(3 . x - 48) . 6 = 33 . 33 + 23 + 32 - 122
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\(a.\left(-83\right)+302+83\\ =\left(-83+83\right)+302\\ =0+302\\ =302\\ b.14.\left(-7\right)-216:2\\ =-98-108\\ =-206\\ c.56.\left(-32\right)+\left(-68\right).56\\ =56.\left[\left(-32\right)+\left(-68\right)\right]\\ =57.\left(-100\right)\\ =-5700\\ d.2^3-6.\left[25-\left(33-28\right)^2\right]\\ =8-6\left[25-5^2\right]\\ =8-6\left[25-25\right]\\ =8-6.0\\ =8-0\\ =8\\ e.15.\left(-6\right)-420:\left(-4\right)\\ =-90-\left(-105\right)\\ =-90+105\\ =15\)
\(f.63.\left(-52\right)+\left(-48\right).63\\ =63.\left[\left(-52\right)+\left(-48\right)\right]\\ =63.\left(-100\right)\\ =-6300\)
a)\(...A=\dfrac{2^{50+1}-1}{2-1}=2^{51}-1\)
b) \(...\Rightarrow B=\dfrac{3^{80+1}-1}{3-1}=\dfrac{3^{81}-1}{2}\)
c) \(...\Rightarrow C+1=1+4+4^2+4^3+...+4^{49}\)
\(\Rightarrow C+1=\dfrac{4^{49+1}-1}{4-1}=\dfrac{4^{50}-1}{3}\)
\(\Rightarrow C=\dfrac{4^{50}-1}{3}-1=\dfrac{4^{50}-4}{3}=\dfrac{4\left(4^{49}-1\right)}{3}\)
Tương tự câu d,e,f bạn tự làm nhé
a: \(x-43=\left(35-x\right)-48\)
=>\(x-43=35-x-48\)
=>\(x-43=-x-13\)
=>\(x+x=-13+43\)
=>2x=30
=>x=30/2=15
b: \(305-x+14=48+\left(x-23\right)\)
=>\(319-x=48+x-23=25+x\)
=>\(x+25=319-x\)
=>\(x+x=319-25\)
=>\(2x=294\)
=>\(x=\dfrac{294}{2}=147\)
c: \(-\left(-x-6+85\right)=\left(x+51\right)-54\)
=>\(-\left(-x+79\right)=x+51-54\)
=>x-79=x-3
=>-79=-3(vô lý)
=>\(x\in\varnothing\)
d: \(-\left(35-x\right)-\left(37-x\right)=33-x\)
=>\(-35+x-37+x=33-x\)
=>2x-72=-x+33
=>\(2x+x=33+72\)
=>3x=105
=>\(x=\dfrac{105}{3}=35\)
\(\left(3x-4x\right)\cdot6=3^3\cdot3^3+2^3+3^2-12^2\)
\(\Leftrightarrow18x-288=3^6+2^3+3^2-12^2\)
\(\Leftrightarrow18x-288=729+8+\left(3-12\right)\cdot\left(3+12\right)\)
\(\Leftrightarrow18x-288=729+8+\left(-9\right)\cdot15\)
\(\Leftrightarrow18x-288=729+8-135\)
\(\Leftrightarrow18x-288=602\)
\(\Leftrightarrow18x=602+288\)
\(\Leftrightarrow18x=890\)
\(\Rightarrow x=\dfrac{445}{9}\)
Vậy \(x=\dfrac{445}{9}\)
(3x-48).6=33.33+23+32-122
(3x-48).6=36+8+9-144
(3x-48).6=729+-127
(3x-48).6= 602
3x-48=\(\dfrac{602}{6}\)
3x=\(\dfrac{602}{6}\)+48
3x=\(\dfrac{445}{3}\Leftrightarrow x=\dfrac{445}{9}\)