2x^2 -3x +1 =0
2x^2 -3x -5 =0
tìm x
lm giúp mink vs còn 5h nữa mink ik hok oy
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
1.\(\left(2x-1\right)\left(x-1\right)=0\)
2. \(\left(x+1\right)\left(2x-5\right)=0\)
3. \(\left(2x-1\right)\left(x+4\right)=0\)
4. Vô nghiệm vì VT > 0 \(\forall\)x
Ta có :
\(\left(2x^2-3x+1\right)-\left(2x^2-3x+4\right)=0\)
\(\Leftrightarrow2x^2-3x+1-2x^2+3x-4=0\)
\(\Leftrightarrow-3=0\left(ktm\right)\)
\(\Leftrightarrow x\in\varnothing\)
Bài 1:
a) f(x)-g(x)=2x3-x2+5+2x3-x2-1-2x
=4x3-2x2-2x-1
Bậc: 3
b) f(x)+g(x)=2x3-x2+5-2x3+x2+1+2x
=2x+6
Để f(x)+g(x)=0 thì 2x+6=0
=>2x=-6
=>x=-3
Bài 2:
a) \(\left|x+\dfrac{1}{5}\right|-\dfrac{1}{7}=0\)
\(\Rightarrow\left|x+\dfrac{1}{5}\right|=\dfrac{1}{7}\)
\(\Rightarrow\left[{}\begin{matrix}x+\dfrac{1}{5}=\dfrac{1}{7}\Rightarrow x=\dfrac{-2}{35}\\x+\dfrac{1}{5}=\dfrac{-1}{7}\Rightarrow x=\dfrac{-12}{35}\end{matrix}\right.\)
b) \(2\left(x+1\right)+4^2=2^4\)
\(\Rightarrow2x+2+16=16\)
\(\Rightarrow2x+2=0\)
\(\Rightarrow2x=-2\)
\(\Rightarrow x=-1\)
a)4(18 - 5x) - 12(3x - 7) = 15(2x - 16) - 6(x + 14)
<=>72 - 20x - 36x +84 = 30x - 240 - 6x 84
<=> -80x = -480
<=> x = 6
b) 5(3x+5)-4(2x-3) =5x+3(2x+12)+1
<=> 15x + 25 - 8x + 12 = 5x + 6x + 36 + 1
<=> 15x + 25 - 8x + 12 - 5x - 6x - 36 - 1 = 0
<=> -4x = 0
<=> x = 0
c) 2(5x-8)-3(4x-5)=4(3x-4)+11
= 10x - 16 - 12x + 15 = 12x - 16 + 11
= -14x = -4
= x =\(\frac{2}{7}\)
d) 5x-3{4x-2[4x-3(5x-2)]}=182
= 5x - 3 . [4x - 2(4x - 15x + 6)]
= 5x - 3 . (4x - 8x + 30x - 12)
= 5x - 12x + 24x - 90x + 36
= -73x + 36 = 182
=> -73x = 182 - 36 = 146
=> x = 146 : (-73) = -2
~Hok tốt~
a) \(\left|x-2\right|+3x-9=0\)
\(\Leftrightarrow\left|x-2\right|=9-3x\)
+) Xét \(x\ge2\)
\(pt\Leftrightarrow x-2=9-3x\)
\(\Leftrightarrow x+3x=9+2\)
\(\Leftrightarrow4x=11\)
\(\Leftrightarrow x=\frac{11}{4}\left(tm\right)\)
+) Xét \(x< 2\)
\(pt\Leftrightarrow2-x=9-3x\)
\(\Leftrightarrow-x+3x=9-2\)
\(\Leftrightarrow2x=7\)
\(\Leftrightarrow x=\frac{7}{2}\left(ktm\right)\)
Vậy....
a) (2x + 1)(x - 1) = 0
<=> 2x + 1 = 0 hoặc x - 1 = 0
<=> x = -1/2 hoặc x = 1
b) (x + 2/3)(x - 1/2) = 0
<=> x + 2/3 = 0 hoặc x - 1/2 = 0
<=> x = -2/3 hoặc x = 1/2
c) (3x - 1)(2x - 3)(x + 5) = 0
<=> 3x - 1 = 0 hoặc 2x - 3 = 0 hoặc x + 5 = 0
<=> x = 1/3 hoặc x = 3/2 hoặc x = -5
d) 3x - 15 = 2x(x - 5)
<=> 3x - 15 = 2x2 - 10x
<=> 3x - 15 - 2x2 + 10x = 0
<=> 13x - 15 - 2x2 = 0
<=> 2x2 - 13x + 15 = 0
<=> 2x2 - 3x - 10x + 15 = 0
<=> x(2x - 3) - 5(2x - 3) = 0
<=> (x - 5)(2x - 3) = 0
<=> x - 5 = 0 hoặc 2x - 3 = 0
<=> x = 0 hoặc x = 3/2
e) x2 - x = 0
<=> x(x - 1) = 0
<=> x = 0 hoặc x - 1 = 0
<=> x = 0 hoặc x = 1
f) x2 - 2x = 0
<=> x(x - 2) = 0
<=> x = 0 hoặc x - 2 = 0
<=> x = 0 hoặc x = 2
g) x2 - 3x = 0
<=> x(x - 3) = 0
<=> x = 0 hoặc x - 3 = 0
<=> x = 0 hoặc x = 3
h) (x + 1)(x + 2) = (2 - x)(x + 3)
<=> x2 + 2x + x + 2 = 2x + 6 - x2 - 3x
<=> x2 + 3x + 2 = -x + 6 - x2
<=> x2 + 3x + 2 + x - 6 + x2 = 0
<=> 2x2 + 4x - 4 = 0
làm nốt đi :))
nỡ giúp rùi thì bn giúp mink nốt ik vì mink ngu toán cực kì luôn
a: =>2x^2-2x+2x-2-2x^2-x-4x-2=0
=>-5x-4=0
=>x=-4/5
b: =>6x^2-9x+2x-3-6x^2-12x=16
=>-19x=19
=>x=-1
c: =>48x^2-12x-20x+5+3x-48x^2-7+112x=81
=>83x=83
=>x=1
2x2-3x+1=0
<=>(2x2-2x)-(x-1)=0
<=>2x(x-1)-(x-1)=0
<=>(2x-1)(x-1)=0
\(< =>\left\{{}\begin{matrix}2x-1=0=>x=\dfrac{1}{2}\\x-1=0=>x=1\end{matrix}\right.\)
2x2-3x-5=0
<=>(2x2+2x)-(5x+5)=0
<=>2x(x+1)-5(x+1)=0
<=>(2x-5)(x+1)=0
\(< =>\left\{{}\begin{matrix}2x-5=0=>x=\dfrac{5}{2}\\x+1=0=>x=-1\end{matrix}\right.\)