225 - 125 = 15 (-x) + 40 = ?
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`@` `\text {Ans}`
`\downarrow`
`x^3 = 125`
`=> x^3 = 5^3`
`=> x = 5`
Vậy, `x = 5`
_____
`4^5 \div 4^3`
`=`\(4^{5-3}\)
`= 4^2`
______
\(8^{12}\cdot8^3\div8^{15}\)
`=`\(8^{12+3-15}\)
`=`\(8^0=1\)
______
\(7^{15}\div7^{13}\)
`=`\(7^{15-13}\)
`=`\(7^2\)
_______
\(17^{15}\cdot17^{10}\div17^{22}\)
`=`\(17^{15+10-22}\)
`= 17^3`
_______
\(5^{10}\cdot25\div5^{11}\)
`=`\(5^{10}\cdot5^2\div5^{11}\)
`=`\(5^{10+2-11}\)
`= 5`
_______
\(15^{10}\cdot225\div15^{11}\)
`=`\(15^{10}\cdot15^2\div15^{11}\)
`=`\(15^{12}\div15^{11}\)
`= 15`
`@` `\text {Kaizuu lv uuu}`
\(x^3=125\)
\(\Rightarrow x^3=5^3\)
\(\Rightarrow x=3\)
___________________
\(4^5:4^3\)
\(=4^{5-3}\)
\(=4^2=16\)
___________________
\(8^{12}.8^3:8^{15}\)
\(=8^{15}:8^{15}\)
\(=1\)
___________________
\(7^{15}:7^{13}\)
\(=7^{15-13}\)
\(=7^2=49\)
___________________
\(17^{15}.17^{10}:17^{22}\)
\(=17^{25}:17^{22}\)
\(=17^3=4913\)
___________________
\(5^{10}.25:5^{11}\)
\(=5^{10}.5^2:5^{11}\)
\(=5^{12}:5^{11}\)
\(=5^1=5\)
___________________
\(15^{10}.225:15^{11}\)
\(=15^{10}.15^2:15^{11}\)
\(=15^{12}:15^{11}\)
\(=15^1=15\)
__________________
* an . am = an+m
an : am = an-m
Chúc bạn học tốt
Bài 1 :
a, \(125⋮x\), \(225⋮x\)=> \(x\inƯC\left(125,225\right)\)
Ta có : 125 = 53 ; 225 = 32 . 52
\(ƯCLN\left(125;225\right)=5^2=25\)
\(\Rightarrow x\inƯC\left(125;225\right)=Ư\left(25\right)=\left\{1;5;25\right\}\)
Mà x < 25 nên x \(\in\left\{1;5\right\}\)
Vậy .......
b, \(x⋮30,x⋮40,x⋮50\Rightarrow x\in BC\left(30;40;50\right)\)
\(30=2.3.5\)
\(40=2^3.5\)
\(50=2.5^2\)
\(BCNN\left(30;40;50\right)=2^3.3.5=120\)
\(\Rightarrow x\in BC\left(30;40;50\right)=B\left(120\right)=\left\{0;120;240;360;480;600;720;840;960;1080;...\right\}\)
Mà x < 1000 nên \(x=960\)
Vậy .....
Bài 2 :
\(\text{Gọi số nhân viên của công ty đó là }a\)và \(500\le a\le600\)
Vì khi lên xe nhóm 15 người , 18 người , 20 người thì vừa đủ nên
\(a⋮15,a⋮18,a⋮20\)=> \(a\in BC\left(15,18,20\right)\)
\(15=3.5\)
\(18=2.3^2\)
\(20=2^2.5\)
\(BCNN\left(15,18,20\right)=3^2.2^2.5=180\)
\(\Rightarrow a\in BC\left(15,18,20\right)=B\left(180\right)=\left\{0;180;360;540;720;...\right\}\)
MÀ \(500\le a\le600\)nên a = 540
Vậy .........
Bài 1 :
a) 1440 : [ 41 - (2x - 5)] = 24.3
=> 1440 : [41 - (2x - 5)] = 16.3
=> 1440 : [41 - (2x - 5)] = 48
=> 41 - (2x - 5) = 1440 : 48 = 30
=> 2x - 5 = 11
=> 2x = 16
=> x = 8
b) 5 . [225 - (x - 10)] - 125 = 0
=> 5 . [225 - (x - 10)] = 125
=> 225 - (x - 10) = 125 : 5
=> 225 - (x - 10) = 25
=> x - 10 = 200
=> x = 210
Bài 2 :
a) [ 545 - (45 + 4.25)] : 50 - 200 : 250 + 215 : 213
= [ 545 - (45 + 100)] : 50 - 4/5 + 22
= [545 - 145] : 50 - 4/5 + 4
= 400 : 50 - 4/5 + 4 = 8 - 4/5 + 4 =56/5
Mấy câu còn lại tương tự
Bài 1.
a, 1440:[41-(2x-5)]=24.3
1440:[41-(2x-5)]= 16.3
1440:[41-(2x-5)]=48
[41-(2x-5)] =1440:48
[41-(2x-5)] = 30
2x-5 = 41-30
2x-5 =11
2x = 11+5
2x = 16
x = 16:2
x =8
b, 5.[225-(x-10)]-125=0
5.[225-(x-10)] =125
[225-(x-10)] =125:5
[225-(x-10)] = 25
(x-10) = 225-25
(x-10) = 200
x =200+10
x = 210
Bài 2.
a, [545-(45+4.25)]:50-200:250+215:213
= [545-(45+100)]:50-200:250+22
= [545-145]:50- 200:250+4
= 400:50-200:250+4
= 8-0,8+4
= 7,2 + 4
= 11,4
b, [504-(25.8+70)]:9-15+190
= [504-(200+70)]:9-15+1
= [504-270]:9-16
= 234:9-16
= 26-16
= 10
c, 5.{26-[3.(5+2.5)+15]:15}
= 5.{26-[3.(5+10)+15]:15}
= 5.{26-[3.15+15]:15}
= 5.{26-[45+15]:15}
= 5.{26-60:15}
= 5.{26-4}
=5.22
= 110
d,[1104-(25.8+40)]:9+316:312
= [1104-(200+40)]:9+34
=[1104-240]:9+34
=864:9+81
=96+81
=177
hok tốt
Giải
Bài 1
\(1,a,-40-37-\left(-29\right)\\ =-40-37+29\\ =-77+29=-48\\ b,27+\left(-36\right)-\left(-45\right)=27-36+45\\ =-9+45\\ =36\\ c,-125-\left[\left(-18\right)-125\right]\\ =-125+18+125\\ =\left(-125+125\right)+18\\ =18\\ d,140+\left[\left(-184\right)-140\right]\\ =140-184-140\\ =\left(140-140\right)-184\\ =0-184\\ =-184\)
Bài 2
\(a,x-\left(-15\right)=-8\\ =>x+15=-8\\ =>x=-8-15\\ =>x=-23\\ b,-40-x=-35\\ =>x=\left(-40\right)-\left(-35\right)\\ =>x=-40+35\\ =>x=-5\\ c,x+\left(-50\right)=-27\\ =>x-50=-27\\ =>x=-27+50\\ =>x=23\)
1, Thực hiện phép tính:
\(a,-40+\left(-37\right)-\left(-29\right)=-77-\left(-29\right)=-48\)
\(b,27+\left(-36\right)-\left(-45\right)=-9-\left(-45\right)=36\)
\(c,-125-\left[\left(-18\right)-125\right]=-125-\left(-143\right)=18\)
\(d,140+\left[\left(-184\right)-140\right]=140+\left(-324\right)=-184\)
2, Tìm x biết:
\(a,x-\left(-15\right)=-8\)
\(x=-8+\left(-15\right)\)
\(x=-23\)
\(b,-40-x=-35\)
\(x=-40-\left(-35\right)\)
\(x=-5\)
\(c,x+\left(-50\right)=-27\)
\(x=-27-\left(-50\right)\)
\(x=23\)
1. 15^x=225
<=>15^x=15^2
=>x=2
vậy....
2. x^3=27
<=>x^3=3^3
=>x=3
vậy......
3. 4.2^x-3=125
4.2^x=128
2^x=32
2^x=2^5
=>x=5
vậy.....
\(15^x=225\)
\(\Leftrightarrow15^x=15^2\)
\(\Leftrightarrow x=2\)
\(x^3=27\)
\(\Leftrightarrow x^3=3^3\)
\(\Leftrightarrow x=3\)
\(4.2^x-3=125\)
\(\Leftrightarrow4.2^x=125+3\)
\(\Leftrightarrow4.2^x=128\)
\(\Leftrightarrow2^x=128:4\)
\(\Leftrightarrow2^x=32\)
\(\Leftrightarrow2^x=2^5\)
\(\Leftrightarrow x=5\)
~ Hok tốt ~
a , 32 - | x - 1 | = 18
| x - 1 | = 32 - 18
| x - 1 | = 14
\(x-1=\hept{\begin{cases}14\\-14\end{cases}}\)
\(x=\hept{\begin{cases}14+1\\-14+1\end{cases}}\)
\(x=\hept{\begin{cases}15\\-13\end{cases}}\)
b, 34 - | x + 2 | = 22
| x + 2 | = 34 - 22 = 12
\(x+2=\hept{\begin{cases}12\\-12\end{cases}}\)
\(x=\hept{\begin{cases}12-2\\-12-2\end{cases}}\)
\(x=\hept{\begin{cases}10\\-14\end{cases}}\)
c , 28 - | x + 3 | = 15
| x + 3 | = 28 - 15 = 13
\(x+3=\hept{\begin{cases}13\\-13\end{cases}}\)
\(x=\hept{\begin{cases}13-3\\-13-3\end{cases}}\)
\(x=\hept{\begin{cases}10\\-16\end{cases}}\)
d , 47 - | x - 12 | = 32
| x - 12 | = 47 - 32 = 15
\(x-12=\hept{\begin{cases}15\\-15\end{cases}}\)
\(x=\hept{\begin{cases}15+12\\-15+12\end{cases}}\)
\(x=\hept{\begin{cases}27\\-3\end{cases}}\)
\(5.\left[225-\left(x-10\right)-125\right]=0\)
\(225-\left(x-10\right)-125=0:5\)
\(225-\left(x-10\right)-125=0\)
\(\left(x-10\right)-125=225-0\)
\(\left(x-10\right)-125=225\)
\(x-10=225+125\)
\(x-10=350\)
Mấy bài này làm theo thứ tứ trái sang phải, nhân chia trc cộng trừ sau thoi mà :>>>?
\(225-125=15\left(-x\right)+40=100\\ 15\left(-x\right)=60\\ x=-4\)
225-125=15(-x)+40=100
15(-x)+40=100
15(-x)=60
-x=60/15
-x=4
=>x=-4