Question

[Đặng thu thảo]

Rút gọn

M=\(\dfrac{\sqrt{x}}{\sqrt{x}-6}\)-\(\dfrac{3}{\sqrt[]{x}+6}\)+\(\dfrac{x}{36-x}\)với x>0;x≠36

N=\(\dfrac{x^2\sqrt{xy}}{y}\).\(\sqrt{\dfrac{y}{x}}\)-x² với x,y>0

P=\(\left(\dfrac{2-a\sqrt{a}}{2-\sqrt{a}}+\sqrt{a}\right).\left(\dfrac{2-\sqrt{a}}{2-a}\right)\)^{2 với a>0;a≠2; ≠4}

Answer 1

[Nguyễn Lê Phước Thịnh]

a: \(M=\dfrac{x+6\sqrt{x}-3\sqrt{x}+18-x}{x-36}\)

\(=\dfrac{3\left(\sqrt{x}+6\right)}{x-36}=\dfrac{3}{\sqrt{x}-6}\)

b: \(N=\dfrac{x^2}{y}\cdot\sqrt{xy\cdot\dfrac{y}{x}}-x^2\)

\(=\dfrac{x^2}{y}\cdot y-x^2=0\)