(\(20^2+18^2+16^2+...+4^2\)) - (\(19^2+17^2+...+3^2+1^2\)) = ?
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\(A=\dfrac{19+\dfrac{18}{2}+\dfrac{17}{3}+\dfrac{16}{4}+...+\dfrac{1}{19}}{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{20}}\)
Biến đổi tử số
\(19+\dfrac{18}{2}+\dfrac{17}{3}+\dfrac{16}{4}+...+\dfrac{1}{19}\)
= 1 + \(\left(1+\dfrac{18}{2}\right)+\left(1+\dfrac{17}{3}\right)+\left(1+\dfrac{16}{4}\right)+...+\left(1+\dfrac{1}{19}\right)\)
= \(\dfrac{20}{20}+\dfrac{20}{2}+\dfrac{20}{3}+...+\dfrac{1}{19}\)
= 20 x \(\left(\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{19}+\dfrac{1}{20}\right)\)
Vậy \(A=\dfrac{19+\dfrac{18}{2}+\dfrac{17}{3}+\dfrac{16}{4}+...+\dfrac{1}{19}}{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{20}}\)
= \(\dfrac{20\times\left(\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{19}+\dfrac{1}{20}\right)}{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{20}}=20\)
Vậy A = 20
\(\left(20^2+18^2+16^2+......+4^2+2^2\right)-\left(19^2+17^2+.....+3^2+1^2\right)\)
\(=20^2-19^2+18^2-17^2+......+2^2-1^2\)
\(=\left(20-19\right)\left(20+19\right)+\left(18-17\right)\left(18+17\right)+.......+\left(2-1\right)\left(2+1\right)\)
\(=39+35+....+7+3\)
\(=\left(39+3\right)\left[\left(39-3\right):4+1\right]:2=210\)
14) \(\sqrt{7-4\sqrt{3}}=2-\sqrt{3}\)
15) \(\sqrt{8+2\sqrt{15}}=\sqrt{5}+\sqrt{3}\)
16) \(\sqrt{10-2\sqrt{21}}=\sqrt{7}-\sqrt{3}\)
17) \(\sqrt{11+2\sqrt{18}}=3+\sqrt{2}\)
18) \(\sqrt{7+2\sqrt{10}}=\sqrt{5}+\sqrt{2}\)
19) \(\sqrt{7+4\sqrt{3}}=2+\sqrt{3}\)
20) \(\sqrt{12-2\sqrt{35}}=\sqrt{7}-\sqrt{5}\)
1+2+3+4+5+...+15+16+17+18+19+20
= ( 1 + 19 ) + ( 2 + 18 ) + ( 3 + 17 ) + ( 4 + 16 ) + ( 5 + 15 ) + ... + ( 9 + 11 ) + ( 10 + 20 )
= 20 + 20 + 20 + 20 + ... + 20 + 30
= 180 + 30 = 210
Tính số phần tử: \(\text{1+2+3+4+...+18+19+20}\)
\(=\left(20-1\right):1+1\) \(=20\)
Tổng : \(\dfrac{\left(20+1\right)\times20}{2}=210\)
20-19+18-17+16-15+14-13+12-11+11-10+10-9+9-8+8-7+7-6+6-5+5-4+4-3+3-2+2-1
=1+1+1+1+1+1+1+1+1+1+1+1+1+1+1
=1x15
=15
tk nhé
20 - 19 + 18 - 17 + 16 - 15 +....+ 4-3 + 2 - 1
= ( 20 - 19 ) + ( 18 - 17 ) + ( 16 - 15 ) + .... + ( 4 - 3 ) + ( 2 - 1 )
= 1 + 1 + 1 + .... + 1 + 1
=> có 10 số 1
=> Tổng dãy số đó là : 1 . 1 = 10
1. 53 = 5.5.5 = 125
2. 27 = 2.2.2.2.2.2.2 = 128
3. 44 = 4.4.4.4 = 256
4. 73 = 7.7.7 = 343
6. 35 = 243
7. 26 = 64
8. 34 = 81
9. 83 = 512
11. 132 = 169
12. 112 = 121
13. 142 = 196
14. 152 = 225
16. 172 = 289
17. 182 = 324
18. 192 = 361
19. 202 = 400
21. 104 = 10000
22. 105 = 100000
23. 106 = 1000000
24. 107 = 10000000
20-19+18-17+16-15+...+4-3+2-1=(20-19)+(18-17)+(16-15)+...+(4-3)+(2-1) (có 10 nhóm)
=1+1+1+...+1+1( có 10 số 1) =10.
( 502 + 482 + 462 +...+ 42 + 22) - (492 + 472 +...+ 32 + 12)
=502- 492 + 482 - 472 +...+ 42 - 32 + 22 - 12
= ( 50 - 49 )( 50 + 49 ) + ( 48 - 47 )( 48 + 47 )+...+( 4 - 3 )( 4 + 3) + ( 2-1 ) (2+1)
=50 + 49 + 48 + 47+...+ 4 + 3 + 2 + 1
=( 50 + 1) . 50 : 2 =1275