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a.120-[7.20-(134-110).5]
=120-(7.20-24.5)
=120-(140-120)
=120-20
=100
b.1987-200.8+1005:5
=1987-1600+201
=588
C, 387.2694+7305.387+387
=387.(2694+7305+1)
=387.10000
3870 000
d,
d.248:{[(368+232):120-3]+122}+2016
=248:{(600:120-3)+122}+2016
=248:(2+122)+2016
=248:144+2016
=2+2016
=2018
a)120-[7.20-(134-110).5]
=120-20
=100
b)1987-200.8+1005:5
=1987-1600+201
=588
c)387.2694+7305.387+387
=1042578+2827035+387
=3870000
d)248:{[368+232):120-3]+122}+2016
=248:124+2016
=2+2016
=2018
a)120-[7.20-(134-110).5]
=120-20
=100
b)1987-200.8+1005:5
=1987-1600+201
=588
c)387.2694+7305.387+387
=1042578+2827035+387
=3870000
d)248:{[368+232):120-3]+122}+2016
=248:124+2016
=2+2016
=2018
120 - [7 . 20 - (134 - 110) . 5]
= 120 - [140 - 24 . 5]
= 120 - (140 - 120)
= 120 - 20
= 100
\(120-\left[7.20-\left(134-110\right).5\right]\)
\(=120-\left[140-24.5\right]\)
\(=120-\left[140-120\right]\)
\(=120-20\)
\(=100\)
_Chúc bạn học tốt_
Ta có: \(\sin {70^o} = \cos {20^o};\;\cos {110^o} = - \cos {70^o} = - \sin {20^o}\)
\(\begin{array}{l} \Rightarrow A = {(\sin {20^o} + \cos {20^o})^2} + {(\cos {20^o} - \sin {20^o})^2}\\ = ({\sin ^2}{20^o} + {\cos ^2}{20^o} + 2\sin {20^o}\cos {20^o}) + ({\cos ^2}{20^o} + {\sin ^2}{20^o} - 2\sin {20^o}\cos {20^o})\\ = 2({\sin ^2}{20^o} + {\cos ^2}{20^o})\\ = 2\end{array}\)
Ta có: \(\tan {110^o} = - \tan {70^o} = - \cot {20^o};\;\cot {110^o} = - \cot {70^o} = - \tan {20^o}.\)
\( \Rightarrow B = \tan {20^o} + \cot {20^o} + ( - \cot {20^o}) + ( - \tan {20^o}) = 0\)
=2/10+3/10+4/10+......+13/10
=\(\frac{2+3+4+......+13}{10}\)
=90/10=9
k cho mình nha
a) 120 - 20 : x = 110
20:x= 120 - 110
20:x= 10
x= 20:10=2
b) 213 - ( x - 13 ) = 1442 : 14
213 - (x-13)=103
x-13= 213 - 103
x-13=110
x=110+13
x=123
c) 2550 : [ 120 - ( x - 5 ) ] = 25
120 - (x-5) = 2550:25
120 - (x-5)=102
x-5 = 120 - 102
x-5= 18
x=18+5
x=23
Câu 1:
Thay \(x=-12\) vào \(\left|x-2\right|\)
\(\Rightarrow\left|-12-2\right|=\left|-14\right|=14\)
Câu 2: Chọn phương án A.
Câu 3:
\(\left|-120\right|+\left|20\right|=120+20=140\)
A)\(\dfrac{7}{20}-\left(\dfrac{5}{8}-\dfrac{2}{5}\right)\)
\(=\dfrac{7}{20}-\left(\dfrac{25}{40}-\dfrac{16}{40}\right)\)
\(=\dfrac{7}{20}-\dfrac{9}{40}\)
\(=\dfrac{14}{40}-\dfrac{9}{40}=\dfrac{5}{40}=\dfrac{1}{8}\)
B) \(\dfrac{5}{6}+\left(\dfrac{5}{9}-\dfrac{1}{4}\right)\)
\(=\dfrac{5}{6}+\left(\dfrac{20}{36}-\dfrac{9}{36}\right)\)
\(=\dfrac{5}{6}+\dfrac{11}{36}\).
\(=\dfrac{30}{36}+\dfrac{11}{36}=\dfrac{41}{36}\)
C) \(\dfrac{9}{10}-\left(\dfrac{2}{5}-\dfrac{3}{10}\right)+\dfrac{7}{20}\)
\(=\dfrac{9}{10}-\left(\dfrac{4}{10}-\dfrac{3}{10}\right)+\dfrac{7}{20}\)
\(=\dfrac{9}{10}-\dfrac{1}{10}+\dfrac{7}{20}\)
\(=\dfrac{18}{20}-\dfrac{2}{20}+\dfrac{7}{20}=\dfrac{23}{20}\)
a: =7/20-5/8+2/5
=14/40-25/40+16/40
=5/40=1/8
b: =5/6+5/9-1/4
=30/36+20/36-9/36
=41/36
c: =9/10-2/5+3/10+7/20
=12/10-2/5+7/20
=7/20+6/5-2/5
=7/20+4/5
=7/20+16/20
=23/20
120 - 7 x 20 - ( 134 - 110 ) x 5
= 120 - 7 x 20 - 24 x 5
= 120 - 140 - 120
= 120 - 20
= 100
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