Tính
\(\frac{12.3^{11}+5.3^{12}}{9^7}\)
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a: \(=\dfrac{2^4\cdot3^6\cdot2\cdot3}{2^4\cdot3^6}=6\)
b: \(=\dfrac{2^{20}\cdot3^{20}}{2^{18}\cdot3^{18}}=2^2\cdot3^2=36\)
c: \(=\dfrac{12^5\cdot13}{12^6\cdot13}-\dfrac{12^8\cdot\left(-11\right)}{12^9\cdot\left(-11\right)}=\dfrac{1}{12}-\dfrac{1}{12}=0\)
a )( 2/5+2/9-2/11)/(8/5+8/9-8/11)=2*(1/5+1/9-1/11)/8*(1/5+1/9-1/11)=2/8=1/4
Câu 1 xem kỉ đề
\(B,\frac{49^6.5-7^{11}}{\left(-7\right)^{10}.5-2.49^5}=\frac{7^{12}.5-7^{11}}{7^{10}.5-2.7^{10}}=\frac{7^{11}.\left(7.5-1\right)}{7^{10}.\left(5-2\right)}=\frac{7.34}{3}=\frac{238}{3}\)
a) A=212.35-\(\frac{2^{12}.3^6}{2^{12}}\)+93+84.35
=212.35-36+36+212.35
=213.35
b)B=496.5-5.\(\frac{7^{11}}{\left(-7\right)^{10}}-2.49^5\)
=496.5-7.5-2.495
=712.5-7.5-2.710
\(\frac{12.3^{11}+5.3^{12}}{9^7}\)
\(=\frac{3.4.3^{11}+5.3^{12}}{\left(3^2\right)^7}\)
\(=\frac{3^{12}.4+5.3^{12}}{3^{14}}\)
\(=\frac{3^{12}\left(4+5\right)}{3^{14}}=\frac{9}{9}=1\)
\(\frac{12.3^{11}+5.3^{12}}{9^7}\)
\(=\frac{4.3.3^{11}+5.3^{12}}{\left(3^2\right)^7}\)
\(=\frac{4.3^{12}+5.3^{12}}{3^{14}}\)
\(=\frac{\left(4+5\right).3^{12}}{3^{14}}\)
\(=\frac{9.1}{3^2}=1\)