tính giá trị biểu thức 56,68 x 75 +56,68 x 20 +56,68 x 5=
a 56,68
b 566,8
c5668
d65,68
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a) 20 x 190 x 50
= 20 x 50 x 190
= 1000 x 190
= 190 000
b) 769 x 85 - 769 x 75
= 769 x (85 - 75)
= 769 x 10
= 7690
a: Thay x=9 vào A, ta được:
\(A=\dfrac{3+2}{3-5}=\dfrac{5}{-2}=\dfrac{-5}{2}\)
\(B=\dfrac{3\sqrt{x}-15+20-2\sqrt{x}}{x-25}=\dfrac{\sqrt{x}+5}{x-25}=\dfrac{1}{\sqrt{x}-5}\)
b: Để \(A=B\cdot\left|x-4\right|\) thì \(\left|x-4\right|=\dfrac{A}{B}=\dfrac{\sqrt{x}+2}{\sqrt{x}-5}:\dfrac{1}{\sqrt{x}-5}=\sqrt{x}+2\)
\(\Leftrightarrow x-4=\sqrt{x}+2\)
\(\Leftrightarrow x-\sqrt{x}-6=0\)
=>x=9
45^10*5^20/75^15
=5^10*9^10*5^20/(5^2)^15
=5^10*5^20*9^10/5^30
=9^10
(0.8)^5/(0.4)^6
=(0.4)^5*2^5/(0.4)^6
=2^5/(0.4)
=32/(0.4)
=80
2^15*9^4/6^6*8^3
=2^15*(3^2)^4/2^6*3^6*(2^3)^3
=2^15*3^8/2^6*3^6*2^9
=3^2
=9
\(45^{10}\cdot5^{20}:75^{15}=\left(5.9\right)^{10}.5^{20}:\left(3.25\right)^{15}=\frac{5^{10}.9^{10}.5^{20}}{3^{15}.25^{15}}=\frac{5^{30}.3^{2.10}}{3^{15}.5^{2.15}}=\frac{5^{30}.3^{20}}{3^{15}.5^{30}}=3^5=243\)
a) (2/5 x 25/29) + (3/5 x 25/29)
= (50/145) + (75/145)
= 125/145
b) (5/2 x 3/7) - (3/14 : 6/7)
= 15/14 - (3/14 x 7/6)
= 15/14 - 1/2
= (30/28) - (14/28)
= 16/28
= 4/7
c) (15/4 : 5/12) - (6/5 : 11/15)
= (15/4 x 12/5) - (6/5 x 15/11)
= 180/20 - 90/55
= 9 - 18/11
= (99/11) - (18/11)
= 81/11
= 7 4/11
a) (2/3) + (20/21 x 3/2 x 7/5)
= 2/3 + (60/210)
= 2/3 + 2/7
= (14/21) + (6/21)
= 20/21
b) (5/17 x 21/32 x 47/24 x 0)
= 0
c) (11/3 x 26/7) - (26/7 x 8/3)
= (286/21) - (208/21)
= 78/21
= 3 9/21
= 3 3/7
a) (25/8) : x = 5/16
=> (25/8) x (16/5) = x
=> 4 = x
b) x + (7/15) = 6/15
=> x = (6/15) - (7/15)
=> x = -1/15
c) x : (28/49) = 7/12
=> x x (49/28) = 7/12
=> x = (7/12) x (28/49)
=> x = 1/2
a) 6 x x = (5/8) : (3/4)
=> 6x = (5/8) x (4/3)
=> 6x = 20/24
=> 6x = 5/6
=> x = (5/6) / 6
=> x = 5/36
câu,b,không,đủ,thông,tin,nhan,bạn.
C) 5668
Học tốt
C.5668
Vì 56,68 x 75 +56,68 x 20 +56,68 x 5
= 56,68 x (75+20+5)
=56,68 x 100
=5668