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19 tháng 12 2016

G G1 G2 Nguồn sáng (1) (3) (2) (4) - Vì tam giác đều mỗi góc của tam giác đều = 60 độ, nên:

=> góc SIN = SNI = 60 độ.

- Vì góc tới bằng góc phản xạ nên:

=> góc (1) = góc (3) = \(\frac{60}{2}=30\)

- Vì góc hợp bởi tia phản xạ và mặt phẳng gương bằng: góc hợp bởi pháp tuyến và mặt phẳng gương (90o) - góc phản xạ. Ta có:

=> góc (2) = góc (3) = 90o- 30o = 60o

- Vì tổng 3 góc của một tam giác bằng 180 độ, nên:

góc IJN = 180o - ( 60o + 60o ) = 60o

  • => Vậy góc hợp bởi giữa hai gương bằng 60o

-- Mình chỉ biết cách làm thôi chứ không biết cách trình bày. Cánh trình bày của mình chưa đúng lắm, mong bạn thông cảm.--

20 tháng 12 2016

Quên vẽ dấu mũi tên của tia phản xạ và tia tới rồi, bạn tự vẽ nha

1 tháng 10 2021

máy tính hay tv đấy 

1 tháng 10 2021

Máy tính như hacker í

27 tháng 12 2018

24 - 16(x - 1/2) = 23

=> 16(x - 1/2) = 24 - 23

=> 16(x - 1/2) = 1

=> x - 1/2 = 1/16

=> x = 1/16 + 1/2

=> x = 9/16

27 tháng 12 2018

\(24-16(x-\frac{1}{2})=23\)

\(16(x-\frac{1}{2})=24-23\)

\(16(x-\frac{1}{2})=1\)

\(x-\frac{1}{2}=\frac{1}{16}\)

\(x=\frac{1}{16}+\frac{1}{2}\)

\(x=\frac{9}{16}\)

Vậy số thực x cần tìm là \(\frac{9}{16}\)

Chúc bạn hok tốt ~

9 tháng 1 2022

I am sorry, I can’t help you.” Peter said to me.

A.   Peter promised to help me.                          B. Peter refused to help me.                   

C. Peter asked me for help.                               D. I couldn’t help Peter.

To make Peter surprised, we _______ and when he comes, we ________.

A. are going to hide / will jump out and shout             B. will hide / are jumping out and shouting

C. are hiding / are going to jump out and shout          D. are hiding / are jumping out and shouting

26 tháng 12 2021

It’s kind of you to help me wash the dishes after the party.

A. Washing the dishes is kind of you to help me.

B. You are so kind when you help me wash the dishes.

C. To help me wash the dishes after the party you are kind.

D. It’s your kind to help me with the dishes after the party.

25 tháng 12 2016

chịu

 

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26 tháng 9 2023

So sánh:\(10^{10}\) và \(48.50^5\)

Ta có:

\(10^{10}=10^{2.5}=\left(10^2\right)^5=100^5=\left(2.50\right)^5=2^5.50^5=32.50^5\)

Vì \(32.50^5< 48.50^5\)

\(\Rightarrow10^{10}< 48.50^5\)

10 tháng 5 2017

Our Greener Would will able to have a clean air. It has many green trees around the Earth. Air around the world will not be able to pollute the air. People will not be affected by breathing. So, I love it so much.

Hơi ngắn

10 tháng 5 2017

Our green world will be able to have a clean air. It has many green trees around the Earth. Air around the world will not be able to pollute the air. People will not be affected by breathing. So, I love it so much.

18 tháng 9 2015

Cần gì , giúp được giúp cho

3 tháng 11 2021

bạn cần giúp gì,mình giúp cho nè 

3:

a: 5^n luôn có chữ số tận cùng là 5 với mọi n là số tự nhiên

=>5^100 có chữ số tận cùng là 5

b: \(2^{4k}\) có chữ số tận cùng là 6 với mọi k là số tự nhiên

mà 100=4*25

nên 2^100 có chữ số tận cùng là 6

c: 2023 chia 2 dư 1

mà \(9^{2k+1}\) luôn có chữ số tận cùng là 9

nên \(9^{2023}\) có chữ số tận cùng là 9

d: 2023 chia 4 dư 3

\(7^{4k+3}\left(k\in N\right)\) luôn có chữ số tận cùng là 3

Do đó: \(7^{2023}\) có chữ số tận cùng là 3

15 tháng 8 2023

Quy luật: 

+) các số có c/s tận cg là 0,1,5,6 nâng lên lũy thừa bậc nào (≠0) thì c/s tận cg vẫn là nó.

+) các số có tận cg là 2,4,8 nâng lên lt bậc 4n(n≠0) thì đều có c.s tận cg là 6.

+)các số có c/s tận cg là 3,7,9 nâng lên lt bậc 4n(n≠0)  thì đều có c/s tận cg là 1.

+) số có tận cg là 3 khi nâng lên lũy thừa bậc 4n+3 sẽ có tận cùng là 7

+) số có tận cg là 7 khi nâng lên lũy thừa bậc 4n+3 sẽ có tận cùng là 3

+) số có tận cg là 2 khi nâng lên lũy thừa bậc 4n+3 sẽ có tận cùng là 8

+) số có tận cg là 8 khi nâng lên lũy thừa bậc 4n+3 sẽ có tận cùng là 2

+) số có c/s tận cg là 0,1,4,5,6,9 khi nâng lên lũy thừa bậc 4n+3 thì c/s tận cg là chính nó

 

Bài 3: áp dụng quy luật bên trên

\(a.5^{100}=\overline{..5}\)     

\(b.2^{100}=2^{4.25}=\overline{..6}\)

\(c.9^{2023}=\overline{..9}\)  

\(d.7^{2023}=7^{4.505+3}=\overline{...3}\)

Bài 4:

\(A=17^{2008}-11^{2008}-3^{2008}\)

\(=\left(\overline{...7}\right)^{4.502}-\left(\overline{..1}\right)^{2008}-\left(\overline{..3}\right)^{4.502}\)

\(=\overline{..1}-\overline{...1}-\overline{...1}\)

\(=\overline{..9}\)

Bài 5:

\(M=17^{25}+24^4-13^{21}\)

\(=\left(\overline{..7}\right)^{4.6}.\left(\overline{..7}\right)+\left(\overline{..4}\right)^{4.1}-\left(\overline{..3}\right)^{4.5}.\left(\overline{..3}\right)\)

\(\overline{..1}.\overline{..7}+\overline{..6}-\overline{..1}.\overline{..3}\)

\(=\overline{...7}+\overline{..6}-\overline{..3}\)

\(=\overline{...0}\)

\(=>M⋮10\)