2^x=8^3*8^-10*8^3
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
b) Ta có: \(5^{x+4}-3\cdot5^{x+3}=2\cdot5^{11}\)
\(\Leftrightarrow2\cdot5^{x+3}=2\cdot5^{11}\)
\(\Leftrightarrow x+3=11\)
hay x=8
c) Ta có: \(2\cdot3^{x+2}+4\cdot3^{x+1}=10\cdot3^6\)
\(\Leftrightarrow18\cdot3^x+12\cdot3^x=10\cdot3^6\)
\(\Leftrightarrow30\cdot3^x=30\cdot3^5\)
Suy ra: x=5
d) Ta có: \(6\cdot8^{x-1}+8^{x+1}=6\cdot8^{19}+8^{21}\)
\(\Leftrightarrow6\cdot\dfrac{8^x}{8}+8^x\cdot8=6\cdot8^{19}+64\cdot8^{19}\)
\(\Leftrightarrow8^x\cdot\dfrac{35}{4}=70\cdot8^{19}\)
\(\Leftrightarrow8^x=8^{20}\)
Suy ra: x=20
![](https://rs.olm.vn/images/avt/0.png?1311)
8 x 0 =0
8 x 8 =64
8 x 2 =16
8 x 4 =32
8 x 6 =48
8 x 9 =72
8 x 3 =24
8 x 7 =56
8 x 10 =80
8 x 0 =0
8 x 8 =64
8 x 2 =16
8 x 4 =32
8 x 6 =48
8 x 9 =72
8 x 3 =24
8 x 7 =56
8 x 10 =80
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\left(x+2\right)^{10}+\left(x+2\right)^8=0\\ \Leftrightarrow\left(x+2\right)^8\left[\left(x+2\right)^2+1\right]=0\\ \Leftrightarrow\left[{}\begin{matrix}\left(x+2\right)^8=0\\\left(x+2\right)^2+1=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x+2=0\\\left(x+2\right)^2=-1\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=-2\\x\in\varnothing\end{matrix}\right.\\ b,\left(x+3\right)^{10}-\left(x+3\right)^8=0\\ \Leftrightarrow\left(x+3\right)^8\left[\left(x+3\right)^2-1\right]=0\\ \Leftrightarrow\left[{}\begin{matrix}\left(x+3\right)^8=0\\\left(x+3\right)^2-1=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x+3=0\\\left(x+3\right)^2=1\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=-3\\x+3=1\\x+3=-1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=-2\\x=-4\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
8 x 1 = 8 8 x 3 = 24 8 x 5 = 40 8 x 7 = 56 8 x 9 = 72
8 x 2 = 16 8 x 4 = 32 8 x 6 = 48 8 x 8 = 64 8 x 10 = 80
![](https://rs.olm.vn/images/avt/0.png?1311)
8 x 1 = 8
8 x 5 = 40
8 x 0 = 0
8 x 8 = 64
8 x 2 = 16
8 x 4 = 32
8 x 6 = 48
8 x 9 =72
8 x 3 = 24
8 x 7 = 56
8 x 10 = 80
![](https://rs.olm.vn/images/avt/0.png?1311)
Học sinh tự nhẩm và ghi như sau:
8 x 3 = 24
8 x 2 = 16
8 x 4 = 32
8 x 1 = 8
8 x 5 = 40
8 x 6 = 48
8 x 7 = 56
0 x 8 = 0
8 x 8 = 64
8 x 10 = 80
8 x 9 = 72
8 x 0 = 0
![](https://rs.olm.vn/images/avt/0.png?1311)
Câu 1:
a. 3/4+1/8=6/8+1/8=7/8
x-5/7=3/5*1/2
x-5/7=3/10
x=3/10+5/7
x=61/70
b.4/5+3/10=8/10+3/10=11/10
x*2/3=8/8+3/4
x*2/3=7/4
x=7/4:2/3
x=21/8
Thế nha, bài này dài đó!!!! :))))
\(2^x=8^3.8^{-10}.8^3=8^{-4}=2^{-12}\\ \Rightarrow x=-12\)