?CuO + HCl ➜ CuCl2
Al2(SO4)3 + ?BaCl2 ➜ ?AlCl3 + ?
?Al(OH)3 ➜ Al2O3 + ?
K
Khách
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GN
GV Nguyễn Trần Thành Đạt
Giáo viên
13 tháng 12 2023
\(a,2Al_2O_3\rightarrow\left(đpnc,criolit\right)4Al+3O_2\\ 2Al+6HCl\rightarrow2AlCl_3+3H_2\\ AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\\ 2Al\left(OH\right)_3\rightarrow\left(t^o\right)Al_2O_3+3H_2O\\ Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)
GN
GV Nguyễn Trần Thành Đạt
Giáo viên
13 tháng 12 2023
\(b,2Cu+O_2\rightarrow\left(t^o\right)2CuO\\ CuO+2HCl\rightarrow CuCl_2+H_2O\\ CuCl_2+2KOH\rightarrow Cu\left(OH\right)_2+2KCl\\ Cu\left(OH\right)_2\rightarrow\left(t^o\right)CuO+H_2O\)
24 tháng 12 2021
a: \(Cu+H_2SO_4->CuSO_4+H_2\)
\(CuSO_4+BaCl_2->CuCl_2+BaSO_4\)
\(2CuCl_2+O_2->2CuO+2Cl_2\)
HH
3
29 tháng 12 2020
4Al+3O2----to--->2Al2O3
Al2O3 +3H2SO4----->Al2(SO4)3+3H2O
Al2(SO4)3+3BaCl2------>2AlCl3+3BaSO4
2AlCl3+3Ca(OH)2---->2Al(OH)3+3CaCl2
Al(OH)3+3HNO3---->Al(NO3)3+3H2O
2Al(NO3)3+3Mg----->3Mg(NO3)2+2Al
2Al+3H2SO4------->Al2(SO4)3+3H2
Al2(SO4)3+3Ca(OH)2------>2Al(OH)3+3CaSO4
2Al(OH)3-----to----->Al2O3+3H2O
2Al2O3----\(\dfrac{t^o}{criolit}\)---->4Al+3O2
2Al+2H2O+2NaOH------>2NaAlO2+3H2
K
29 tháng 12 2020
4Al+3O2\(\underrightarrow{t^o}\) 2Al2O3
Al2O3+H2SO4 —> Al2(SO4)3+3H2O
Al2(SO4)3+3BaCl2–>3BaSO4\(\downarrow\)+2AlCl3
AlCl3+3NaOH—>Al(OH)3\(\downarrow\)+3NaCl
Al(OH)3+HNO3 —>Al(NO3)3+NO2\(\uparrow\)+H2O
2Al(NO3)3+3Mg—>3Mg(NO3)2+2Al\(\downarrow\)
2Al+3H2SO4–>Al2(SO4)3+3H2\(\uparrow\)
Al2(SO4)3+6NaOH—>2Al(OH)3+3Na2SO4
2Al(OH)3\(\underrightarrow{t^o}\)Al2O3+3H2O
2Al2O3\(\xrightarrow[criolit]{đien.phan.nong.chay}\)
4Al+3O2
2Al+2NaOH+2H2O—>2NaAlO2+3H2
HL
0
NN
2
18 tháng 12 2023
\(2Al+6HCl\rightarrow2AlCl_3+3H_2\)
\(AlCl_3+3NaOH\rightarrow3NaCl+Al\left(OH\right)_3\)
\(2Al\left(OH\right)_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+6H_2O\)
\(Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow2AlCl_3+3BaSO_4\)
\(AlCl_3+3AgNO_3\rightarrow3AgCl+Al\left(NO_3\right)_3\)
\(Al\left(NO_3\right)_3+3KOH\rightarrow3KNO_3+Al\left(OH\right)_3\)
\(2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\)
\(Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)
H
18 tháng 12 2023
\(Al+\dfrac{3}{2}Cl_2\rightarrow AlCl_3\\ AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\\ 2Al\left(OH\right)_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+6H_2O\\ Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow2AlCl_3+3BaSO_4\\ AlCl_3+3AgNO_3\rightarrow Al\left(NO_3\right)_3+3AgCl\\ Al\left(NO_3\right)_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaNO_3\\ 2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\\ Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)
TP
12 tháng 8 2021
1.2FeO + \(\dfrac{1}{2}\)O2 → Fe2O3
2.2FexOy + \(\dfrac{3x-2y}{2}\) O2 → xFe2O3
3.2Al + 6HCl → 2AlCl3 + 3H2
4.Al2O3 + 3H2SO4 → Al2(SO4)3 + 3H2O
5.Al(OH)3 + 3HNO3 → Al(NO3)3 + 3H2O
TP
12 tháng 8 2021
6. 2Al + 3H2SO4 → Al2(SO4)3 + 3H2
7.2C4H10 + 13O2 → 8CO2 + 10H2O
8. 2KMnO4 → K2MnO4 + MnO2 + O2
9.2Cu(NO3)2 → 2CuO + 4NO2 + O2
10.M2Ox + 2xHNO3 → 2M(NO3)x + xH2O
24 tháng 12 2020
\(4Al+3O_2\underrightarrow{t^o}2Al_2O_3\)
\(4K+O_2\rightarrow2K_2O\)
\(2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\)
\(Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\)
\(CaCl_2+Fe\left(OH\right)_3\rightarrow\) Không phản ứng
\(BaCl_2+H_2SO_4\rightarrow2HCl+BaSO_4\downarrow\)
24 tháng 3 2020
\(3Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)
\(Al_2\left(SO_4\right)_3+3Cu\rightarrow3CuSO_4+2Al\)
\(4Al+3O_2\rightarrow2Al_2O_3\)
\(Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\)
\(AlCl_3+3H_2O\rightarrow Al\left(OH\right)_3+3HCl\)
\(2Al\left(OH\right)_3\rightarrow Al_2O_3+3H_2O\)
\(2Al_2O_3\rightarrow4Al+3O_2\)
\(2Al+3Cl_2\rightarrow2AlCl_3\)
CuO +2 HCl ➜ CuCl2+2H2O
Al2(SO4)3 + 3BaCl2 ➜ 2AlCl3 + 3BaSO4
2Al(OH)3 ➜ Al2O3 + 3H2O
\\tham khảo nhé//
CuO + 2HCl ➜ CuCl2 + H2O
Al2(SO4)3 + 3BaCl2 ➜ 2AlCl3 + 3BaSO4↓
2Al(OH)3 ➜ Al2O3 + 3H2O