(52 + 53)x + (52 - 32)x - 40 = 102
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a) 5.22 + (x + 3) = 52
5.4 + (x + 3) = 25
20 + (x + 3) = 25
x + 3 = 25 – 20
x + 3 = 5
x = 5 – 3 = 2
b) 23 + (x – 32) = 53 - 43
8 + (x – 9) = 125 – 64
8 + (x – 9) = 61
x – 9 = 61 – 8
x – 9 = 53
x = 53 + 9 = 62
a) \(5.2^2+\left(x+3\right)=5^2\)
\(x+3=5^2-5.2^2\)
\(x+3=25-20\)
\(x+3=5\)
\(x=2\)
b) \(2^3+\left(x-3^2\right)=5^3-4^3\)
\(8+\left(x-9\right)=125-64\)
\(x-9=53\)
\(x=62\)
a, 10 x + 2 2 . 5 = 10 2
10x = 100–20
10x = 80
x = 8
b, 5 2 + 15 - x = 30
15–x = 5
x = 10
c, 2 2 . 5 2 - 25 + x = 40
100–(25+x) = 40
25+x = 60
x = 35
d, 7 2 x - 6 2 x = 13 . 2 3 - 26
49x–36x = 104–26
13x = 78
x = 6
<=> 52 * x - 156 = 159
<=> 52 * x = 159 + 156
<=> 52 * x = 315
=> x = 315 : 52
=> x = .....................Tự tính
52(x-3)=53*3
x-3=53*3/52= 3.0.....
Bạn ghi đề sai ak? Nếu tính ra thì số lớn lắm
\(3.2+\left(x+5^2\right)=10^2\)
\(6+\left(x+25\right)=100\)
\(x+25=100-6=94\)
\(x=94-25=69\)
`#3107`
`52(9 - x) = 52?`
`=> 9 - x = 52 \div 52`
`=> 9 - x = 1`
`=> x = 9 - 1`
`=> x = 8`
Vậy, `x = 8.`
\(A=1^2+2^2+3^2+....+10^2\\ A=1^{ }+\left(1+1\right)\cdot2+3\cdot\left(2+1\right)+.....+10\cdot\left(9+1\right)\\ A=1+2\cdot1+2+3\cdot2+3+....+10\cdot9+10\\ A=\left(1+2+3...+10\right)+\left(1\cdot2+3\cdot2+.....+10\cdot9\right)\)
Gọi 1+2+3+...+10 là P
Số số hạng là: (10 - 1) : 1 +1 = 10 (số)
P = (10+1) . 10 : 2 = 55
P = 55
Gọi \(1\cdot2+2\cdot3+....+9\cdot10\) là C
\(C=1\cdot2+2\cdot3+....+9\cdot10\\ 3\cdot C=1\cdot2\cdot3+2\cdot3\cdot3+....+9\cdot10\cdot3\\ 3\cdot C=1\cdot2\cdot3+2\cdot3\cdot\left(4-1\right)+....+9\cdot10\cdot\left(11-8\right)\\ 3\cdot C=1\cdot2\cdot3+2\cdot3\cdot4-1\cdot2\cdot3+.....+9\cdot10\cdot11-8\cdot9\cdot10\\ 3\cdot C=9\cdot10\cdot11\\ 3\cdot C=990\\ C=330\)
\(=>A=P+C\\ =>A=55+330\\ A=385\)
b)
\(B=5^2+10^2+15^2+...+50^2\\ B=5^2+\left(2\cdot5\right)^2+\left(3\cdot5\right)^2+....+\left(5\cdot10\right)^2\\ B=5^2+2^2\cdot5^2+3^2\cdot5^2+...+5^2\cdot10^2\\ B=5^2\cdot\left(1+2^2+3^2+....+10^2\right)\\ B=25\cdot\left(1+2^2+3^2+....+10^2\right)\)
\(\left(1+2^2+3^2+....+10^2\right)=A\)
\(=>B=25\cdot A\\ B=25\cdot385\\ B=9625\)
\(B=3+3^2+3^3+3^4+...+3^{2009}+3^{2010}\)
\(=\left(3+3^2\right)+\left(3^3+3^4\right)+...+\left(3^{2009}+3^{2010}\right)\)
\(=3\left(1+3\right)+3^3\left(1+3\right)+...+3^{2009}\left(1+3\right)\)
\(=4.\left(3+3^3+...+3^{2009}\right)\)
⇒ \(B\) ⋮ 4
b: \(C=5\left(1+5+5^2\right)+...+5^{2008}\left(1+5+5^2\right)=31\cdot\left(5+...+5^{2008}\right)⋮31\)
(36 + 52) x 46 + (36 + 52) x 53 + 88
= 88 x 46 + 88 x 141
= 4048 + 12408
= 16456