Tìm x biết :
\(\frac{x-20}{9}+\frac{x-21}{10}+\)\(\frac{x-26}{15}=-3\)
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NH
0
DT
4
2 tháng 9 2020
Không viết lại đề bài
\(\Leftrightarrow\frac{x-20}{9}+\frac{x-21}{10}+\frac{x-26}{15}+3=0\)
\(\Leftrightarrow\left(\frac{x-20}{9}+1\right)+\left(\frac{x-21}{10}+1\right)+\left(\frac{x-26}{15}+1\right)=0\)
\(\Leftrightarrow\left(\frac{x-20+9}{9}\right)+\left(\frac{x-21+10}{10}\right)+\left(\frac{x-26+15}{15}\right)=0\)
\(\Leftrightarrow\frac{x-11}{9}+\frac{x-11}{10}+\frac{x-11}{15}=0\)
\(\Leftrightarrow\left(x-11\right)\left(\frac{1}{9}+\frac{1}{10}+\frac{1}{15}\right)=0\)
Vì \(\frac{1}{9}+\frac{1}{10}+\frac{1}{15}\ne0\)
\(\Rightarrow x-11=0\Leftrightarrow x=11\)
XO
2 tháng 9 2020
Ta có\(\frac{x-20}{9}+\frac{x-21}{10}+\frac{x-26}{15}=-3\)
=> \(\left(\frac{x-20}{9}+1\right)+\left(\frac{x-21}{10}+1\right)+\left(\frac{x-26}{15}+1\right)=-3+1+1+1\)
=> \(\frac{x-11}{9}+\frac{x-11}{10}+\frac{x-11}{15}=0\)
=> \(\left(x-11\right)\left(\frac{1}{9}+\frac{1}{10}+\frac{1}{15}\right)=0\)
Vì \(\frac{1}{9}+\frac{1}{10}+\frac{1}{15}\ne0\)
=> x - 11 = 0
=> x = 11
Vậy x = 11
DP
24 tháng 6 2017
\(a,\)\(x+\frac{4}{5.9}+\frac{4}{9.13}+\frac{4}{13.17}+...+\frac{4}{41.45}=-\frac{37}{45}\)
\(x+\left(\frac{9-5}{5.9}+\frac{13-9}{9.13}+\frac{17-13}{13.17}+...+\frac{45-41}{41.45}\right)=-\frac{37}{45}\)
\(x+\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+\frac{1}{13}-\frac{1}{17}+....+\frac{1}{41}-\frac{1}{45}\right)-\frac{37}{45}\)
\(x+\left(\frac{1}{5}-\frac{1}{45}\right)=-\frac{37}{45}\)
\(x+\frac{8}{45}=-\frac{37}{45}\)
\(x=-\frac{37}{45}-\frac{8}{45}\)
\(x=-1\)
21 tháng 8 2019
\(\frac{x}{6}+\frac{x}{10}+\frac{x}{15}+\frac{x}{21}+\frac{x}{28}+\frac{x}{39}=\frac{8}{9}.\)
\(\Rightarrow x.\left(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{1}{39}\right)=\frac{8}{9}\)
\(\Rightarrow x.\frac{23}{52}=\frac{8}{9}\)
\(\Rightarrow x=\frac{426}{207}\)
Study well
21 tháng 8 2019
\(\frac{x}{6}+\frac{x}{10}+\frac{x}{15}+\frac{x}{21}+\frac{x}{28}+\frac{x}{39}=\frac{8}{9}\)
<=> x\(\left(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{x}{39}\right)=\frac{8}{9}\)
<=> x = \(\frac{8}{9}:\frac{23}{52}\)
<=> x = \(\frac{416}{207}\)
CA
0
3 tháng 7 2017
a ) Ta có : \(\frac{x+11}{10}+\frac{x+21}{20}+\frac{x+31}{30}=\frac{x+41}{40}+\frac{x+101}{5}\)
\(\Leftrightarrow\left(\frac{x+11}{10}-1\right)+\left(\frac{x+21}{10}-1\right)+\left(\frac{x+31}{30}-1\right)=\left(\frac{x+41}{40}-1\right)+\left(\frac{x+101}{50}-2\right)\)
\(\Leftrightarrow\frac{x+1}{10}+\frac{x+1}{20}+\frac{x+1}{30}=\frac{x+1}{40}+\frac{x+1}{50}\)
\(\Rightarrow\frac{x+1}{10}+\frac{x+1}{20}+\frac{x+1}{30}-\frac{x+1}{40}-\frac{x+1}{50}=0\)
\(\Leftrightarrow\left(x+1\right)\left(\frac{1}{10}+\frac{1}{20}+\frac{1}{30}-\frac{1}{40}-\frac{1}{50}\right)=0\)
Mà \(\left(\frac{1}{10}+\frac{1}{20}+\frac{1}{30}-\frac{1}{40}-\frac{1}{50}\right)\ne0\)
Nên x + 1 = 0
=> x = -1
mình sắp lên lớp 4 rùi
\(\frac{x-20}{9}+\frac{x-21}{10}+\frac{x-26}{15}=-3\)
\(\Leftrightarrow\frac{x-20}{9}+1+\frac{x-21}{10}+1+\frac{x-26}{15}+1=0\)
\(\Leftrightarrow\frac{x-11}{9}+\frac{x-11}{10}+\frac{x-11}{15}=0\)
\(\Leftrightarrow\left(x-11\right)\left(\frac{1}{9}+\frac{1}{10}+\frac{1}{15}\ne0\right)=0\Leftrightarrow x=11\)