x/2,5 - 3x/10 = 10
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a) x/7 = 6/21
x/7 = 2/7
=>x=2
b)2/3x -1/2=1/10
2/3x = 1/10+1/2
2/3x = 3/5
x=3/5:2/3
x=9/10
c)1/4+1/3 : x = -5
d)3x+17=2
đ)2/3x +1/4 =7/12
2x+3/10= 11/6 . 6/11
x : 4 1/3 = -2,5
a) \(\left|2x\right|-\left|-2,5\right|=\left|-7,5\right|\)
\(\Leftrightarrow\left|2x\right|-2,5=7,5\)
\(\Leftrightarrow\left|2x\right|=10\)
\(\Leftrightarrow\begin{cases}x\ge0\\2x=10\end{cases}\) hoặc \(\begin{cases}x< 0\\2x=-10\end{cases}\)
\(\Leftrightarrow\begin{cases}x\ge0\\x=5\left(tm\right)\end{cases}\) hoặc \(\begin{cases}x< 0\\x=-5\left(tm\right)\end{cases}\)
Vậy x={5;-5}
b)\(\left|3x\right|\cdot\left|-3,5\right|=\left|-2,8\right|\)
\(\Leftrightarrow\left|3x\right|\cdot3,5=2,8\)
\(\Leftrightarrow\left|3x\right|=\frac{4}{5}\)
\(\Leftrightarrow\begin{cases}x\ge0\\3x=\frac{4}{5}\end{cases}\) hoặc \(\begin{cases}x< 0\\3x=-\frac{4}{5}\end{cases}\)
\(\Leftrightarrow\begin{cases}x\ge0\\x=\frac{4}{15}\end{cases}\) hoặc \(\begin{cases}x< 0\\x=-\frac{4}{15}\end{cases}\)
Vậy x={4/15;-4/15}
c) \(\left(3x-5\right)\left(\frac{3}{2}x+2\right)\left(0,5x-10\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}3x-5=0\\\frac{3}{2}x+2=0\\0,5x-10=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=\frac{5}{3}\\x=-\frac{4}{3}\\x=20\end{array}\right.\)
a)|2x|-|-2,5|=|-7,5|
|2x|-2,5=7,5
|2x|=10
\(\Rightarrow\left[\begin{array}{nghiempt}2x=10\\2x=-10\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=5\\x=-5\end{array}\right.\)
Vậy x=5;-5
a, x : 46 / 15 = 13 / 12
x = 13/12 . 46/15
x = 299/90
b, - 2/3x + 1 / 5 = 3 / 10
- 2 / 3 x = 3 / 10 - 1 / 5
- 2 / 3 x = 1 / 10
x = -3 / 20
c, x : 13 / 3 = - 2 / 5
x = - 2 / 5 . 13 / 3
x = -26 /15
d, 2 / 4 x + 2 / 5 x = 1
x ( 2 / 4 + 2 / 5 ) = 1
x . 9 / 10 = 1
x = 10 / 9
\(\dfrac{2}{10}x+\dfrac{3}{10}x=2,5x\)
\(\dfrac{1}{2}x=2,5x\)
\(\dfrac{1}{2}x=\dfrac{5}{2}x\)
\(\dfrac{1}{2}x-\dfrac{5}{2}x=0\)
\(-2x=0\)
\(x=0\)
\(\dfrac{2}{10}x+\dfrac{3}{10}x=2,5x\\ \dfrac{1}{2}x=\dfrac{5}{2}x\\ \dfrac{1}{2}x-\dfrac{5}{2}x=0\\ -2x=0\\ x=0\)
#1q2w3e
a: \(\dfrac{x}{0.9}=\dfrac{5}{6}\)
\(\Leftrightarrow x=\dfrac{3}{4}\)
b: \(\dfrac{-6}{x}=\dfrac{9}{-15}\)
\(\Leftrightarrow x=10\)
c: \(\dfrac{\dfrac{14}{15}}{\dfrac{9}{10}}=\dfrac{x}{\dfrac{3}{7}}\)
\(\Leftrightarrow x=\dfrac{3}{7}\cdot\dfrac{14}{15}:\dfrac{9}{10}=\dfrac{2}{5}\cdot\dfrac{10}{9}=\dfrac{20}{45}=\dfrac{4}{9}\)
Ta có:
\(\dfrac{x}{2,5}-\dfrac{3x}{10}=10\)
\(\Leftrightarrow4x-3x=100\)
\(\Leftrightarrow x=100\)
Vậy \(S=\left\{100\right\}\)
Chúc pạn hok tốt!!!
\(\dfrac{x}{2,5}-\dfrac{3x}{10}=10\)
<=>\(\dfrac{4x}{10}-\dfrac{3x}{10}=\dfrac{100}{10}\)
=> x=100
chúc bạn học tốt ^^