\times\dfrac{5}{11}=2025\)
\(y\times\left(\dfrac{5}{11}+\dfrac{6}{11}\right)=2025\)
\(y\times1=2025\)
\(y=2025\)
\(y.\dfrac{6}{11}+y.\dfrac{5}{11}=2025\)
\(y.\left(\dfrac{6}{11}+\dfrac{5}{11}\right)=2025\)
\(y.\left(\dfrac{11}{11}\right)=2025\)
\(y=2025\)
Dấu . là dấu nhân
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Có `x/5=y/3;y/6=z/11`
`=>x/10=y/6;y/6=z/11`
`=>x/10=y/6=z/11`
Áp sụng t/c của `DTSBN , ta đc:
`x/10=y/6=z/11=(x+y-z)/(10+6-11)=80/5=16`
`=>x=160;y=96;z=176`
Có :
\(\dfrac{x}{5}=\dfrac{y}{3}\\\Leftrightarrow \dfrac{x}{10}=\dfrac{y}{6}\\ \dfrac{y}{6}=\dfrac{z}{11}\\ \Rightarrow\dfrac{x}{10}=\dfrac{y}{6}=\dfrac{z}{11}\)
Áp dụng tính chất dãy tỉ số bằng nhau :
x/10 = y/6 = z/11 = \(\dfrac{x+y-z}{10+6-11}=\dfrac{80}{5}=16\)
=> x = 10 x 16 =160
y = 6 x 16 =96
z = 11 x 16 =176
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2 x A = 1 - \(\dfrac{1}{2027}\)
\(A=\dfrac{1013}{2027}\)
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x/15 = y/20 = z/24 = 11/59
x = 11.15/59
y = 11.20/59
z = 11.24/59
( cái tui thích nhất môn toán là học phải suy nghĩ)
\(\frac{x}{3}=\frac{y}{4};\frac{y}{5}=\frac{z}{6}\)và\(y+z+x=11\)
\(\Rightarrow\frac{x}{15}=\frac{y}{20}=\frac{z}{24}\)
Áp dụng t/c của dãy tỉ số = nhau, ta có:
\(\frac{x}{15}=\frac{y}{20}=\frac{z}{24}=\frac{x+y+z}{15+20+24}=\frac{11}{59}\)
\(suy\)\(ra\)\(\frac{x}{15}=\frac{11}{59}\Rightarrow x=\frac{11.15}{59}=\frac{165}{59}\)
\(\frac{y}{20}=\frac{11}{59}\Rightarrow y=\frac{11.20}{59}=\frac{220}{59}\)
\(\frac{z}{24}=\frac{11}{59}\Rightarrow z=\frac{24.11}{59}=\frac{264}{59}\)
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\(\frac{6}{11}x=\frac{9}{2}y=\frac{18}{5}z\) va -x+y+z=-120
\(\left(\frac{6}{11}\right)x=\left(\frac{9}{2}\right)y\Rightarrow x=\left(\frac{9}{2}\right)\left(\frac{11}{6}\right)y=\left(\frac{33}{4}\right)y\)
\(\left(\frac{9}{2}\right)y=\left(\frac{18}{5}\right)z\Rightarrow z=\left(\frac{9}{2}\right)\left(\frac{5}{18}\right)y=\left(\frac{5}{4}\right)y\)
\(\Rightarrow-x+y+z=\left(\frac{-33}{4}\right)y+y+\left(\frac{5}{4}\right)y=-120\)
\(\Rightarrow-6y=-120\Rightarrow y=20;x=165;z=25\)
y= 2025 nhaaaaaaaaaaaaaaaaaaaaaaa