tìm x
a) ( 152\(\frac{2}{4}\)-148\(\frac{3}{8}\)) : 0,2 = X : 0,3
b) ( (6\(\frac{3}{5}\)-3\(\frac{3}{14}\)) -2,5 ) : ( 21-1,25) = X : 5\(\frac{5}{6}\)
c) (4-\(\frac{3}{4}\)) : ( 2\(\frac{1}{3}\)-1\(\frac{1}{9}\)) = 31. X : ( 45\(\frac{-10}{63}\)-44\(\frac{25}{84}\))
d) \(\frac{2.X+3}{5.X+2}\)=\(\frac{3.X-4}{7}\)
e) \(\frac{3.X-1}{40-5.X}\)=\(\frac{25-3.X}{5.X-34}\)