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28 tháng 11 2018

2x2+x-10=2x2+5x-4x-10=(2x2-4x)+(5x-10)=2x(x-2)+5(x-2)=2x+5)(x-2)

16 tháng 11 2023

\(x^{10}+x^2+1\)

\(=x^{10}-x^8+x^4+x^8-x^6+x^2+x^6-x^4+1\)

\(=x^4\left(x^6-x^4+1\right)+x^2\left(x^6-x^4+1\right)+\left(x^6-x^4+1\right)\)

\(=\left(x^6-x^4+1\right)\left(x^4+x^2+1\right)\)

\(=\left(x^6-x^4+1\right)\left[x^4+2x^2+1-x^2\right]\)

\(=\left(x^6-x^4+1\right)\left[\left(x^2+1\right)^2-x^2\right]\)

\(=\left(x^6-x^4+1\right)\left(x^2+1+x\right)\left(x^2+1-x\right)\)

\(=\left(x+2\right)\left(x+5\right)\)

`#040911`

`x^2 - 3x - 10`

`= x^2 + 2x - 5x - 10`

`= (x^2 + 2x) - (5x + 10)`

`= x(x + 2) - 5(x + 2)`

`= (x - 5)(x + 2)`

22 tháng 8 2023

Kq = ( x - 5 ) ( x + 2 )

21 tháng 8 2016

thiếu đề đúng k?

ta có: x^10 + x^5 + 1 
= x^10 + x^9 - x^9 + x^8 - x^8 + x^7 - x^7 + x^6 - x^6 + x^5 + x^5 - x^5 + x^4 - x^4 + x^3 - x^3 + x^2 - x^2 + x - x + 1 
= (x^10 + x^9 + x^8) - (x^9 + x^8 + x^7) + (x^7 + x^6 + x^5) - (x^6 + x^5 + x^4) + (x^5 + x^4 + x^3) - (x^3 + x^2 + x) + (x^2 + x + 1) 
= x^8 (x^2 + x + 1) - x^7 (x^2 + x + 1) + x^5 (x^2 + x + 1) - x^4 (x^2 + x + 1) + x^3 (x^2 + x + 1) - x (x^2 + x + 1) + (x^2 + x + 1) 
= (x^2 + x + 1) (x^8 - x^7 + x^5 - x^4 + x^3 - x + 1) 

hì chả bít sao ^^ !!!! 454345645767587634536346623354546456577687687687698797856756756

\(x+7\sqrt{x}+10=\left(\sqrt{x}+2\right)\left(\sqrt{x}+5\right)\)

30 tháng 10 2015

Kết quả : (x + 8)(x + 2)(x2 + 10x + 8)

30 tháng 10 2015

\(x\left(x+4\right)\left(x+6\right)\left(x+10\right)+128\)

\(=x\left(x+10\right)\left(x+4\right)\left(x+6\right)+128\)

\(=\left(x^2+10x\right)\left(x^2+10x+24\right)+128\)

\(=\left(x^2+10x\right)^2+24\left(x^2+10x\right)+128\)

\(=\left(x^2+10x\right)^2+2.\left(x^2+10x\right).12+12^2-16\)

\(=\left(x^2+10x+12\right)^2-4^2\)

\(=\left(x^2+10x+12-4\right) \left(x^2+10x +12+4\right)\)

\(=\left(x^2+10x-8\right)\left(x^2+10x+16\right)\)

\(=\left(x^2+10x-8\right)\left(x^2+2x+8x+16\right)\)

\(=\left(x^2+10x-8\right)\left[x\left(x+2\right)+8\left(x+2\right)\right]\)

\(=\left(x^2+10x-8\right)\left(x+2\right)\left(x+8\right)\)

26 tháng 6 2016

\(A=\left(x-2\right)\left(x+2\right)\left(x^2-10\right)-72=\left(x^2-4\right)\left(x^2-10\right)-72=x^4-14x^2+40-72\)

\(A=x^4-14x^2-32=x^4+2x^2-16x^2-32=x^2\left(x^2+2\right)-16\left(x^2+2\right)\)

\(A=\left(x^2+2\right)\left(x^2-16\right)=\left(x-4\right)\left(x+4\right)\left(x^2+2\right)\)

2 tháng 9 2023

a) \(x^2-x-12\)

\(=x^2-4x+3x-12\)

\(=\left(x^2-4x\right)+\left(3x-12\right)\)

\(=x\left(x-4\right)+3\left(x-4\right)\)

\(=\left(x+3\right)\left(x-4\right)\)

b) \(x^2-5x-24\)

\(=x^2-8x+3x-24\)

\(=\left(x^2-8x\right)+\left(3x-24\right)\)

\(=x\left(x-8\right)+3\left(x-8\right)\)

\(=\left(x+3\right)\left(x-8\right)\)

c) \(3x^2+13x-10\)

\(=3x^2+15x-2x-10\)

\(=\left(3x^2+15x\right)-\left(2x+10\right)\)

\(=3x\left(x+5\right)-2\left(x+5\right)\)

\(=\left(3x-2\right)\left(x+5\right)\)

a: =x^2-4x+3x-12

=x(x-4)+3(x-4)

=(x-4)(x+3)

b: =x^2-8x+3x-24

=x(x-8)+3(x-8)

=(x-8)(x+3)

c: =3x^2+15x-2x-10

=3x(x+5)-2(x+5)

=(x+5)(3x-2)