1+2+1+13+1+1+27+40+1+1+1+1+!1111111111+11111111111111+
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Bài làm
1+1=2
2+11111111111111= 1111111111113
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\(a,30+X=120:5+27\\ 30+X=24+27\\ 30+X=51\\ X=51-30=21\\ ---\\ b,40-3\times X=13\\ 3\times X=40-13=27\\ X=\dfrac{27}{3}=9\\ ---\\ 2\times X-8=16\\ 2\times X=16+8\\ 2\times X=24\\ X=\dfrac{24}{2}=12\\ \\---\\ \dfrac{1}{2}\times X-\dfrac{1}{3}=\dfrac{1}{4}\\ \dfrac{1}{2}\times X=\dfrac{1}{4}+\dfrac{1}{3}=\dfrac{7}{12}\\ X=\dfrac{7}{12}:\dfrac{1}{2}=\dfrac{7}{6}\)
Bài 1:a, \(\dfrac{13}{2}\) = \(\dfrac{13\times5}{2\times5}\) = \(\dfrac{65}{10}\)
b, \(\dfrac{11}{40}\) = \(\dfrac{11\times25}{40\times25}\) = \(\dfrac{275}{1000}\)
c, \(\dfrac{21}{250}\) = \(\dfrac{21\times4}{250\times4}\) = \(\dfrac{84}{1000}\)
d, \(\dfrac{27}{45}\) = \(\dfrac{27:9}{45:9}\) = \(\dfrac{3}{5}\) = \(\dfrac{3\times2}{5\times2}\) = \(\dfrac{6}{10}\)
Bài 2:
a, (3\(\dfrac{1}{8}\) + 1\(\dfrac{3}{4}\)): 2\(\dfrac{1}{4}\)
= (\(\dfrac{25}{8}\) + \(\dfrac{7}{4}\)): \(\dfrac{9}{4}\)
= \(\dfrac{39}{8}\) \(\times\) \(\dfrac{4}{9}\)
= \(\dfrac{13}{6}\)
a: \(=\left(9-\dfrac{13}{18}\right):\dfrac{325}{27}-\dfrac{17}{8}:\dfrac{51}{40}\)
\(=\dfrac{149}{18}\cdot\dfrac{27}{325}-\dfrac{17}{8}\cdot\dfrac{40}{51}\)
\(=\dfrac{447}{650}-\dfrac{5}{3}=-\dfrac{1909}{1950}\)
b: \(=\dfrac{48}{64}+\left(\dfrac{4}{5}-2-\dfrac{4}{15}\right):\dfrac{11}{3}\)
\(=\dfrac{3}{4}+\dfrac{-22}{15}\cdot\dfrac{3}{11}=\dfrac{3}{4}-\dfrac{2}{5}=\dfrac{15-8}{20}=\dfrac{7}{20}\)
1.1112222e+13
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