Bài 4: Phân tích các đa thức sau thành nhân tử:
a) x3 - 2x2 + x b) x2 – 2x – 15
c) 5x2y3 – 25x3y4 + 10x3y3 d) 12x2y – 18xy2 – 30y2
e) 5(x-y) – y.( x – y) f) y .( x – z) + 7(z - x)
g) 27x2( y- 1) – 9x3 ( 1 – y) h) 36 – 12x + x2
i) 3x3y2 – 6x2y3 + 9x2y2
a) \(x^3-2x^2+x=x\left(x^2-2x+1\right)=x\left(x-1\right)^2\)
b) \(x^2-2x-15=\left(x^2-2x+1\right)-16=\left(x-1\right)^2-4^2=\left(x-1-4\right)\left(x-1+4\right)=\left(x-5\right)\left(x+3\right)\)
c) \(5x^2y^3-25x^3y^4+10x^3y^3=5x^2y^3\left(1-5xy+2x\right)\)
d) \(12x^2y-18xy^2-30y^2=6\left(2x^2y-3xy^2-5y^2\right)\)
e, ntc: x-y
f, đối dấu --> ntc
g, như ý f
h, \(36-12x+x^2=\left(6-x\right)^2=\left(x-6\right)^2\)
i, \(3x^3y^2-6x^2y^3+9x^2y^2=3x^2y^2\left(x-y+3\right)\)
thanks