Question

[Phan An]

Phân tích đa thức thành nhân tử 

e)x^3−x^2+x+3

g)3x^3−4x^2+13x−4

h)6x^3+x^2+x+1

i)4x^3+6x^2+4x+1

Answer 1

[Lấp La Lấp Lánh]

e) \(=x^2\left(x+1\right)-2x\left(x+1\right)+3\left(x+1\right)=\left(x+1\right)\left(x^2-2x+3\right)\)

g) \(=x^2\left(3x-1\right)-x\left(3x-1\right)+4\left(3x-1\right)=\left(3x-1\right)\left(x^2-x+4\right)\)

h) \(=3x^2\left(2x+1\right)-x\left(2x+1\right)+\left(2x+1\right)=\left(2x+1\right)\left(3x^2-x+1\right)\)

i) \(=2x^2\left(2x+1\right)+2x\left(2x+1\right)+\left(2x+1\right)=\left(2x+1\right)\left(2x^2+2x+1\right)\) 

Answer 2

[Phan An]

ảm ơn nha