42015 : ( 42013 + 3 . 42013)
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\(\Rightarrow10+2x=4^2=16\\ \Rightarrow2x=6\Rightarrow x=3\)
\(\Rightarrow10+2x=\dfrac{4^{2013}}{4^{2011}}=4^2=16\)
\(\Rightarrow2x=6\Rightarrow x=3\)
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a) \(58+7x=100\)
\(=>7x=100-58\)
\(=>7x=42\)
\(=>x=42:7\)
\(=>x=6\)
b) \(3x-7=28\)
\(=>3x=28+7\)
\(=>3x=35\)
\(=>x=35:3\)
\(=>x=\dfrac{35}{3}\)
c) \(x-56:4=16\)
\(=>x-14=16\)
\(=>x=16+14\)
\(=>x=30\)
d) \(101+\left(36-4x\right)=105\)
\(=>36-4x=105-101\)
\(=>36-4x=4\)
\(=>4x=36-4\)
\(=>4x=32\)
\(=>x=32:4\)
\(=>x=8\)
e) \(\left(x-12\right):12=12\)
\(=>x-12=12.12\)
\(=>x-12=144\)
\(=>x=144-12\)
\(=>x=132\)
f) \(\left(3x-2^4\right).7^3=2.7^4\)
\(=>3x-2^4=2.7^4:7^3\)
\(=>3x-16=2.7=14\)
\(=>3x=14+16\)
\(=>3x=30\)
\(=>x=30:3\)
\(=>x=10\)
i) \(\left(10+2x\right).4^{2011}=4^{2013}\)
\(=>10+2x=4^{2013}:4^{2011}\)
\(=>10+2x=4^2=16\)
\(=>2x=16-10\)
\(=>2x=6\)
\(=>x=6:2\)
\(=>x=3\)
\(#WendyDang\)
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Bài 1:
Ta có: \(3n+1⋮n-1\)
\(\Leftrightarrow3n-3+4⋮n-1\)
mà \(3n-3⋮n-1\)
nên \(4⋮n-1\)
\(\Leftrightarrow n-1\inƯ\left(4\right)\)
\(\Leftrightarrow n-1\in\left\{1;-1;2;-2;4;-4\right\}\)
hay \(n\in\left\{2;0;3;-1;5;-3\right\}\)(tm)
Vậy: \(n\in\left\{2;0;3;-1;5;-3\right\}\)
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đây có phải cậu đạt câu hỏi thật ko
nếu chơi thì k mk nha
=3
=))))))))))))))))
1 + 1 = 2
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3+3+3+3+3+3+3+3+3+3+3+3+3+3+3+3+123456789+987654321=1111111152
=4^2015:[4^2013.(3+1)]
=4^2015:(4^2013.4)
=4^2015:4^2014
=4
k cho mk nha mk đang -16
42015 : ( 42013 + 3 . 42013 )
= 42015 : [ 42013 . ( 3 + 1 ) ]
= 42015 : [ 42013 . 4 ]
= 42015 : 42014
= 4
hok tốt