[ ( 47.32 +47.68) :100] .1001. tính hợp lý nhất có thể
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32.47+47.68- 100 . 17
= (32.47+47.68) - 100 . 17
= 47 (32 + 68) - 100.17
= 47.100 - 100.17
= 100.(47-17)
= 100. 30
= 3000
32.47+47.68- 100 . 17
= 47. ( 32+68 ) - 100.17
=47.100 - 100.17
=100.( 47-17 )
=100.30
=3000
\(a,S_3=-2-2-...-2\)
Tổng có \(\left[\left(2003-1\right):2+1\right]:2=501\left(số.hạng\right)\)
\(\Rightarrow S_3=501\cdot\left(-2\right)=-1002\)
\(b,S_4=\left(-1001+1001\right)+\left(-1000+1000\right)+...+\left(-1+1\right)+1002\\ S_4=1002\)
a: \(S_3=1+\left(-3\right)+5+\left(-7\right)+...+2001+\left(-2003\right)\)
=(-2)+(-2)+...+(-2)
=-2004
\(\left(9^{98}\cdot80+9^{98}\right):9^{100}\)
\(=\frac{9^{98}\cdot80+9^{98}}{9^{100}}\)
\(=\frac{9^{98}\cdot\left(80+1\right)}{9^{100}}\)
\(=\frac{9^{98}\cdot81}{100}\)
\(=\frac{9^{98}\cdot9^2}{9^{100}}\)
\(=\frac{9^{100}}{9^{100}}=1\)
\(=\dfrac{9^3\cdot\left(2^3\cdot3+45\right)}{9^3}=8\cdot3+45=69\)
100:{250:[450-(500-\(2^2\).25)]}
=100:{250:[450-(500-4.25)]}
=100:{250:[450-(500-100)]}
=100:{250:[450-400]}
=100:{250:50}
=100:50
=2
100:(250:[450-(500-4.25)]
=100:(250:(450-(500-100)]
=100:(250:(450-400)]
=100:(250:50)
=100:5
=20
c: \(=5+\dfrac{6}{7}-2-\dfrac{3}{8}-1-\dfrac{1}{8}=2+\dfrac{6}{7}-\dfrac{1}{2}=\dfrac{3}{2}+\dfrac{6}{7}=\dfrac{33}{14}\)
e: \(=\dfrac{-3}{5}\left(-\dfrac{1}{9}-\dfrac{5}{6}+\dfrac{5}{2}\right)=\dfrac{-3}{5}\cdot\dfrac{14}{9}=\dfrac{-14}{15}\)
[47.(32+68):100].1001=(47.100:100).1001=47.1001=47047
[ ( 47.32 +47.68) :100] .1001
= [ ( 47 . 32 + 68) :100] .1001
= [ ( 47 . 100 ) : 100 ] . 1001
= [ ( 4700 ) : 100 ] . 1001
= [ 4700 : 100 ] . 1001
= 47 . 1001
= 47047