(x*4+5) + (x*2+x) =110
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c, (2\(\times\) \(x\) - 3) \(\times\) 5 = 4
2 \(\times\) \(x\) - 3 = \(\dfrac{4}{5}\)
2 \(\times\) \(x\) = 0,8 + 3
2\(x\) = 3,8
\(x\) = \(3,8\) : 2
\(x\) = 1,9
d, 1 + 3 + 5 +....+\(x\) = 36
(\(x\) + 1)\(\times\) \(x\): 2 = 36
(\(x+1\)) \(\times\)\(x\) = 72
(\(x+1\))\(\times\)\(x\) = 8 x 9
\(x\) = 8
a) (X - 5) x 4 = 36
⇒ X - 5 = 36 : 4
⇒ X - 5 = 9
⇒ X = 9 + 5
⇒ X = 14
Vậy X = 14
b) (48 - X) x 2 = 14
⇒ 48 - X = 14 : 2
⇒ 48 - X = 7
⇒ X = 48 - 7
⇒ X = 41
Vậy X = 41
a: \(\Leftrightarrow\left(\dfrac{x+2001}{5}+1\right)+\left(\dfrac{x+1999}{7}+1\right)+\left(\dfrac{x+1997}{9}+1\right)+\left(\dfrac{x+1995}{11}+1\right)=0\)
=>x+2006=0
=>x=-2006
b: \(\Leftrightarrow\left(\dfrac{x-15}{100}-1\right)+\left(\dfrac{x-10}{105}-1\right)+\left(\dfrac{x-100}{5}-1\right)=\left(\dfrac{x-100}{15}-1\right)+\left(\dfrac{x-105}{10}-1\right)+\left(\dfrac{x-110}{5}-1\right)\)
=>x-105=0
=>x=105
\(2x+\left(1+2+3+...+100\right)=15150\)
\(2x+\left[\left(1+100\right)+\left(2+99\right)+...+\left(50+51\right)\right]=15150\)
\(2x+\left[101+101+...+101\right]=15150\)CÓ 50 SỐ 101
\(2x+\left[101\times50\right]=15150\)
\(2x=15150:5050\)
\(2x=3\)
\(x=3:2\)
\(x=1.5\)
a, 2x + (1+2+3+4+...+100) = 15150
=> 2x + \(\frac{\left(1+100\right).\left[\left(100-1\right)+1\right]}{2}\)= 15150
=> 2x + \(\frac{101.100}{2}\)= 15150
=> 2x + 5050 = 15150
=> 2x = 15150 - 5050
=> 2x = 10100
=> x = 10100 : 2
=> x = 5050
Vậy x = 5050
b, .(x+1)+(x+2)+(x+3)+(x+4)+(x+5)+(x+6)+(x+7)+(x+8)=36
=> (x + x + x + x +x + x +x +x ) + (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8) = 36
=> 8x + 36 = 36
=> 8x = 0
=> x = 0
Vậy x = 0
c, 0+0+4+6+8+...+2x=110
Sửa đề :0 + 2 + 4 + 6 + 8 + ... + 2x = 110 = 2 + 4 + 6 + 8 + ... + 2x = 110
SSH : \(\frac{\left(2\text{x}-2\right)}{2}+1=x-1+1=x\)
Tổng : \(\frac{\left(2\text{x}+2\right).x}{2}=110\Leftrightarrow\frac{2.\left(x+1\right).x}{2}=110\)
\(\Leftrightarrow\left(x+1\right)x=110\)
\(\Leftrightarrow\left(10+1\right).10=110\)
=> x = 10
Vậy x = 10
câu a) <=> 2x+10+28=20-3x-12
<=>5x=--30
<=>x=-6(TM)
câu b) chị ko bit em học hằng đt chưa nên để người khác giải nha ^^
a: x-56:4=16
nên x-14=16
hay x=30
b: \(101+\left(36-4x\right)=105\)
\(\Leftrightarrow36-4x=4\)
hay x=8
Vì a: x-56:4=16
=>x-14=16
Hay:x=30
Vì b: 101+(36−4x)=105101+(36−4x)=105
⇔36−4x=4⇔36−4x=4
Hay:x=8
Vậy x={30:8}
Nếu sai thì thui nhá,đừng chửi mình!
\(x^2+y^2=\left(x+y\right)^2-2xy=25-2xy\)
\(x^4+y^4=\left(x^2+y^2\right)^2-2x^2y^2=\left(25-2xy\right)^2-2x^2y^2\)
\(\Rightarrow x^4+y^4=2x^2y^2-100xy+625\)
Thay vào ta được:
\(2x^2y^2-100xy+625+25-2xy=110\)
\(\Leftrightarrow2x^2y^2-102xy+540=0\Rightarrow\left[{}\begin{matrix}xy=45>\frac{\left(x+y\right)^2}{4}\left(l\right)\\xy=5\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x+y=5\\xy=6\end{matrix}\right.\) \(\Rightarrow\left(x;y\right)=\left(2;3\right);\left(3;2\right)\)
\(\Rightarrow P=2^5+3^5=275\)
(x.4 + 5) + (x.2 + x) = 110
=> x . 4 + 5 + x(2 + 1) = 110
=> x . 4 + 5 + 3x = 110
=> (4 + 3)x + 5 = 110
=> 7x = 110 - 5
=> 7x = 105
=> x = 15
x*6+x+5=110
x*7=110-5=105
x=105/7=15