Tìm các số nguyên x,y biết
7/x = y/27 = -45/54
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7/x=y/27=-42/54=-7/9
7/x=-7/9 nên x=-9
y/27=-7/9=-21/27 nên y=-21
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`A)2/3=x/60`
`=>40/60=x/60`
`=>x=40`
`B)-1/2=y/18`
`=>-9/18=y/18`
`=>y=-9`
`C)3/x=y/35=-36/84`
Mà `-36/84=(-3 xx 12)/(7 xx 12)=-3/7`
`=>3/x=-3/7`
`=>x=-7`
`y/35=-3/7=-15/35`
`=>y=-15`
`D)7/x=y/27=-42/54`
Mà `-42/54=(-7 xx 6)/(9 xx 6)=-7/9`
`=>7/x=-7/9`
`=>x=-9`
`y/27=-7/9=-21/27`
`=>y=-21`
\(\frac{7}{x}=\frac{y}{27}=\frac{-42}{54}\)
+) => \(\frac{y\cdot2}{27\cdot2}=\frac{-42}{54}\)
=> \(y\cdot2=-42\)
\(\Rightarrow y=-21\)
+) \(\frac{7}{x}=\frac{-21}{27}\)
=> \(\frac{7\cdot\left(-3\right)}{x\cdot\left(-3\right)}=\frac{-21}{27}\)
=> \(x\cdot\left(-3\right)=27\)
=> \(x=-9\)
* Lớp 6 chưa học đến tỉ lệ thức nên đây là cách đơn giản nhất r *
\(\frac{y}{27}\)=\(\frac{-42}{54}\)=>\(\frac{2y}{54}\)=\(\frac{-42}{54}\)=>2y= -42 y= \(\frac{-42}{2}\)= -21 \(\frac{7}{x}\)=\(\frac{-21}{27}\)=> -21x=7*27=189 x=\(\frac{189}{-21}\)= -9 Vậy x= -9, y= -21
a.x/3=7/y
suy ra 3.7=x.y
suy ra 21=x.y
mà 21=-3.-7=3.7=1.21=-1.-21
vậy (x;y)E{(-3;-7);(-7;-3);(7;3);(3;7);(1;21);(21;1);(-1;-21);(-21;-1)}
b.x-3/27=7/21
suy ra (x-3).21=27.7
suy ra (x-3).21=189
suy ra(x-3)=189:21=9
suy ra x=9+3=12
vậy x =12
k cho mình như
a, \(\frac{42}{54}\)= \(\frac{7}{x}\)=> 42x=7.54 => x=\(\frac{7.54}{42}\)= 9. Vậy x=9 b, \(\frac{x}{15}\)= \(\frac{-2}{3}\)=> 3x= (-2).15 => x= \(\frac{\left(-2\right).15}{3}\)= -10. Vậy x=-10 c, \(\frac{x}{27}\)= \(\frac{-5}{9}\)=> 9x=(-5).27 => x\(\frac{\left(-5\right).27}{9}\)= -15 Thay x = -15 vào biểu thức ta có: \(\frac{-15}{27}\)= \(\frac{-45}{y}\)=> -15y= (-45).27 => y= \(\frac{\left(-45\right).27}{-15}\)=81 Vậy x=-15, y = -81 .KÍCH NKA PẠN
7/x=y/27=-5/6
=>x=-42/5; y=-45/2