1×1
1×2
1×2
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\(\dfrac{21}{4}\cdot\dfrac{-11}{4}+\dfrac{21}{4}\cdot\dfrac{1}{2}+\dfrac{21}{4}\cdot\dfrac{-1}{2}\)
\(=\dfrac{21}{4}\cdot\dfrac{-11}{4}\cdot\dfrac{21}{4}+\dfrac{2}{4}+\dfrac{21}{4}\cdot\dfrac{-2}{4}\)
\(=\dfrac{21}{4}\cdot\left(\dfrac{-11}{4}+\dfrac{2}{4}+\dfrac{-2}{4}\right)\)
\(=\dfrac{21}{4}\cdot\dfrac{-11}{4}\)
\(=\dfrac{-231}{16}\)
\(-\dfrac{3}{17}+\left(\dfrac{2}{3}+\dfrac{3}{17}\right)=\dfrac{-3}{17}+\dfrac{3}{17}+\dfrac{2}{3}=\dfrac{2}{3}\)
\(\dfrac{-5}{21}+\dfrac{-16}{21}+1=-1+1=0\)
\(\dfrac{-4}{11}\cdot\dfrac{5}{15}\cdot\dfrac{11}{-4}=\dfrac{5}{15}=\dfrac{1}{3}\)
a: \(=\dfrac{3}{22}\cdot22\cdot\dfrac{3}{11}=3\cdot\dfrac{3}{11}=\dfrac{9}{11}\)
b: \(=\dfrac{5}{6}\cdot\dfrac{2}{5}=\dfrac{1}{3}\)
c: =17/21(3/5+2/5)=17/21
(10 - 1 \(\dfrac{1}{6}\) x \(\dfrac{6}{7}\)) : ( 21: \(\dfrac{11}{2}\) + 5\(\dfrac{2}{11}\) )
( 10 \(\dfrac{7}{6}\) x \(\dfrac{6}{7}\) ) : ( 21 : \(\dfrac{11}{2}\) + \(\dfrac{57}{11}\) )
(10 - 1) : ( \(\dfrac{42}{11}\) + \(\dfrac{57}{11}\) )
= 9 : 9
= 1
=> đáp án : 1
=(10 - 1 1/6 x 6/7) : ( 21: 11/2 + 5 2/11)
=( 10 7/6 x 6/7 ) : ( 21 : 11/2 + 57/11)
=(10 - 1) : ( 42/11 + 57/11 )
= 9 : 9
=1
=(10 - 1 1/6 x 6/7) : ( 21: 11/2 + 5 2/11)
=( 10 7/6 x 6/7 ) : ( 21 : 11/2 + 57/11)
=(10 - 1) : ( 42/11 + 57/11 )
= 9 : 9
=1
=(10 - 1 1/6 x 6/7) : ( 21: 11/2 + 5 2/11)
=( 10 7/6 x 6/7 ) : ( 21 : 11/2 + 57/11)
=(10 - 1) : ( 42/11 + 57/11 )
= 9 : 9
=1
52/1*6 + 52/6*11 + 52/11*16 + 52/16*21 + 52/21*26 + 52/26*31
=5(1-1/6+1/6-1/11+1/11-...+1/26-1/31)
=5(1-1/31)
=5.30/31
=150/31
52/1 x 6 + 52/6 x 11 + 52/11 x 16 + 52/16 x 21 + 52/21 x 26 + 52/26 x 31
= 5.(5/1.6 + 5/6.11 + 5/11.16 + 5/16.21 + 5/21.26 + 5/26.31)
= 5.(1 - 1/6 + 1/6 - 1/11 + 1/11 - 1/16 + 1/16 - 1/21 + 1/21 - 1/26 + 1/26 - 1/31)
= 5.(1 - 1/31)
= 5.30/31
= 150/31
1
2
2
Kb nhé
1x1=1
1x2=2
1x2=2
Chúc bạn học tốt nhé !