45.(13-35) + 35.(45-13)
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TK
a) (35 - 15).(-4) + 24.(-13 - 17)
= 20.(-4) + 24.(-30)
= (-80) + (-720)
b) (-13).(57 - 34) +57. (13 - 45)
= (-13).23 + 57.(-32)
= (-299) + (-1824)
= -2123
1: =20*(-4)+24(-30)
=-80-720=-800
2: =-13*57+13*32+57*13-57*45
=13*32-57*45=-2149
3: =-12*8*125
=-12*1000=-12000
4: =(-134)(1-51+48)
=(-134)*(-2)=268
5: =(-24)(45-5)=40*(-24)=-960
a)126.(-43)+26.43=43(-126+26)=43(-100)=-4300
b)(-135)(-45)-35.45=-45(-135+35)=-45(-100)=4500
c)113(-27)+27.13=27(-113+13)=27(-100)=-2700
d)125(-35)-(-25).35=-35(125-25)=-35.100=-3500
\(a)126.\left(-43\right)+26.43\)
\(=\left(-126\right).43+26.43\)
\(=43\left(-126+26\right)\)
\(=43.\left(-100\right)\)
\(=-4300\)
\(b)\left(-135\right).\left(-45\right)-35.45\)
\(=135.45-35.45\)
\(=45\left(135-35\right)\)
\(=45.100\)
\(=4500\)
\(c)113.\left(-27\right)+27.13\)
\(=\left(-113\right).27+27.13\)
\(=27\left(-113+13\right)\)
\(=27.\left(-100\right)\)
\(=-2700\)
\(d)125.\left(-35\right)-\left(-25\right).35\)
\(=\left(-125\right).35-\left(-25\right).35\)
\(=35\left(-125+25\right)\)
\(=35.\left(-100\right)\)
\(=-3500\)
Ta có:
\(\frac{2^{35}.45^{25}.13^{22}.35^{16}}{9^{26}.65^{22}.28^{17}.25^9}=\frac{2^{35}.\left(9.5\right)^{25}.13^{22}.\left(5.7\right)^{16}}{9^{26}.\left(5.13\right)^{22}.\left(7.4\right)^{17}.\left(5.5\right)^9}\)
\(=\frac{2^{35}.9^{25}.5^{25}.13^{22}.5^{16}.7^{16}}{9^{26}.13^{22}.5^{22}.7^{17}.4^{17}.5^9.5^9}\)
\(=\frac{2^{35}.5^3}{9.4^{17}.5^2.7}\)
\(=\frac{2^{35}.5}{9.4^{17}.7}\)
\(=\frac{2^{35}.5}{9.2^{34}.7}\)
\(=\frac{2.5}{9.7}\)
\(=\frac{10}{63}\)
p/s: - Ko chắc ~
\(A=\dfrac{2^{35}.45^{25}.13^{22}.35^{16}}{9^{26}.65^{22}.28^{17}.25^9}=\dfrac{2^{35}.3^{50}.5^{25}.13^{22}.5^{16}.7^{16}}{3^{52}.13^{22}.5^{22}.2^{34}.7^{17}.5^{18}}\)
\(=\dfrac{2.5^3}{3^2.5^2.7}=\dfrac{2.5}{3^2.7}=\dfrac{10}{63}\)
a, 18.(-24) + 35.42 - 18.76 + 35.(-142)
= [ 18.(-24) - 18.76] + (35.42 + 35(-142)]
= -18.[ 24 + 76] - 35.( 142 - 42)
= -18.100 - 35. 100
= - 100.(18 + 35)
= - 100. 53
= - 5300
h, 104 : (-13) - [56 - 220 : (-4)]
= 104 : (-13) - [ 56 + 55]
= -8 - 111
= - 119
5(2-x)=35
2-x= 35: 5
2-x= 7
x= 2-7
x=-5
29x-13=45
29x = 45+13
29x = 58
x= 58 : 29
x= 2
\(45\left(13-35\right)+35\left(45-13\right).\)
\(=45.13-45.35+35.45-35.13.\)
\(=\left[-\left(45.35\right)+35.45\right]+\left(45.13-35.13\right).\)
\(=0+13\left(45-35\right).\)
\(=0+13.10.\)
\(=0+130=130.\)
Vậy..........