Tìm số nguyên \(x\), biết :
\(11-\left(15+11\right)=x-\left(25-9\right)\)
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8 tháng 12 2018
\(11-\left(15-49\right)=-x+\left(9-25\right)\)
\(11-15+49=-x+9-25\)
\(x=9-25-11+15-49\)
\(x=-61\)
Vậy \(x=-61\)
8 tháng 12 2018
\(x-+\left(-479-479\right)=-\left(26-74\right)\)
\(x+479+479=-26+74\)
\(x=74-26-479-479\)
\(x=-910\)
Vậy \(x=-910\)
Y
7 tháng 7 2023
\(9,\left(2x-5\right)^2-\left(x+1\right)^2=0\\ \Leftrightarrow\left(2x-5-x-1\right)\left(2x-5+x+1\right)=0\)
\(\Leftrightarrow\left(x-6\right)\left(3x-4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-6=0\\3x-4=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=6\\x=\dfrac{4}{3}\end{matrix}\right.\)
Vậy \(S=\left\{6;\dfrac{4}{3}\right\}\)
\(10,\left(x+3\right)^2-x^2=45\)
\(\Leftrightarrow x^2+6x+9-x^2-45=0\\ \Leftrightarrow6x=36\\ \Leftrightarrow x=6\)
Vậy \(S=\left\{6\right\}\)
\(11,\left(5x-4\right)^2-49x^2=0\\ \Leftrightarrow\left(5x-4\right)^2-\left(7x\right)^2=0\\ \Leftrightarrow\left(5x-4-7x\right)\left(5x-4+7x\right)=0\\ \Leftrightarrow\left(-2x-4\right)\left(12x-4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}-2x-4=0\\12x-4=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=\dfrac{1}{3}\end{matrix}\right.\)
Vậy \(S=\left\{-2;\dfrac{1}{3}\right\}\)
\(12,16\left(x-1\right)^2-25=0\\ \Leftrightarrow4^2\left(x-1\right)^2-5^2=0\\ \Leftrightarrow\left[4\left(x-1\right)\right]^2-5^2=0\\ \Leftrightarrow\left(4x-4\right)^2-5^2=0\\ \Leftrightarrow\left(4x-4-5\right)\left(4x-4+5\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}4x-9=0\\4x+1=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{9}{4}\\x=-\dfrac{1}{4}\end{matrix}\right.\)
Vậy \(S=\left\{-\dfrac{1}{4};\dfrac{9}{4}\right\}\)
NN
Nguyễn Ngọc Anh Minh
CTVHS
VIP
3 tháng 8 2023
\(p=\left[\left(x+5\right).\left(x+11\right)\right].\left[\left(x+7\right).\left(x+9\right)\right]+16=\)
\(=\left(x^2+16x+55\right)\left(x^2+16x+63\right)+16=\)
\(=\left(x^2+16x\right)^2+118.\left(x^2+16x\right)+3481=\)
\(=\left(x^2+16x\right)^2+2.\left(x^2+16x\right).59+59^2=\)
\(=\left[\left(x^2+16x\right)+59\right]^2\) là một số chính phương
13 tháng 11 2023
Bài 1:
\(A=26^2-24^2=\left(26-24\right)\left(26+24\right)=2\cdot50=100\)
\(B=27^2-25^2=\left(27-25\right)\left(27+25\right)=2\cdot52=104\)
=>A<B
Bài 2:
\(4\left(x+1\right)^2+\left(2x-1\right)^2-8\left(x-1\right)\left(x+1\right)=11\)
=>\(4\left(x^2+2x+1\right)+4x^2-4x+1-8\left(x^2-1\right)=11\)
=>\(4x^2+8x+4+4x^2-4x+1-8x^2+8=11\)
=>4x+13=11
=>4x=-2
=>\(x=-\dfrac{1}{2}\)
15 tháng 12 2023
\(\left(x-2\right)^3-\left(x+5\right)\left(x^2-5x+25\right)+6x^2=11\)
=>\(x^3-6x^2+12x-8-\left(x^3+125\right)+6x^2=11\)
=>\(x^3+12x-8-x^3-125=11\)
=>12x-133=11
=>12x=144
=>\(x=\dfrac{144}{12}=12\)
27 tháng 3 2018
( 7x - 11 ) 3 = ( -3 )2 .15 + 208
( 7x - 11 ) 3 = 9 .15 + 208
( 7x - 11 ) 3 = 135 + 208
( 7x - 11 ) 3 = 343
( 7x - 11 ) 3 = 73
=> 7x - 11 = 7
=> 7x = 7 + 11 = 18
=> x = 18/7
27 tháng 3 2018
\(\left(7x-11\right)^3=\left(-3\right)^2.15+208\)
\(\Leftrightarrow\)\(\left(7x-11\right)^3=9.15+208\)
\(\Leftrightarrow\)\(\left(7x-11\right)^3=135+208\)
\(\Leftrightarrow\)\(\left(7x-11\right)^3=343\)
\(\Leftrightarrow\)\(\left(7x-11\right)^3=7^3\)
\(\Leftrightarrow\)\(7x-11=7\)
\(\Leftrightarrow\)\(7x=18\)
\(\Leftrightarrow\)\(x=\frac{18}{7}\)
Vậy \(x=\frac{18}{7}\)
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11-(15+11)=x-(25-9)
11-26 =x-(25-9)
-15 =x-(25-9)
-15 =x-16
16+(-15) =x
1 =x
\(11-\left(15+11\right)=x-\left(25-9\right)\)
\(\Leftrightarrow11-26=x-16\)
\(\Leftrightarrow-15=x-16\)
\(\Leftrightarrow x=16-15\)
\(\Leftrightarrow x=1\)