tính N = \(8\dfrac{1}{5}\left(11\dfrac{94}{1591}-6\dfrac{38}{1517}\right):8\dfrac{11}{43}\)
K
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12 tháng 7 2023
b: \(=8.2\left(11+\dfrac{94}{1591}-6-\dfrac{38}{1517}\right):\left(8+\dfrac{11}{43}\right)\)
\(=\dfrac{41}{5}\cdot\left(5+\dfrac{60}{1763}\right):\dfrac{355}{43}\)
\(=\dfrac{41}{5}\cdot\dfrac{8875}{1763}\cdot\dfrac{43}{355}\)
\(=5\)
c: \(=10101\cdot\left(\dfrac{10+5}{222222}-\dfrac{4}{111111}\right)\)
\(=10101\cdot\dfrac{7}{222222}=\dfrac{7}{22}\)
PB
1
24 tháng 2 2018
\(8\frac{1}{5}\)X \(\left(11\frac{94}{1592}-6\frac{38}{1517}\right):8\frac{11}{43}\)
= \(\frac{41}{5}\)X \(\left(\frac{17606}{1592}-\frac{9140}{1517}\right):\frac{355}{43}\)
= \(\frac{41}{5}\)X \(\left(\frac{26708302}{2415064}-\frac{14550880}{2415064}\right):\frac{355}{43}\)
= \(\frac{41}{5}\)X \(\frac{12157422}{2415064}:\frac{355}{43}\)
= \(\frac{49845430200000006}{12075320}:\frac{355}{43}\)
= \(\frac{5358383746500001}{1071684650}\)
CN
1
18 tháng 6 2016
\(8\frac{1}{5}.\left(11\frac{94}{1591}-6\frac{38}{1517}\right):8\frac{11}{43}\\ =8\frac{1}{5}.5\frac{60}{1763}:8\frac{11}{43}\\ =41\frac{12}{43}:8\frac{11}{43}\\ =5\)
K
2
\(N=8\dfrac{1}{5}\left(11\dfrac{94}{1591}-6\dfrac{38}{1517}\right):8\dfrac{11}{43}\)
\(N=\dfrac{41}{5}\left(\dfrac{17595}{1591}-\dfrac{9140}{1517}\right):\dfrac{355}{43}\)
\(N=\dfrac{41}{5}.\dfrac{8875}{1763}:\dfrac{355}{43}\)
\(N=\dfrac{1775}{43}:\dfrac{355}{43}\)
\(N=5.\)