5×18/10×36-10×27/20×54+15×36/30×27
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\(\frac{1\cdot3\cdot9+2\cdot6\cdot18+3\cdot9\cdot27}{1\cdot5\cdot18+2\cdot10\cdot36+3\cdot15\cdot54}\)
\(=\frac{1\cdot3\cdot9+2\left(1\cdot3\cdot9\right)+3\left(1\cdot3\cdot9\right)}{1\cdot5\cdot18+2\left(1\cdot5\cdot18\right)+3\left(1\cdot5\cdot18\right)}\)
\(=\frac{\left(1\cdot3\cdot9\right)\left(1+2+3\right)}{\left(1\cdot5\cdot18\right)\left(1+2+3\right)}\)
\(=\frac{3}{10}\)
b: 12/20+6/18=3/5+1/3=9/15+5/15=14/15
c: 8/12+20/30=2/3+2/3=4/3
d: 10/12+12/36=5/6+2/6=7/6
a) Ta có:
\(\begin{array}{l}\frac{{ - 10}}{{18}} =\frac{{ - 10:2}}{{18:2}} = \frac{{ - 5}}{9};\,\,\,\\\frac{{10}}{{18}} = \frac{{10:2}}{{18:2}} =\frac{5}{9};\,\,\\\,\frac{{15}}{{ - 27}} =\frac{{15:(-3)}}{{ - 27:(-3)}} = \frac{{ - 5}}{9};\,\\ - \frac{{20}}{{36}} =- \frac{{20:4}}{{36:4}}= \frac{{ - 5}}{9}.\end{array}\)
Vậy những phân số nào biểu diễn số hữu tỉ \(\frac{{ - 5}}{9}\) là: \(\frac{{ - 10}}{{18}};\,\frac{{15}}{{ - 27}};\, - \frac{{20}}{{36}}.\)
b) Số đối của các số \(12;\,\frac{{ 4}}{9};\, - 0,375;\,\frac{0}{5};\,-2\frac{2}{5}\) lần lượt là: \( - 12;\,\frac{-4}{9};\,0,375;\,\frac{0}{5};\, 2\frac{2}{5}\).
1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30+31+32+33+34+35+36+37
=(1+37)x37:2
=703
\(\frac{1.5.18+2.10.36+3.15.54}{1.3.9+2.6.18+3.9.27}=\frac{1.5.18.\left(1+2.2.2+3.3.3\right)}{1.3.9.\left(1+2.2.2+3.3.3\right)}\)
\(=\frac{1.5.18}{1.3.9}=\frac{10}{3}\)
\(\frac{5\cdot18}{10\cdot36}-\frac{10\cdot27}{20\cdot54}+\frac{15\cdot36}{30\cdot27}\)
\(=\frac{5\cdot18}{5\cdot2\cdot18\cdot2}-\frac{10\cdot27}{10\cdot2\cdot27\cdot2}+\frac{15\cdot9\cdot4}{15\cdot2\cdot9\cdot3}\)
\(=\frac{1}{2\cdot2}-\frac{1}{2\cdot2}+\frac{4}{2\cdot3}\)
\(=\frac{1}{4}-\frac{1}{4}+\frac{2}{3}\)
\(=\frac{2}{3}\)
\(5\)x\(\frac{18}{10}\) x \(36-10\) x \(\frac{27}{20}\) x\(54+15\) x \(\frac{36}{30}\) x \(27\)
5 x \(\frac{9}{5}\) x 36 - 10 x \(\frac{27}{20}\) x 54 + 15 x \(\frac{6}{5}\) x 27
81